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Siemens Technical Questions 2014

Posted on :04-02-2016

Q1. Which of following operator cant be overloaded?

a) ==
b) ++
c) ?!
d) <=

Q2. For the following C program

#include
main()
{printf("Hello World");}

The program prints Hello World without changing main() ,the output should be initialisation Hello World Destruct The changes should be

a) IOstream operator
b)(iostream os, char*s)
c) os<
d) none of the above

Q3. CDPATH shell variable is in(c-shell)

Q4. The term stickily bit is related to

a) Kernel
b) Undeletable file
c) Both (a) and (b)
d) None

Q5. Semaphore variable is different from ordinary variable by

Q6. For the following C program:

swap(int x,y)
int temp;
temp=x;
x=y;
y=temp;}
main()
{int x=2;y=3;
swap(x,y);}

After calling swap, what are the values x & y?

Q7. Static variable will be visible in

a) Function. in which they are defined
b) Module in which they are defined
c) All the program
d) None

Q8. Unix system is

a) Multi processing
b) Multi processing, multiuser
c) Multi processing, multiuser, multitasking
d) Multiuser, multitasking

Q9. X.25 protocol encapsulates the following layers

a) Network
b) Datalink
c) Physical
d) All of the above
e) None of the above

Q10. TCP/IP can work on

a) Ethernet
b) Token ring
c) (a) & (b)
d) None

Q11. A node has the IP address 138.50.10.7 and  138.50.10.9. But it is transmitting data from node 1 to node 2o nly. The reason may be

a) A node cannot have more than one address
b) class A should have second octet different
c) class B should have second octet different
d) All of the above

Q12. The OSI layer from bottom to top

Q13. For an application which exceeds 64 k the memory model should be

a) Medium
b) Huge
c) Large
d) None

Q14. The condition required for dead lock in unix system is

Q15. Set-user-id is related to (in unix)

Q16. Bourne shell has

Q17. Which of the following is not true about C++

a) Code removeably
b) Encapsulation of data and code
c) Program easy maintenance
d) Program runs faster

Q18. For the following C program

struct base {int a,b;
base();
int virtual function1();}
struct derv1:base
{int b,c,d;
derv1()
int virtual function1();}
struct derv2 : base
{int a,e; } base::base() {a=2;b=3;
derv1::derv1()
{b=5; c=10;d=11;}
base::function1()
{return(100); }
derv1::function1()
{ return(200); }
main()
base ba;
derv1 d1,d2;
printf("%d %d",d1.a,d1.b)

Output of the program is:

a) a=2;b=3;
b) a=3; b=2;
c) a=5; b=10;
d) none

Q19. For the above program answer the following qs

main()
base da;
derv1 d1;
derv2 d2;
printf("%d %d %d",da.function1(),d1.function1(),d2.function1());

Output is:

a) 100,200,200;
b) 200,100,200;
c) 200,200,100;
d) None of the above program

Q20. 

struct { int x; int y; }abc;

x cannot be accessed by the following

1) abc-->x;
2) abc[0]-->x;
3) abc.x;
4)( abc)-->x;

a )1, 2, 3
b) 2 & 3
c) 1 & 2
d) 1, 3, 4

Q21. Automatic variables are destroyed after function. ends because

a) Stored in swap
b) Stored in stack and popped out after function. returns
c) Stored in data area
d) Stored in disk

Q22. Relation between x-application and x-server (x-win)
 
Q23. What is UIL? (user interface language)


  
   






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