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Quest-Global placement paper set1
Posted on :01-04-2016
Q1. A three digit number consists of 9,5 and one more number . When these digits are reversed and then subtracted from the original number the answer yielded will be consisting of the same digits arranged yet in a different order. What is the other digit?
Solution:Let the digit unknown be n.The given number is then 900+50+n=950+n.When reversed the new number is 100n+50+9=59+100n.Subtracting these two numbers we get 891-99n.The digit can be arranged in 3 ways or 6 ways.We have already investigated 2 of these ways.We can now try one of the remaining 4 ways. One of these is n 95100n+90+5=891-99nor 199n =796so, n=4the unknown digit is 4.
Q2. A farmer built a fence around his 17 cows, in a square shaped region. He used 27 fence poles on each side of the square. How many poles did he need altogether?
ANS: 104 poles
Here 25 poles Must be there on each side .And around four corners 4 poles will be present.4*25+4=100+4=104 poles.
Q3. On the first test of the semester, kiran scored a 60. On the last test of the semester, kiran scored 75% By what percent did kirans score improve?
Solution:In first test kiran got 60In last test he got 75.% increase in test ( 60(x+100))/100=750.6X+60=750.6X=15X=15/0.6=25%
Q4. A group consists of equal number of men and women. Of them 10% of men and 45% of women are unemployed. If a person is randomly selected from the group. Find the probability for the selected person to be an employee.
Solution:Assume men=100,women=100 then employed men & women r (100-10)+(100-45)=145So probability for the selected person to be an employee=145/200=29/40
Q5. Randys chain of used car dealership sold 16,400 cars in 1998. If the chain sold 15,744 cars in 1999, by what percent did the number of cars sold decrease?
Solution:Let percentage of decrease is x , then16400(100-x)/100=1574416400-15744=164xx=656/164=4%
Q6. A radio when sold at a certain price gives a gain of 20%. What will be the gain percent, if sold for thrice the price?
A) 260%B) 150%C) 100%D) 50%E) None of these
Solution:Let x be original cost of the radio.The solding price = (100+20)x=120xIf , it is sold for thrice the price ,then 3*120x=360xSo, gain percent is (360-100)=260%.
Q7. If the Arithmetic mean is 34 and geometric mean is 16 then what is greates number in that series of numbers?
Solution:Let two numbers be x, y;Arithmetic mean=34=>( x+y)/2=34x+y=68geometric mean=16=>(xy)pow 1/2=16xy=16*16=256By trail and error 16*16=64*4And 64+4/2=34So the greatest number int hat series is 64.
Q8. The diameter of the driving wheel of a bus is 140cm. How many revolutions per minute must the wheel make in order to keep a speed of 66 kmph?
Solution:Distance to be covered in 1 min=(66*1000)/60 m=1100mCircumference of the wheel =(2*22/7*0.70)m=4.4m.So, Number of revolutions per min=1100/4.4=250.
Q9. The boys and girls in a college are in the ratio 3:2. If 20% of the boys and 25% of the girls are adults, the percentage of students who are not adults is:?
Solution:Suppose boys = 3x and girls = 2xNot adults = (80*3x/100) + (75*2x/100) = 39x/10Required percentage = (39x/10)*(1/5x)*100 = 78%
Q10. Vivek travelled 1200km by air which formed 2/5 of his trip. One third of the whole trip , he travelled by car and the rest of the journey he performed by train. The distance travelled by train was?
Solution:Let the total trip be x km.Then 2x/5=1200x=1200*5/2=3000kmDistance travelled by car =1/3*3000=1000kmJourney by train =[3000-(1200+1000)]=800km.
Q11. In a college ,1/5 th of the girls and 1/8 th of the boys took part in a social camp. What of the total number of students in the college took part in the camp?
Solution:Out of 5 girls 1 took part in the campout of 8 boys 1 took part in the campso, out of 13 students 2 took part in the camp.So, 2/13of the total strength took part in the camp.
Q12. On sports day, if 30 children were made to stand in a column,16 columns could be formed. If 24 children were made to stand in a column , how many columns could be formed?
Solution:Total number of children=30*16=480Number of columns of 24 children each =480/24=20.
Q13. Two trains 200mts and 150mts are running on the parallel rails at this rate of 40km/hr and 45km/hr. In how much time will they cross each other if they are running in the same direction.
Solution:Relative speed=45-40=5km/hr=25/18 mt/secTotal distance covered =sum of lengths of trains =350mts.So, time taken =350*18/25=252sec.
Q14. 5/9 part of the population in a village are males. If 30% of the males are married, the percentage of unmarried females in the total population is:
Solution:Let the population =x Males=(5/9)xMarried males = 30% of (5/9)x = x/6Married females = x/6Total females = (x-(5/9)x)=4x/9Unmarried females = (4x/9 – x/6) = 5x/18Required percentage = (5x/18 * 1/x * 100) = (250/9)%
Q15. From height of 8 mts a ball fell down and each time it bounces half the distance back. What will be the distance travelled
Solution:8+4+4+2+2+1+1+0.5+0.5+ and etc .. =24
Q16. First day of 1999 is Sunday what day is the last day
Q17. Increase area of a square by 69% by what percent should the side be increased
Solution:Area of square=x2Then area of increase=100+69=169square root of 169 i.e 13 .
Q18. Ten years ago, chandrawathis mother was four times older than her daughter. After 10years, the mother will be twice older than daughter. The present age of Chandrawathi is:
ANS: 20 years
Solution:Let Chandrawathis age 10 years ago be x years.Her mothers age 10 years ago = 4x(4x+10)+10=2(x+10+10)x=10Present age of Chandrawathi = (x+10) = 20years
Q19. Finding the wrong term in the given series
7, 28, 63, 124, 215, 342, 511
Solution:Clearly, the correct sequence is2^3 – 1, 3^3 – 1, 4^3 – 1, 5^3 – , ……….Therefore, 28 is wrong and should be replaced by (3^3 – 1) i.e, 26.
Q20. If a man walks at the rate of 5kmph, he misses a train by only 7min. However if he walks at the rate of 6 kmph he reaches the station 5 minutes before the arrival of the train. Find the distance covered by him to reach the station.
Solution:Let the required distance be x km.
Q21. Difference in the times taken at two speeds=12mins=1/5 hr.
Therefore x/5-x/6=1/5 or 6x-5x=6 or x=6km. Hence ,the required distance is 6 km