## Quest-Global Placement Papers

Quest-Global placement paper set 2

Quest-Global placement paper set1

Quest-Global Technical Questions

Quest-Global Latest Technical Questions

Quest-Global Technical Mechanical Questions

## Placement Papers for All Companies

3i infotech

Abacus Infotech

Abatix

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Agilysys

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AMDL

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AMI

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ANZ

Apple

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Apps Associates

Aricent

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Ashok Leyland Ltd

Asian Paints

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AT & T

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Atos Origin

AXA Technology Services

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Bain

Bajaj

Bayer

Bharti Airtel Ltd

Bhawan Cybertek

Birlasoft

Blue Star Infotech

BMC

BOB

Brakes India

C-DOT

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Canarys

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Caterpillar

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Changepond Technologies

Cimtrix Systems

Cisco system

Citicorp Overseas Software Ltd

ClinTech

CMC Limited

CMS

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Consagous Technologies

Convergys

CORDYS

CRISIL

Crompton Greaves

CSC

CSFB

CtrlS Datacenters Ltd

Cummins

Cyient

Daffodil

Daimler

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Directi

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Eicher

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Emphasis

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ESKO

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Facebook

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Fujitsu

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GE

Genpact India

Geodesic

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GlobalEdge

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Harita - TVS

HCL

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Headstrong

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Intel

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Jindal Steel and Power Limited

KPIT

L & T

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LG Soft

Linde India Ltd

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LnT-ECC

Lucas - TVS

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Mahindra Ltd

Maruti

Matrix

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McAfee

Microland

Microsoft

Mindtree

Miraclesoft

MKCL

Motorola

Mu-Sigma

Nagarro

NASSCOM

NCR Corporation

Ness Technologies

Neudesic

NIIT Technologies

Novell

Nvidia

Oracle

Persistent

Philips

Planetasia

Polaris

Poornam Info Vision

PSI Data Systems Limited

Quest-Global

Quinnox

R Systems

Redpine

Reliance Energy

Robert Bosch

RS Software

Samsung

SAP labs India

Sapient

Sasken Communications

Schneider India

Serco

Siemens

Sierra Atlantic

SkyTECH

Soliton

Sonata Software

Sony India

SQL Star

Steria

Subex Limited

Sutherland Global Services

Syntel

Talisma

Tata motors

Tata technologies

Tata-ELXSI

TCE

TCS

Tech Mahindra

Temenos

Tesco

Texas Instruments

Thermax

ThoughtWorks

Torry Harris

Triad

Trianz

Trilogy

TVS Motor

Unisys

UnitedHealth Group

UST Global

UTC Aerospace System

Valuelabs

Vedanta

Verifone

Verizon

Virtusa

Vision Infotech

Vizual

VMware

Wipro

Yahoo

YASH Technologies

Zenith

Zensar Technologies

ZTE

# Quest-Global Sample paper

Posted on :01-04-2016

**Q1. The ratio of marks obtained by vinod and Basu is 6:5. If the combined average of their percentage is 68.75 and their sum of the marks is 275, find the total marks for which exam was conducted.**

Solution:Let Vinod marks be 6x and Basus is 5x. Therefore, the sum of the marks = 6x + 5x = 11x.But the sum of the marks is given as 275 = 11x. We get x = 25 therefore, vinod marks is 6x = 150 and Basu marks = 5x = 125.Therefore, the combined average of their marks = (150 + 125) / 2 = 137.5.If the total mark of the exam is 100 then their combined average of their percentage is 68.75Therefore, if their combined average of their percentage is 137.5 then the total marks would be (137.5 / 68.75)*100 = 200.

**Q2) If the cost price of 20 articles is equal to the selling price of 16 articles, What is the percentage of profit or loss that the merchant makes?**

Solution:Let Cost price of 1 article be Re.1.Therefore, Cost price of 20 articles = Rs. 20.Selling price of 16 articles = Rs. 20Therefore, Selling price of 20 articles = (20/16) * 20 = 25Profit = Selling price – Cost price= 25 – 20 = 5Percentage of profit = Profit / Cost price * 100.= 5 / 20 * 100 = 25% Profit

**Q3. A candidate who gets 20% marks fails by 10 marks but another candidate who gets 42% marks gets 12% more than the passing marks. Find the maximum marks.**

Solution:Let the maximum marks be x.From the given statement pass percentage is 42% – 12% = 30%By hypothesis, 30% of x – 20% of x = 10 (marks)i.e., 10% of x = 10Therefore, x = 100 marks.

**Q4. When processing flower-nectar into honeybees extract, a considerable amount of water gets reduced. How much flower-nectar must be processed to yield 1kg of honey, if nectar contains 50% water, and the honey obtained from this nectar contains 15% water?**

Solution:

Flower-nectar contains 50% of non-water part.In honey this non-water part constitutes 85% (100-15).Therefore 0.5 X Amount of flower-nectar = 0.85 X Amount of honey = 0.85 X 1 kgTherefore amount of flower-nectar needed = (0.85/0.5) * 1kg = 1.7 kg.

**Q5. A man can row 50 km upstream and 72 km downstream in 9 hours. He can also row 70 km upstream and 90 km downstream in 12 hours. Find the rate of current.**

Solution:

Let x and y be the upstream and downstream speed respectively.Hence 50/x + 72/y = 9 and 70/x + 90/y = 12Solving for x and y we get x = 10 km/hr and y = 18 km/hrWe know that Speed of the stream = 1/2 * (downstream speed – upstream speed) = 1/2 (18 – 10) = 4 km/hr.

**Q6. How long will it take for a sum of money to grow from Rs.1250 to Rs.10,000, if it is invested at 12.5% p.a simple interest?**

Solution:Simple interest is given by the formula SI = (pnr/100), where p is the principal, n is the number of years for which it is invested, r is the rate of interest per annumIn this case, Rs. 1250 has become Rs.10,000.Therefore, the interest earned = 10,000 – 1250 = 8750.8750 = [(1250*n*12.5)/100]=> n = 700 / 12.5 = 56 years.

**Q7) The time in a clock is 20 minute past 2. Find the angle between the hands of the clock.**

Solution:

Time is 2:20. Position of the hands: Hour hand at 2 (nearly).Minute hand at 4Angle between 2 and 4 is 60 degrees [(360/12) * (4-2)]Angle made by the hour hand in 20 minutes is 10 degrees, since it turns through ½ degrees in a minute.Therefore, angle between the hands is 60 degrees – 10 degrees = 50 degrees

**Q8. A man buys an article for Rs. 27.50 and sells it for Rs. 28.60. Find his gain percent.**

Solution:C.P. = Rs.27.50, S.P. = Rs. 28.60.Therefore Gain = Rs. (28.60 – 27.50) = Rs.1.10.Therefore Gain % = (1.10*100/27.50) % = 4%.9)Find S.P., when:(i) C.P. = Rs. 56.25, gain = 20%.(ii) C.P. = Rs. 80.40, loss = 15%.Solution:(i) S.P. = 120% of Rs. 56.25 = Rs. (120*56.25/100) = Rs. 67.50.(ii) S.P. = 85% of Rs. 80.40 = Rs. (85*80.40/100) = Rs. 68.34.

**Q10. A scooterist covers a certain distance at 36 kmph. How many meters does he cover in 2 min?**

Solution:Speed = 36 kmph = 36 * 5/18 = 10mpsTherefore, Distance covered in 2 min = (10 * 2 * 60)m = 1200m

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