## Godrej Infotech Placement Papers

Godrej Infotech Technical Interview Questions 2013

Godrej Infotech Verbal Ability

Godrej Infotech Technical Questions

Godrej Infotech Reasoning Ability

Godrej Infotech Arithmetic Ability Questions

Godrej Infotech Aptitude Questions

Godrej Infotech - Model Test Paper

Godrej Placement Paper May 2013

Godrej Placement Paper December 2012, January 2015

Godrej Infotech Written Test Paper 2014

## Placement Papers for All Companies

3i infotech

Abacus Infotech

Abatix

Abaxis

ABB

ACC Limited

Accel Frontline

Accenture

Aditi Technologies

Adobe System

ADP

Agilysys

AgreeYa

AIG

AirNet

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Allfon

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Amazon

AMDL

Amdocs

AMI

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ANZ

Apple

Applied Materials

Apps Associates

Aricent

ASDC

Ashok Leyland Ltd

Asian Paints

Aspire System

AT & T

Atlas Copco

Atos Origin

AXA Technology Services

Axes Technology

Bain

Bajaj

Bayer

Bharti Airtel Ltd

Bhawan Cybertek

Birlasoft

Blue Star Infotech

BMC

BOB

Brakes India

C-DOT

CA Technologies

Cadence

Calsoft

Canarys

Capgemini

Caterpillar

Celstream

CGI Group

Changepond Technologies

Cimtrix Systems

Cisco system

Citicorp Overseas Software Ltd

ClinTech

CMC Limited

CMS

Cognizant

Compaq

Consagous Technologies

Convergys

CORDYS

CRISIL

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CSC

CSFB

CtrlS Datacenters Ltd

Cummins

Cyient

Daffodil

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Directi

DSRC

Eicher

ELGI

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EMC Corporation

Emphasis

Ericsson

Ernst & Young

ESKO

Essar

Facebook

Fanuc Corporation

Fidelity

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Flipkart

Freescale

Fujitsu

Gajshield

GE

Genpact India

Geodesic

Geometric Limited

GlobalEdge

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GMR Group

Godrej Infotech

Google

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Harita - TVS

HCL

HCL Technologies

Headstrong

Healthasyst

HEC Ltd

Hexaware

HFCL

Holool

Honeywell

HP

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Huawei

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IBM

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Ikanos

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IndiaBulls Power Limited

Inductis-EXL

Industrial Alliance

Infineon

Infogain

Infosys

Intec

Integra

Intel

Intergraph

ITC Infotech

Jindal Steel and Power Limited

KPIT

L & T

L & T Infotech

LG Soft

Linde India Ltd

LnT Emsys

LnT-ECC

Lucas - TVS

Mahindra Engineering Services Ltd

Mahindra Ltd

Maruti

Matrix

Maveric Systems

McAfee

Microland

Microsoft

Mindtree

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MKCL

Motorola

Mu-Sigma

Nagarro

NASSCOM

NCR Corporation

Ness Technologies

Neudesic

NIIT Technologies

Novell

Nvidia

Oracle

Persistent

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Planetasia

Polaris

Poornam Info Vision

PSI Data Systems Limited

Quest-Global

Quinnox

R Systems

Redpine

Reliance Energy

Robert Bosch

RS Software

Samsung

SAP labs India

Sapient

Sasken Communications

Schneider India

Serco

Siemens

Sierra Atlantic

SkyTECH

Soliton

Sonata Software

Sony India

SQL Star

Steria

Subex Limited

Sutherland Global Services

Syntel

Talisma

Tata motors

Tata technologies

Tata-ELXSI

TCE

TCS

Tech Mahindra

Temenos

Tesco

Texas Instruments

Thermax

ThoughtWorks

Torry Harris

Triad

Trianz

Trilogy

TVS Motor

Unisys

UnitedHealth Group

UST Global

UTC Aerospace System

Valuelabs

Vedanta

Verifone

Verizon

Virtusa

Vision Infotech

Vizual

VMware

Wipro

Yahoo

YASH Technologies

Zenith

Zensar Technologies

ZTE

# Godrej Infotech Aptitude Paper 2011

Posted on :01-02-2016

**Q1.**

**Lucia is a wonderful grandmother. Her age is between 50 and 70. Each of her sons have as many sons as they have brothers. Their combined number gives Lucia**

a) 55b) 64c) 73

__ANS:__64**Q2. Complete the series:5, 20, 24, 6, 2, 8, ?**

a) 32b) 12c) 16d) 3

__ANS:__**12**

**Q3. A 1 k.m. long wire is held by n poles. If one pole is removed, the length of the gap becomes 12/3m. What is the number of poles initially?**

a) n=196b) n=200c) n=251

__ANS:__**251**

**Q4. A software engineer returns from America. As he is fat he decided to have evening walk.....he started at 3pm. he walks along the road at 4km/hr for some time then he climbs a upward slope area at 3km/hr then downwards at the rate of 6km/hr. then back to the home through the road at 4km/hr. what is the distance he covered in one way if he reaches back home at 9pm.**

a) 8 Kmb) 6 Kmc) 3 Kmd) 9 Km

__ANS:__**6**

**Q5. In a race Andrew beats Jim. Jack is not the last. Dennis loses to both Jack and Lucia.Jim beats Jack. Who won the race?**

__ANS:__

**Andrew**

Explanation:The possible positions in the race are,Andrew AndrewJim JimJack LuciaLucia JackDennis DennisIn either caseAndrew is the winner.

**Q6.**

**Find the digits X,Y,Z**

**X X X X**

**Y Y Y Y +**

**Z Z Z Z**

**-----------------**

**Y X X X Z**

**-----------------**

__ANS:__**X Y Z**

**9 1 8**

Explanation:x+y+z = z ==> x+y = 10max value for y = 1hence x = 1also, (carry)1+x+y+z = x ==> 1+y+z = 10hence z=8X Y Z9 1 8

**Q7. A 1 k.m. long wire is held by n poles. If one pole is removed, the length of the gap becomes 12/3m. What is the number of poles initially?**

**251**

__ANS:__Explanation:Let the no. of poles originally = nAfter taking away one pole(n-1)*12/3 = 1000n = 251

**Q8. A + B + C +D = D + E + F + G = G + H + I =17.IF A = 4 WHAT ARE THE VALUES OF D AND G. EACH LETTER TAKEN ONLY ONE OF THE DIGIT FROM 1 TO 9.**

**A = 4 ,B = 2, C =6, D = 5, E = 3, F = 8, G = 1,H = 7, I = 9.**

__ANS:__**Q9. Can you find out what day of the week was January 12, 1979?**

__ANS:__**Friday.**

**Q10. Find x+2y**

(i). x+y=10

(ii). 2x+4y=20

__ANS:__**(ii)**

**Q11. Is angle BAC is a right angle**

(1) AB=2BC

(2) BC=1.5AC

**Q12. Is x greater than y**

(i) x=2k

(ii) k=2y

**Q13. Find the antonym for gaurish.**

a) Cheapb) Flashyc) Costly

__ANS:__**a) Cheap**

**Q14. Choose an appropriate antonym for the word deliberate.**

a) unintendedb) targetedc) focussed

__ANS:__**a) Unintended**

**Q15. Choose the antonym for Sorrow.**

a) Joyb) empathc) sympathy

__ANS:__**a) Joy**

**Q16. How many three digit numbers exist with the property that first digit of the 3-digit number is the product of last two digits?**

a) 19b) 17c) 12d) None of these

__ANS:__**b) 17.**

Explanation:First digit (100s place) of a 3-digit number cannot be zero, let us start with 1.If the first digit is 1, then the possible last two digits to get the product 1 is (1,1)Therefore, the number is 111.If the first digit is 2, then the possible last two digits to get the product 2 are (1,2) and (2,1).Therefore, the numbers are 212 and 221.Proceeding like this, we get,First digit Corresponding Total number3-digit numbers of numbers1 1112 212, 221 1+2 = 33 313, 331 3+2 = 54 414, 441 5+2 = 75 515, 551 7+2 = 96 616, 661 9+2 = 117 717, 771 11+2 = 138 818, 881 13+2 = 159 919, 991 15+2 = 17Thus, the required number of such 3-digit numbers is 17.

**Q17. How many 3-digit numbers satisfy the following property: Last digit of cube of the 3-digit number is 6 ?**

a) 10b) 100c) 90d) none of these

__ANS:__**a)10.**

Explanation:Note that,When three numbers are multiplied, the units digit of the product will be the last digit of the product of the last digit of each of the numbers.If last digit of a 3-digit number is 1 then last digit of cube of the number will be 1.Similarly, if last digit of the cube of a 3-digit number is 6 then last digit of its corresponding 3-digit number must be 6.Therefore, possible such three digits numbers are,106, 116, 126,....,196 -> 10 numbers.206, 216, 226,....,296 -> 10 numbers.Proceeding like this, we have,806, 816, 826,....,896 -> 10 numbers.906, 916, 926,....,996 -> 10 numbers.Thus, number of such numbers = 10+10+...+10 (9 terms) = 90.Hence the answer is 90.

**Q18. Consider a 4-digit number 5611 where last two digits are the sum of first two digits (5 + 6 = 11) and the unit digit is 1. How many such 4-digit numbers are exist?**

a) 9b) 10c) 51d) none of these

__ANS:__**a) 9**

Explanation:Since last digit of required 4-digit numbers is 1 then the possible last two digits of such numbers are 01,11, 21, 31,41,...,91.Note that, the maximum possibility of sum of two single digits is 18. (9 + 9 = 18).Therefore, 21, 31,...91 are not possible.Then only possible last two digits are 01 and 11.If last two digits is 01 then the number is 1001.And if the last two digit is 11 then the numbers are211, 8311, 7411, 6511,5611, 4711, 3811 and 2911.Hence, the total number of numbers is 1 + 8 = 9.

**Q19. A man lent out a certain amount of money to A on simple interest (S.I) at the rate 20% per annum for 2 years and the same amount of money at same rate to B on compound interest (C.I) which is compounded half yearly for 2 years. At the end of 2 years, he got Rs.1282 as the difference amount of S.I and C.I then what was the amount he lent out?**

a) Rs.20,000b) Rs.21,000c) Rs.22,000d) Rs.23,000

__ANS:__

**a) Rs.20,000**

Explanation:Let the required amount be Rs. P.S.I on P for 2 years at 20% per annum = P x R x T /100 = P x 2 x 20 / 100 = 2P/5.C.I on P for 2 years at 20% (compounded half yearly) = P {1 + (R/2)/100}2n= P {1 + (20/2)/100}2(2)= P {1 + 10/100}4= P {1 + 1/10}4= P {11/10}4Given that, the difference is Rs.1282.i.e., P{11/10}4= P {11/10}4= P{14641/10000 7/5} = Rs.1282= P{14641- 14000/10000 } = Rs.1282= P{641/10,000} = Rs.1282= P = Rs. 20,000.Hence, the answer is Rs.20,000.

**Q20. A man invested Rs. A in bank X which offers simple interest at 10% per annum and he invested Rs. B in**

**bank Y which offers compound interest at 6% per annum. If the total amount of interest (together bank X and Y) in 2 years was Rs.8017 and the total amount invested by him was Rs. 52500 then which of the following is equal to A?**

a) Rs.20,000b) Rs.21,500c) Rs.22,000d) Rs.23,500

__ANS:__**a) Rs.20,000.**

Explanation:We have to find Rs. ATotal amount invested by him is Rs. 52500i.e., Rs. (A + B) = Rs. 52,500Then B = Rs.52500 - AHe invests Rs. Rs.52500 - A in bank Y on C.I at 6% per annum for 2 years.Total S.I from bank X = PRT/100 = A x 10 x 2 / 100 = Rs. A / 5 .....(1)Total C.I from bank Y = P {1 + R/100}n= (52500 - A)[{1+ 6/100}2= (52500 - A)[{1+ 3/50}2= (52500 - A)[{53/50}2= (52500 - A)[{2809/2500} -1 ]= (52500 - A){309/2500} ......(2)Total interest amount of S.I and C.I = Rs.8017.From (1) and (2), A/5 + (52500 A)(309 / 2500) = 8017A/5 + 52500 x (309/2500) A (309/2500) = 8017191A/2500 + 21x309 = 8017191A/2500 = 8017 6489191A/2500 = 1528A = 8 x 2500 = 20,000Hence the required answer is Rs.20,000.

**Q21. A man borrowed a certain amount on S.I and C.I at same rate of interest. At the end of two years, he paid back Rs.1600 and Rs.1664 as S.I and C.I respectively. If he took 3 years to return the amount then what was the difference of C.I and S.I ?**

a) Rs.197.12b) Rs.128.12c) Rs.293.12d) Rs.179.12

__ANS:__**a) Rs.197.12**

Explanation:Let the amount he borrowed be Rs.PLet C.I on P for 2 years be X and S.I on P for 2 years be Y.S.I on P for 1st year = Y/2 .....(1)C.I for 2nd year = Fixed Interest + Interest on interestTherefore, X = Y + S.I on Y/2 for 1st year (by eqn(1))X - Y = S.I on Y/2 for 1st year ....(2)He paid S.I at the end of 2nd year (Y) = Rs.1600 then S.I for 1st year (Y/2) = Rs.800S.I for 3rd year = S.I for 2nd years + S.I for 1st year = Rs.1600 + Rs.800 = Rs.2400 ....(3)He paid C.I at the end of 2nd year = Rs. 1664Difference S.I C.I = (X - Y) = Rs.1664 1600 = Rs. 64.sub. X - Y in eqn(2), we getRs.64 = S.I on Y/2 for 1st year.S.I on Rs.800 for 1st year = Rs.64Therefore, principal P1 = Rs.800, S.I = 64, T = 1 year.Then R = 100 x S.I / P x T= 100 x 64 / 800 x 1 = 8%Now, R = 8%, t = 2 years and S.I = 1600Then, principal P = 100 x S.I / R x T= 100 x 1600 / 8 x 2 = Rs.10,000Now, we have to calculate the C.I on Rs.10,000 for 3 years at 8% per annum.C.I = P [{1 + R/100}n= 10000[{1+ 8/100}3= 10000[{27/25}3= 10000[{273= Rs.2597.12C.I for 3 years = Rs.2597.12Required difference = C.I for 3 years S.I for 3 years = Rs.( 2597.12 2400) = Rs.197.12

**Q22. It costs Rs.P to print each first 500 copies of a document and Rs.Q to print each subsequent copy. Which of the following expression is equal to the total cost to print R number of copies of the document if R is greater than 500?**

a) Rs. R(P - Q) + 500RQb) Rs. 500(P - Q) + RQc) Rs. 500(P + Q) - RQd) Rs. R(P + Q) - 500RQ

__ANS:__**b) Rs. 500(P - Q) + RQ.**

Explanation:Cost to print one copy of first 500 copies = Rs.PTotal cost to print first 500 copies = Rs.(500 x P).We have to print R number of copies, and given that R > 500.For more than 500 copies the cost to print is Rs.Q.Total cost to print remaining (R-500) copies of R = Rs. (R-500) x Q.Required cost to print total R copies = Rs. [500P + (R-500)Q] = 500P + RQ 500Q= Rs. 500(P - Q) + RQ.Hence, the answer is option b.

**Q23. There were certain number of students in a seminar hall before the seminar started. 1 hour later, the number of students in the seminar hall is increased by n% and after another one hour it was decreased by n%. At the end of the seminar, there were only 100 students. Find the initial number of students.**

__ANS:__**10,00,000 / (1002)**

Explanation:Let the number of students be X.After 1 hour, number of students was increased by n%.That is, after 1 hour, number of students = X + nX/100After 2 hours, decreased by n%.That is, after 2 hours, number of students = [X + nX/100] n% of [X + nX/100]= [X + nX/100] (n/100)[ X + nX/100]=(X / 100) (100 + n) (n / 100) (X / 100) (100 + n)=(X / 100) (100 + n){1 (n / 100)}=(X / 100) (100 + n){100 n}(1 / 100)= (X/10000)(1002)There were only 100 students at the end of the seminar.Therefore, from (1), 100 = (X/10000)(1002)X = 10,00,000 / (1002)Hence, the answer is 10,00,000 / (1002)

**Q24. There are 6 members in a family and their average weight is A. If B is the average weight of three of them and C is the average weight of remaining three then which of the following is true?**

a) A = 2(B + C)b) 2A = (B + C)c) A = 3(C + B)d) none of these

__ANS:__**b) 2A = (B + C)**

Explanation:Average weight of 6 members = ATotal weight of 6 members = 6AAverage weight of 3 of them = BTotal weight of this 3 members = 3BAverage weight of remaining 3 = CTotal weight of remaining 3 = 3C.Therefore, 6A = 3B + 3Ci.e., 2A = B+C.Hence the answer is option b.

## Godrej Infotech Placement Papers

➤ Godrej Infotech Technical Interview Questions 2013

➤ Godrej Infotech Verbal Ability

➤ Godrej Infotech Technical Questions

➤ Godrej Infotech Reasoning Ability

➤ Godrej Infotech Arithmetic Ability Questions

➤ Godrej Infotech Aptitude Questions

➤ Godrej Infotech - Model Test Paper

➤ Godrej Placement Paper May 2013

➤ Godrej Placement Paper December 2012, January 2015

➤ Godrej Infotech Written Test Paper 2014

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