Citicorp Aptitude, Technical Test 12th June 2011


Posted on :13-04-2016

 

APTITUDE:

Q1. A man walks from 9.15 to 5.15 from Monday to Friday and 9.00 to 12.00 on Saturday. Each day 0.45 min lunch. How much time he walks in a week?

ANS: 39hrs15min

 

Q2. A company requires 11,500 strength. Present employees are 200 women, men and 6500 unmarried. To reach the target, how many women required to maintain the same ratio?

ANS: 300

 

Q3. Five trays cost is 0.35 each and dozen trays cost is -----

ANS: Rs13.75

 

Q4. In 60 reems of paper 40 reems were utilised then what percent will remain?

ANS: 33.33%

 

Q5. In a journey of 15 miles two third distance was travelled with 40 mph and remaining with 60 mph. How much time the journey takes?

ANS: 20 min

 

Q6. 12 revolutions takes 1/8 th second time. In 20 seconds how many revolutions?

ANS: 1920

 

Q7. A man, how many bikes of Rs. 14000 can buy by selling 2100 bikes of Rs. 500 of each?

ANS: 75

 

Q8. What is the time required to punch 1500 cards of 50 column each at the rate of 10,000 punches per hour?

ANS: 7 hr 30 min

 

Q9. In a storage stall of 5x3x2 inch, how many blanks of size 2x1x1inch can be stored?

ANS: 15

 

Q10. A started at 9.00 am with 6 mph and B started at 9.30 am with 8mph in the same direction. At what time they will meet?

ANS: 11.00 am

 

Q11. In a company 3/5 of people know shorthand 1/4th know typing and 1/5 know both. What fraction of people do not know both?

ANS: 35%

 

Q12. A man said to woman "your only brothers son is my wifes brother". How is the woman related to the mans wife?

ANS: Aunt

 

TECHNICAL:

Q13. What is the output of the following program?

#include
main()
{
char *p1;
char *p2;
p1=(char *) malloc(25);
p2=(char *) malloc(25);
strcpy(p1,"Ramco");
strcpy(p2,"Systems");
strcat(p1,p2);
printf("%s",p1);
}

 

Q14. What is the output of the following program?

main()
{
char *ptr = "Ramco Systems";
(*ptr)++;
printf("%s ",ptr);
ptr++;
printf("%s ",ptr);
}

 

Q15. What is the output of the following program?

#include
main()
{
char s1[] = "Ramco";
char s2[] = "Systems";
s1=s2;
printf("%s", s1);
}

 




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