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Time and Distance Questions: Solved 288 Time and Distance Questions and answers section with explanation for various online exam preparation, various interviews, Aptitude Category online test. Category Questions section with detailed description, explanation will help you to master the topic.
Time and Distance Questions
121. A train running at the speed of 60 km/hr crosses a pole in 9 seconds .What is the length of the train?
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Correct Ans:150 m
Explanation:
Workspace
122. A train 360 m long is running at a speed of 45 km/hr. In what time will it pass a bridge 140 m long?
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Correct Ans:40 seconds
Explanation:
Given, Length of train =360 m
Length of bridge =140 m
Speed of train = 45 km/hr ---> Converting into meter/ second
= 45 * (5/18) m / sec
= 12.5 m/sec
=>Speed of train =12.5 m/sec
Required Time =(Length of train +Length of bridge) /Speed of train
= (360 + 140) / 12.5
= 500 / 12.5
= 40 sec
=>Required Time =40 sec
Length of bridge =140 m
Speed of train = 45 km/hr ---> Converting into meter/ second
= 45 * (5/18) m / sec
= 12.5 m/sec
=>Speed of train =12.5 m/sec
Required Time =(Length of train +Length of bridge) /Speed of train
= (360 + 140) / 12.5
= 500 / 12.5
= 40 sec
=>Required Time =40 sec
Workspace
123. How much time does a train 110 metres long running at the speed of 72 km/hr take to cross a bridge 132 metres in length?
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Correct Ans:12.1 seconds
Explanation:
Given, Length of train = 110 meter
Speed of train =72 km/hr
Length of bridge =132 metre
---> Converting Speed from km/hr into m/sec
=>Speed of train = 72 * (5/18) m/sec
= 4 * 5
= 20 m/sec
Formula:-Time taken by train to cross the bridge = (Length of the train + Length of the bridge) /Speed of train
= (110 + 132) / 20
= 242/ 20
= 12.1 sec
Thus,Time taken by train to cross the bridge =12.1 seconds
Speed of train =72 km/hr
Length of bridge =132 metre
---> Converting Speed from km/hr into m/sec
=>Speed of train = 72 * (5/18) m/sec
= 4 * 5
= 20 m/sec
Formula:-Time taken by train to cross the bridge = (Length of the train + Length of the bridge) /Speed of train
= (110 + 132) / 20
= 242/ 20
= 12.1 sec
Thus,Time taken by train to cross the bridge =12.1 seconds
Workspace
124. A train 280 m long, running with a speed of 63 km/hr will pass a tree in:
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Correct Ans:16 seconds
Explanation:
Given
Length of the train = 280 m
Speed of the train = 63 km / hr
---> To convertkm/hr to m/sec multiply speed with (5 / 18)
= 63 x (5 / 18) m/sec
= 17.5 m/sec
ThereforeSpeed of the train =17.5m/sec
Now,Time taken by the train tocross an electric pole =Length of the train/Speed of the train
= 280/17.5
=16 sec
The time taken is16 sec.
Length of the train = 280 m
Speed of the train = 63 km / hr
---> To convertkm/hr to m/sec multiply speed with (5 / 18)
= 63 x (5 / 18) m/sec
= 17.5 m/sec
ThereforeSpeed of the train =17.5m/sec
Now,Time taken by the train tocross an electric pole =Length of the train/Speed of the train
= 280/17.5
=16 sec
The time taken is16 sec.
Workspace
125. In what time will a train 100 metres long cross an electric pole, if its speed be 144 km/hr?
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Correct Ans:2.5 seconds
Explanation:
Given
Length of the train = 100 m
Speed of the train = 144 km / hr
---> To convertkm/hr to m/sec multiply speed with (5 / 18)
= 144 x (5 / 18) m/sec
= 40 m/sec
Therefore Speed of the train =40 m/sec
Now, Time taken by the train tocross an electric pole =Length of the train/Speed of the train
T = 100 / 40
= 2.5 sec
The time taken is 2.5 sec.
Length of the train = 100 m
Speed of the train = 144 km / hr
---> To convertkm/hr to m/sec multiply speed with (5 / 18)
= 144 x (5 / 18) m/sec
= 40 m/sec
Therefore Speed of the train =40 m/sec
Now, Time taken by the train tocross an electric pole =Length of the train/Speed of the train
T = 100 / 40
= 2.5 sec
The time taken is 2.5 sec.
Workspace
126. Two trains 100 metres and 120 metres long are running in the same direction with the speeds of 72 km/hr and 54 km/hr .In how much time will the first train cross the second?
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Correct Ans:44 second
Explanation:
Workspace
127. A train is moving at a speed of 132 km/hr .If the length of the train is 110 metres ,how long will it take to cross a railway platform 165 metres long?
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Correct Ans:7 1/2 sec
Explanation:
Workspace
128. A train 100 m long is running at the speed of 30 km/hr.Find the time taken by it to pass a man standing near the railway line:
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Correct Ans:12 sec
Explanation:
Workspace
129. A man rows to a place 48 km distant and come back in 14 hours. He finds that he can row 4 km with the stream in the same time as 3 km against the stream. The rate of the stream is:
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Correct Ans:1 km/hr
Explanation:
Suppose he move 4 km downstream in x hours. Then,
Speed downstream = ( 4/ x ) km/hr.
Speed upstream = (3/ x ) km/hr.
Therefore, 48 / ( 4 / x ) + 48 / (3/x) = 14 or x = 1/2 .
So, Speed downstream = 8 km/hr, Speed upstream = 6 km/hr.
Rate of the stream = 1 / 2 (8-6) km/hr = 1 km/hr
Workspace
130. A man takes twice as long to row a distance against the stream as to row the same distance in favour of the stream. The ratio of the speed of the boat (in still water) and the stream is:
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Correct Ans:3:1
Explanation:
Let man's rate upstream be x kmph.
Then, his rate downstream = 2x kmph.
WKT,
Speed of still water = 1/2(x + y)
Speed of stream = 1/2(x - y)
Therefore , (Speed in still water) : (Speed of stream)
( 2x + x) /2 : ( 2x - x) /2
3x / 2 : x /2
3 : 1
Then, his rate downstream = 2x kmph.
WKT,
Speed of still water = 1/2(x + y)
Speed of stream = 1/2(x - y)
Therefore , (Speed in still water) : (Speed of stream)
( 2x + x) /2 : ( 2x - x) /2
3x / 2 : x /2
3 : 1
Workspace
131. Speed of a boat in standing water is 9 kmph and the speed of the stream is 1.5 kmph. A man rows to a place at a distance of 105 km and comes back to the starting point. The total time taken by him is:
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Correct Ans:24 hours
Explanation:
Given
Distance = 105 km
Speed upstream = 7.5 kmph.
Speed downstream = 10.5 kmph.
Total time taken = Distance / Speed inupstream +Speed indownstream
= ( 105 / 7.5) + (105 / 10.5 ) hours
= 14 + 10
= 24 hours.
Total time taken by him = 24 hours.
Distance = 105 km
Speed upstream = 7.5 kmph.
Speed downstream = 10.5 kmph.
Total time taken = Distance / Speed inupstream +Speed indownstream
= ( 105 / 7.5) + (105 / 10.5 ) hours
= 14 + 10
= 24 hours.
Total time taken by him = 24 hours.
Workspace
132. A boatman goes 2 km against the current of the stream in 1 hour and goes 1 km along the current in 10 minutes. How long will it take to go 5 km in stationary water ?
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Correct Ans:1 hr 15 min
Explanation:
Rate downstream = ( 1 / 10 x 60 ) km/hr = 6 km/hr
Rate upstream = 2 km/hr.
Speed in still water = 1/2 (6 + 2) km/hr = 4 km/hr.
Therefore, Required time = ( 5/4 ) hrs = 1 ( 1/4 ) hrs = 1 hr 15 min.
Rate upstream = 2 km/hr.
Speed in still water = 1/2 (6 + 2) km/hr = 4 km/hr.
Therefore, Required time = ( 5/4 ) hrs = 1 ( 1/4 ) hrs = 1 hr 15 min.
Workspace
133. A boat covers a certain distance downstream in 1 hour, while it comes back in 1 1/2 hours. If the speed of the stream be 3 kmph, what is the speed of the boat in still water?
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Correct Ans:15 kmph
Explanation:
Let the speed of the boat in still water be x kmph.
Given,speed of the stream = 3 kmph
Then, Speed downstream = speed of the boat +speed of the stream
= (x + 3) kmph
Speed upstream = speed of the boat - speed of the stream
= (x - 3) kmph.
Therefore, Downstream distance =upstream distance
=> SpeedDownstream * Downstream Time =Speedupstream *upstream Time
=> (x + 3) x 1 = (x - 3) x 3/2
=> 2x + 6 = 3x - 9
=> x = 15 kmph.
Thus,speed of the boat in still water = 15 kmph
Given,speed of the stream = 3 kmph
Then, Speed downstream = speed of the boat +speed of the stream
= (x + 3) kmph
Speed upstream = speed of the boat - speed of the stream
= (x - 3) kmph.
Therefore, Downstream distance =upstream distance
=> SpeedDownstream * Downstream Time =Speedupstream *upstream Time
=> (x + 3) x 1 = (x - 3) x 3/2
=> 2x + 6 = 3x - 9
=> x = 15 kmph.
Thus,speed of the boat in still water = 15 kmph
Workspace
134. A man can row at 5 kmph in still water. If the velocity of current is 1 kmph and it takes him 1 hour to row to a place and come back, how far is the place ?
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Correct Ans:2.4 km
Explanation:
If the speed of a boat in still water is xkm/hr and the speed of the stream is ykm/hr, then:
Speed downstream = (x+ y) km/hr.
Speed upstream = (x- y) km/hr.
Speed downstream = (5 + 1) kmph = 6 kmph.Speed upstream = (5 - 1) kmph = 4 kmph.
Let the required distance be x km.
Distance / Speed = Time
Given, Time fordownstream+ upstream = 1 hour
Then, x / 6 + x / 4 = 1
=> 2x + 3x = 12
=> 5x = 12
=> x = 2.4 km
Thus, the required distance =2.4 km
Workspace
135. A boat takes 90 minutes less to travel 36 miles downstream than to travel the same distance upstream. If the speed of the boat in still water is 10 mph, the speed of the stream is:
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Correct Ans:2 mph
Explanation:
Let the speed of the stream be x mph.
Given, Speed of Boat = 10 mph
Then, Speed downstream = speed of Boat +Speed of Stream
= (10 + x) mph,
Speed upstream = speed of Boat -Speed of Stream
= (10 - x) mph.
Therefore, Upstream Time - Downstream Time = 90 mins
Since, Time = Distance / Speed
So, [Upstream Distance / Upstream Speed] - [Downstream Distance / Downstream Speed] = 90 mins
=> [36 / ( 10 - x)] - [36 / (10 + x )] = 90 / 60
=> 36 (10 + x -10 + x) / (10^2 - x^2) = 3/2
=> 12 (2x / 100 - x^2) = 1/2
=> 24 (2x) = 100 - x^2
=> 48 x = 100 - x^2
=> x^2 + 48x - 100 = 0
=> (x+ 50)(x - 2) = 0
=> x = 2 mph
Therefore,speed of the stream= 2 mph.
Given, Speed of Boat = 10 mph
Then, Speed downstream = speed of Boat +Speed of Stream
= (10 + x) mph,
Speed upstream = speed of Boat -Speed of Stream
= (10 - x) mph.
Therefore, Upstream Time - Downstream Time = 90 mins
Since, Time = Distance / Speed
So, [Upstream Distance / Upstream Speed] - [Downstream Distance / Downstream Speed] = 90 mins
=> [36 / ( 10 - x)] - [36 / (10 + x )] = 90 / 60
=> 36 (10 + x -10 + x) / (10^2 - x^2) = 3/2
=> 12 (2x / 100 - x^2) = 1/2
=> 24 (2x) = 100 - x^2
=> 48 x = 100 - x^2
=> x^2 + 48x - 100 = 0
=> (x+ 50)(x - 2) = 0
=> x = 2 mph
Therefore,speed of the stream= 2 mph.
Workspace
136. The speed of a boat in still water is 15 km/hr and the rate of current is 3 km/hr. The distance travelled downstream in 12 minutes is:
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Correct Ans:3.6 km
Explanation:
Speed downstream = (15 + 3) kmph = 18 kmph. Distance travelled = ( 18 x 12 / 60 ) km = 3.6 km.
Workspace
137. A boat running downstream covers a distance of 16 km in 2 hours while for covering the same distance upstream, it takes 4 hours. What is the speed of the boat in still water?
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Correct Ans:6 km/hr
Explanation:
Rate downstream = (16 / 2 ) kmph = 8 kmph
Rate upstream = (16/4) kmph = 4 kmph
Speed in still water = 1/2 (8 + 4 ) kmph = 6 kmph.
Workspace
138. In one hour, a boat goes 11 km/hr along the stream and 5 km/hr against the stream. The speed of the boat in still water (in km/hr) is:
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Correct Ans:8 km/hr
Explanation:
Speed in still water = 1/2 ( 11 + 5) kmph = 8 kmph.
Workspace
139. A motorboat, whose speed in 15 km/hr in still water goes 30 km downstream and comes back in a total of 4 hours 30 minutes. The speed of the stream (in km/hr) is:
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Correct Ans:5
Explanation:
Let the speed of the stream be x km/hr.
Then, Speed downstream = (15 + x) km/hr,
Speed upstream = (15 - x) km/hr.
Therefore 30 / (15 + x) + 30 / (15 - x ) = 4 (1/2)
=> 900 / 225 - x^2 = 9/2
=> 100 / 225 - x^2 = 1/2
=> 200 =225 - x^2
=> x^2 = 225 - 200
=> x^2 = 25
=> x = 5 km/hr
Therefore, the speed of the stream = 5 km/hr
Then, Speed downstream = (15 + x) km/hr,
Speed upstream = (15 - x) km/hr.
Therefore 30 / (15 + x) + 30 / (15 - x ) = 4 (1/2)
=> 900 / 225 - x^2 = 9/2
=> 100 / 225 - x^2 = 1/2
=> 200 =225 - x^2
=> x^2 = 225 - 200
=> x^2 = 25
=> x = 5 km/hr
Therefore, the speed of the stream = 5 km/hr
Workspace
140. A man's speed with the current is 15 km/hr and the speed of the current is 2.5 km/hr. The man's speed against the current is:
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Correct Ans:10 km/hr
Explanation:
Man's rate in still water = (15 - 2.5) km/hr = 12.5 km/hr.
Man's rate against the current = (12.5 - 2.5) km/hr = 10 km/hr.
Workspace
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