# Time and Distance Questions and Answers updated daily – Aptitude

Time and Distance Questions: Solved 288 Time and Distance Questions and answers section with explanation for various online exam preparation, various interviews, Aptitude Category online test. Category Questions section with detailed description, explanation will help you to master the topic.

## Time and Distance Questions

121. A train running at the speed of 60 km/hr crosses a pole in 9 seconds .What is the length of the train?

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Correct Ans:150 m

Explanation:

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122. A train 360 m long is running at a speed of 45 km/hr. In what time will it pass a bridge 140 m long?

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Correct Ans:40 seconds

Explanation:

Given, Length of train =360 m

Length of bridge =140 m

Speed of train = 45 km/hr ---> Converting into meter/ second

= 45 * (5/18) m / sec

= 12.5 m/sec

=>

= (360 + 140) / 12.5

= 500 / 12.5

Length of bridge =140 m

Speed of train = 45 km/hr ---> Converting into meter/ second

= 45 * (5/18) m / sec

= 12.5 m/sec

=>

**Speed of train =12.5 m/sec****Required Time =(Length of train +Length of bridge) /Speed of train**= (360 + 140) / 12.5

= 500 / 12.5

**= 40 sec**

=>Required Time =40 sec=>Required Time =40 sec

Workspace

123. How much time does a train 110 metres long running at the speed of 72 km/hr take to cross a bridge 132 metres in length?

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Correct Ans:12.1 seconds

Explanation:

Given, Length of train = 110 meter

Speed of train =72 km/hr

Length of bridge =132 metre

---> Converting Speed from km/hr into m/sec

=>Speed of train = 72 * (5/18) m/sec

= 4 * 5

=

= (110 + 132) / 20

= 242/ 20

= 12.1 sec

Thus,

Speed of train =72 km/hr

Length of bridge =132 metre

---> Converting Speed from km/hr into m/sec

=>Speed of train = 72 * (5/18) m/sec

= 4 * 5

=

**20**m/sec__Formula__:-Time taken by train to cross the bridge = (Length of the train + Length of the bridge) /Speed of train= (110 + 132) / 20

= 242/ 20

= 12.1 sec

Thus,

**Time taken by train to cross the bridge =12.1 seconds**
Workspace

124. A train 280 m long, running with a speed of 63 km/hr will pass a tree in:

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Correct Ans:16 seconds

Explanation:

Given

Speed of the train = 63 km / hr

---> To convertkm/hr to m/sec multiply speed with (5 / 18)

= 63 x (5 / 18) m/sec

= 17.5 m/sec

Therefore

Now,

= 280/17.5

=

The time taken is

**Length of the train = 280 m**Speed of the train = 63 km / hr

---> To convertkm/hr to m/sec multiply speed with (5 / 18)

= 63 x (5 / 18) m/sec

= 17.5 m/sec

Therefore

**Speed of the train =17.5****m/sec**Now,

**Time taken by the train tocross an electric pole =Length of the train/Speed of the train**= 280/17.5

=

**16 sec**The time taken is

**16 sec**.
Workspace

125. In what time will a train 100 metres long cross an electric pole, if its speed be 144 km/hr?

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Correct Ans:2.5 seconds

Explanation:

Given

Speed of the train = 144 km / hr

---> To convertkm/hr to m/sec multiply speed with (5 / 18)

= 144 x (5 / 18) m/sec

= 40 m/sec

Therefore

Now,

T = 100 / 40

=

The time taken is

**Length of the train = 100 m**Speed of the train = 144 km / hr

---> To convertkm/hr to m/sec multiply speed with (5 / 18)

= 144 x (5 / 18) m/sec

= 40 m/sec

Therefore

**Speed of the train =40 m/sec**Now,

**Time taken by the train tocross an electric pole =Length of the train/Speed of the train**T = 100 / 40

=

**2.5 sec**The time taken is

**2.5 sec**.
Workspace

126. Two trains 100 metres and 120 metres long are running in the same direction with the speeds of 72 km/hr and 54 km/hr .In how much time will the first train cross the second?

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Correct Ans:44 second

Explanation:

Workspace

127. A train is moving at a speed of 132 km/hr .If the length of the train is 110 metres ,how long will it take to cross a railway platform 165 metres long?

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Correct Ans:7 1/2 sec

Explanation:

Workspace

128. A train 100 m long is running at the speed of 30 km/hr.Find the time taken by it to pass a man standing near the railway line:

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Correct Ans:12 sec

Explanation:

Workspace

129. A man rows to a place 48 km distant and come back in 14 hours. He finds that he can row 4 km with the stream in the same time as 3 km against the stream. The rate of the stream is:

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Correct Ans:1 km/hr

Explanation:

Suppose he move 4 km downstream in x hours. Then,
Speed downstream = ( 4/ x ) km/hr.
Speed upstream = (3/ x ) km/hr.
Therefore, 48 / ( 4 / x ) + 48 / (3/x) = 14 or x = 1/2 .
So, Speed downstream = 8 km/hr, Speed upstream = 6 km/hr.
Rate of the stream = 1 / 2 (8-6) km/hr = 1 km/hr

Workspace

130. A man takes twice as long to row a distance against the stream as to row the same distance in favour of the stream. The ratio of the speed of the boat (in still water) and the stream is:

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Correct Ans:3:1

Explanation:

Let man's rate upstream be x kmph.

Then, his rate downstream = 2x kmph.

WKT,

Therefore , (Speed in still water) : (Speed of stream)

( 2x + x) /2 : ( 2x - x) /2

3x / 2 : x /2

3 : 1

Then, his rate downstream = 2x kmph.

WKT,

**Speed of still water = 1/2(x + y)**

Speed of stream = 1/2(x - y)Speed of stream = 1/2(x - y)

Therefore , (Speed in still water) : (Speed of stream)

( 2x + x) /2 : ( 2x - x) /2

3x / 2 : x /2

3 : 1

Workspace

131. Speed of a boat in standing water is 9 kmph and the speed of the stream is 1.5 kmph. A man rows to a place at a distance of 105 km and comes back to the starting point. The total time taken by him is:

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Correct Ans:24 hours

Explanation:

Given

Distance = 105 km

Speed upstream = 7.5 kmph.

Speed downstream = 10.5 kmph.

Total time taken = Distance / Speed inupstream +Speed indownstream

= ( 105 / 7.5) + (105 / 10.5 ) hours

= 14 + 10

=

Total time taken by him =

Distance = 105 km

Speed upstream = 7.5 kmph.

Speed downstream = 10.5 kmph.

Total time taken = Distance / Speed inupstream +Speed indownstream

= ( 105 / 7.5) + (105 / 10.5 ) hours

= 14 + 10

=

**24 hours.**Total time taken by him =

**24 hours.**
Workspace

132. A boatman goes 2 km against the current of the stream in 1 hour and goes 1 km along the current in 10 minutes. How long will it take to go 5 km in stationary water ?

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Correct Ans:1 hr 15 min

Explanation:

Rate downstream = ( 1 / 10 x 60 ) km/hr = 6 km/hr

Rate upstream = 2 km/hr.

Speed in still water = 1/2 (6 + 2) km/hr = 4 km/hr.

Therefore, Required time = ( 5/4 ) hrs = 1 ( 1/4 ) hrs = 1 hr 15 min.

Rate upstream = 2 km/hr.

Speed in still water = 1/2 (6 + 2) km/hr = 4 km/hr.

Therefore, Required time = ( 5/4 ) hrs = 1 ( 1/4 ) hrs = 1 hr 15 min.

Workspace

133. A boat covers a certain distance downstream in 1 hour, while it comes back in 1 1/2 hours. If the speed of the stream be 3 kmph, what is the speed of the boat in still water?

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Correct Ans:15 kmph

Explanation:

Let the speed of the boat in still water be x kmph.

Given,speed of the stream = 3 kmph

Then,

= (x + 3) kmph

= (x - 3) kmph.

Therefore,

=> (x + 3) x 1 = (x - 3) x 3/2

=> 2x + 6 = 3x - 9

=>

Given,speed of the stream = 3 kmph

Then,

**Speed downstream = speed of the boat +speed of the stream**= (x + 3) kmph

**Speed upstream = speed of the boat - speed of the stream**= (x - 3) kmph.

Therefore,

**Downstream distance =upstream distance**

=> SpeedDownstream * Downstream Time =Speedupstream *=> SpeedDownstream * Downstream Time =Speedupstream *

**upstream Time**=> (x + 3) x 1 = (x - 3) x 3/2

=> 2x + 6 = 3x - 9

=>

**x = 15 kmph.**

Thus,speed of the boat in still water = 15 kmphThus,speed of the boat in still water = 15 kmph

Workspace

134. A man can row at 5 kmph in still water. If the velocity of current is 1 kmph and it takes him 1 hour to row to a place and come back, how far is the place ?

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Correct Ans:2.4 km

Explanation:

If the speed of a boat in still water is *x*km/hr and the speed of the stream is *y*km/hr, then:

**Speed downstream = ( x+ y) km/hr.**

**Speed upstream = ( x- y) km/hr.**

Speed upstream = (5 - 1) kmph = 4 kmph.

Let the required distance be x km.

**Distance / Speed = Time**

Given,Time fordownstream+ upstream = 1 hour

Given,

Then, x / 6 + x / 4 = 1

=> 2x + 3x = 12

=> 5x = 12

=>

**x = 2.4 km**

Thus, the required distance =2.4 km

Thus, the required distance =2.4 km

Workspace

135. A boat takes 90 minutes less to travel 36 miles downstream than to travel the same distance upstream. If the speed of the boat in still water is 10 mph, the speed of the stream is:

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Correct Ans:2 mph

Explanation:

Let the speed of the stream be x mph.

Given, Speed of Boat = 10 mph

Then,

= (10 + x) mph,

= (10 - x) mph.

Therefore,

=> [36 / ( 10 - x)] - [36 / (10 + x )] = 90 / 60

=> 36 (10 + x -10 + x) / (10^2 - x^2) = 3/2

=> 12 (2x / 100 - x^2) = 1/2

=> 24 (2x) = 100 - x^2

=> 48 x = 100 - x^2

=> x^2 + 48x - 100 = 0

=> (x+ 50)(x - 2) = 0

=>

Given, Speed of Boat = 10 mph

Then,

**Speed downstream = speed of Boat +Speed of Stream**= (10 + x) mph,

**Speed upstream = speed of Boat -Speed of Stream**= (10 - x) mph.

Therefore,

**Upstream Time - Downstream Time = 90 mins**

Since, Time = Distance / Speed

So, [Upstream Distance / Upstream Speed] - [Downstream Distance / Downstream Speed] = 90 minsSince, Time = Distance / Speed

So, [Upstream Distance / Upstream Speed] - [Downstream Distance / Downstream Speed] = 90 mins

=> [36 / ( 10 - x)] - [36 / (10 + x )] = 90 / 60

=> 36 (10 + x -10 + x) / (10^2 - x^2) = 3/2

=> 12 (2x / 100 - x^2) = 1/2

=> 24 (2x) = 100 - x^2

=> 48 x = 100 - x^2

=> x^2 + 48x - 100 = 0

=> (x+ 50)(x - 2) = 0

=>

**x = 2 mph**

Therefore,speed of the stream= 2 mph.Therefore,speed of the stream= 2 mph.

Workspace

136. The speed of a boat in still water is 15 km/hr and the rate of current is 3 km/hr. The distance travelled downstream in 12 minutes is:

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Correct Ans:3.6 km

Explanation:

Speed downstream = (15 + 3) kmph = 18 kmph. Distance travelled = ( 18 x 12 / 60 ) km = 3.6 km.

Workspace

137. A boat running downstream covers a distance of 16 km in 2 hours while for covering the same distance upstream, it takes 4 hours. What is the speed of the boat in still water?

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Correct Ans:6 km/hr

Explanation:

Rate downstream = (16 / 2 ) kmph = 8 kmph
Rate upstream = (16/4) kmph = 4 kmph
Speed in still water = 1/2 (8 + 4 ) kmph = 6 kmph.

Workspace

138. In one hour, a boat goes 11 km/hr along the stream and 5 km/hr against the stream. The speed of the boat in still water (in km/hr) is:

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Correct Ans:8 km/hr

Explanation:

Speed in still water = 1/2 ( 11 + 5) kmph = 8 kmph.

Workspace

139. A motorboat, whose speed in 15 km/hr in still water goes 30 km downstream and comes back in a total of 4 hours 30 minutes. The speed of the stream (in km/hr) is:

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Correct Ans:5

Explanation:

Let the speed of the stream be x km/hr.

Then, Speed downstream = (15 + x) km/hr,

Speed upstream = (15 - x) km/hr.

Therefore 30 / (15 + x) + 30 / (15 - x ) = 4 (1/2)

=> 900 / 225 - x^2 = 9/2

=> 100 / 225 - x^2 = 1/2

=> 200 =225 - x^2

=> x^2 = 225 - 200

=> x^2 = 25

=>

Therefore, the

Then, Speed downstream = (15 + x) km/hr,

Speed upstream = (15 - x) km/hr.

Therefore 30 / (15 + x) + 30 / (15 - x ) = 4 (1/2)

=> 900 / 225 - x^2 = 9/2

=> 100 / 225 - x^2 = 1/2

=> 200 =225 - x^2

=> x^2 = 225 - 200

=> x^2 = 25

=>

**x = 5 km/hr**Therefore, the

**speed of the stream = 5 km/hr**
Workspace

140. A man's speed with the current is 15 km/hr and the speed of the current is 2.5 km/hr. The man's speed against the current is:

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Correct Ans:10 km/hr

Explanation:

Man's rate in still water = (15 - 2.5) km/hr = 12.5 km/hr.
Man's rate against the current = (12.5 - 2.5) km/hr = 10 km/hr.

Workspace

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