# Puzzle Questions and Answers updated daily – Logical Reasoning

Puzzle Questions: Solved 717 Puzzle Questions and answers section with explanation for various online exam preparation, various interviews, Logical Reasoning Category online test. Category Questions section with detailed description, explanation will help you to master the topic.

## Puzzle Questions

661. In a party of 77 people, there are twice as many women as children and twice as many children as men. How many children were present

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Correct Ans:22
Explanation:
Let m be the number of men, w be no. of women and c be no. of children. Then w/c = 2 => w=2c c/m = 2 => m = c/2 Now, m + w + c = 77 => c/2 + c+2c = 77=> 7c/2 = 77=> c/2 = 11 => c = 22 Now, no. of children = 22
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662. What is the angle between the hands of the clock at 4:40 ?

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Correct Ans:100o
Explanation:
Soln: At 4 the angle between the hands, A = 120o
In 40 min, B = 40 X 5.5 = 220o
The required angle = A ~ B = 100o
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663. At what time between 5 and 6 will the hands of the clock coincide?

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Correct Ans:27 3/11 min
Explanation:
Soln: At 5 the angle between the hands is 150 deg. To coincide, they collectively have to travel this distance. Every minute they travel 5.5 deg. So no. of minutes required to coincide = 150 / 5.5 = 300 / 11 = 27 3/11 min.
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664. In a row of trees, a tree is 29th from left end and 11th from right end. How many tree are there in the row ?

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Correct Ans:39
Explanation:
Number of trees in total will be = 29+11 - 1= 39
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665. In a party of 49 people, there are twice as many women as children and twice as many children as men. How many children were present

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Correct Ans:14
Explanation:
Let m be the number of men, w be no. of women and c be no. of children. Then w/c = 2 => w=2c c/m = 2 => m = c/2 Now, m + w + c = 49 => c/2 + c+2c = 49=> 7c/2 = 49=> c/2 = 7 => c = 14 Now, no. of children = 14
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666. Find the angle between two hands of a clock at 25 minutes past 11 O clock.

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Correct Ans:32.5
Explanation:
Here H = 11 and M = 25 The required angle = 30 (H - M/5) + M/2 degrees = 30 ( 11-25/5) + 25/2 degrees = 32.5degrees (note angles to be expressed in positive sign)
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667. Find the angle between two hands of a clock at 30 minutes past 12 O clock.

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Correct Ans:75
Explanation:
Here H = 12 and M = 30 The required angle = 30 (H - M/5) + M/2 degrees = 30 ( 12-30/5) + 30/2 degrees = 75degrees (note angles to be expressed in positive sign)
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668. In a party of 84 people, there are twice as many women as children and twice as many children as men. How many children were present

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Correct Ans:24
Explanation:
Let m be the number of men, w be no. of women and c be no. of children. Then w/c = 2 => w=2c c/m = 2 => m = c/2 Now, m + w + c = 84 => c/2 + c+2c = 84=> 7c/2 = 84=> c/2 = 12 => c = 24 Now, no. of children = 24
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669. In a row of trees, a tree is 13th from left end and 19th from right end. How many tree are there in the row ?

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Correct Ans:31
Explanation:
Number of trees in total will be = 13+19 - 1= 31
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670. Find the angle between two hands of a clock at 20 minutes past 6 O clock.

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Correct Ans:70
Explanation:
Here H = 6 and M = 20
The required angle = 30 (H - M/5) + M/2 degrees = 30 ( 6-20/5) + 20/2 degrees = 70 degrees (note angles to be expressed in positive sign)
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671. Find the angle between two hands of a clock at 10 minutes past 4 O clock.

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Correct Ans:65
Explanation:
Here H = 4 and M = 10
The required angle = 30 (H - M/5) + M/2 degrees = 30 ( 4-10/5) + 10/2 degrees = 65 degrees (note angles to be expressed in positive sign)
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672. In a party of 98 people, there are twice as many women as children and twice as many children as men. How many children were present?

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Correct Ans:28
Explanation:
Let m be the number of men, w be no. of women and c be no. of children. Then w/c = 2 => w=2c c/m = 2 => m = c/2
Now, m + w + c = 98 => c/2 + c + 2c = 98 => 7c/2 = 98 => c/2 = 14 => c = 28
Now, no. of children = 28
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673. In a row of trees, a tree is 17th from left end and 16th from right end. How many trees are there in the row ?

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Correct Ans:32
Explanation:
Number of trees in total will be = 17+16 - 1= 32
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674. Find the angle between two hands of a clock at 20 minutes past 3 O clock.

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Correct Ans:20
Explanation:
Here H = 3 and M = 20
The required angle = 30 (H - M/5) + M/2 degrees = 30 ( 3-20/5) + 20/2 degrees = 20 degrees (note angles to be expressed in positive sign)
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675. Find the angle between two hands of a clock at 10 minutes past 2 O clock.

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Correct Ans:5
Explanation:
Here H = 2 and M = 10
The required angle = 30 (H - M/5) + M/2 degrees
= 30 ( 2 - 10/5) + 10/2 degrees = 5 degrees (note angles to be expressed in positive sign)
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676. In a party of 77 people, there are twice as many women as children and twice as many children as men. How many men were present?

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Correct Ans:11
Explanation:
Let m be the number of men, w be no. of women and c be no. of children.
Then w/c = 2 => w = 2c c/m = 2 => m = c/2
Now, m + w + c = 77 => c/2 + c + 2c = 77 => 7c/2 = 77 => c/2 = 11 => c = 22
Now, no. of men = c/2 = 22/2 = 11
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677. In a row of trees, a tree is 8th from left end and 17th from right end. How many trees are there in the row ?

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Correct Ans:24
Explanation:
Number of trees in total will be = 8+17 - 1= 24
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678. In a party of 84 people, there are twice as many women as children and twice as many children as men. How many children were present ?

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Correct Ans:24
Explanation:
Let m be the number of men, w be no. of women and c be no. of children.
Then w/c = 2 => w=2c c/m = 2 => m = c/2
Now, m + w + c = 84 => c/2 + c+ 2c = 84
=> 7c/2 = 84 => c/2 = 12 => c = 24
Now, no. of children = 24
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679. Two numbers add upto 11, what could be the maximum value of their product  ?

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Correct Ans:30.25
Explanation:
Solution is :
1+10 = 11 ,
1 x 11 = 11 2 + 9 = 11 ,
2 x 9 = 18 3 + 8 = 11 ,
3 x 8 = 24 4 + 7 = 11 ,
4 x 7 = 28 5 + 6 = 11,
5 x 6 = 30 5.5 + 5.5 = 11 ,
5.5 x 5.5 = 30.25
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680. In a row of trees, a tree is 8th from left end and 15th from right end. How many trees are there in the row  ?

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Correct Ans:22
Explanation:
Solution is :
Number of trees in total will be = 8+15 - 1= 22
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