# Mixture and Alligation Questions and Answers updated daily – Aptitude

Mixture and Alligation Questions: Solved 187 Mixture and Alligation Questions and answers section with explanation for various online exam preparation, various interviews, Aptitude Category online test. Category Questions section with detailed description, explanation will help you to master the topic.

## Mixture and Alligation Questions

161. A zookeeper counted the heads of the animals in a zoo and found it to be 80. When he counted the legs of the animals he found it to be 260. If the zoo had either pigeons or horses, how many horses were there in the zoo?

Correct Ans:50
Explanation:
Given, total number of heads = 80 = Total number of Animals in the zoo
Total Number of legs = 260
Let the number of horses = x
Then the number of pigeons = 80 – x.

Each pigeon has 2 legs and each horse has 4 legs.
Therefore, total number of legs= 4x + 2(80−x) = 260
=> 4x + 160 - 2x = 260
=> 2x = 100
=> x =50
Therefore, number of horses = x = 50
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162. How many liters of a 12 litre mixture containing milk and water in the ratio of 2 : 3 be replaced with pure milk so that the resultant mixture contains milk and water in equal proportion?

Correct Ans:2 liters
Explanation:
The mixture contains 40% milk and 60% water in it.
That is 4.8 liters of milk and 7.2 liters of water.

Now we are replacing the mixture with pure milk so that the amount of milk and water in the mixture is 50% and 50%.
That is we will end up with 6 liters of milk and 6 liters of water.

Water gets reduced by 1.2 liters.
To remove 1.2 liters of water from the original mixture containing 60% water, we need to remove 1.2 / 0.6 liters of the mixture = 2 liters
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163. 48 liters of a mixture has 75% alcohol. How much water must be added to it to get 60% alcohol concentration ?

Correct Ans:12 liters
Explanation:
In 48 liters, alcohol = (75/100) x 48 = 36 liters. Let x liters of water be added => (36/(48+x))x 100 = 60 => 36/(48+x) = 3/5 180 = 144 + 3x => x = 36/3 = 12 liters
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164. 17 liters of mixture has 80% milk. How much milk should be added to the mixture to make it 90% pure?

Correct Ans:17 liters
Explanation:
In mixture, concentration of milk = 80 % In milk, concentration of milk = 100% 80 100 90 10 10 1 1 Ratio is 1 : 1, hence we need to add 17 liters of milk to the 17 liters of mixture.
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165. If the average income of a family of 'x' members is Rs. 25000 while average income of another family of 6 members is Rs. 32000, then find the value of 'x' if the average income of both families is Rs. 28000

Correct Ans:8
Explanation:
25 32 28 32-28 = 4 28-25 = 3 Required ratio is 4 : 3 Ratio of the number members in family 1 and 2 is 4 : 3. 2nd family there are 6 members, => there should be 8 people in the first family.
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166. How many kgs of Basmati rice costing Rs.42/kg should a shopkeeper mix with 25 kgs of ordinary rice costing Rs.24 per kg so that he makes a profit of 25% on selling the mixture at Rs.40/kg?

Correct Ans:20
Explanation:
Let the amount of Basmati rice being mixed be x kgs. As the trader makes 25% profit by selling the mixture at Rs.40/kg, his cost /kg of the mixture = Rs.32/kg. i.e. (x * 42) + (25 * 24) = 32 (x + 25) => 42x + 600 = 32x + 800 => 10x = 200 or x = 20 kgs.
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167. How many liters of water should be added to a 30 liter mixture of milk and water containing milk and water in the ratio 7:3 such that the resultant mixture has 40 % water in it.

Correct Ans:5
Explanation:
30 Liters of mixture, Milk and water in the ratio 7 : 3 Which means, we have 21 liters of milk and 9 liters of water. We add water the resulting solution is 21 liters of milk and 9 + x liters of water. Total quantity = 30 +x. Water percentage is 40 % = > 40 x (30+x)/100 = 9 + x 4(30+x) = 10(9+x) => 120 + 4x = 90 + 10x => 10x – 6x = 120-90 6x = 120 – 90 => 6x = 30 => x = 5
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168. The average marks of 10 students of a class is 72 and the average marks of another 12 students of the same class is 75, find the overall average of the class.

Correct Ans:73.64
Explanation:
Solution is :
Given

Average marks of 10 students = 72
Average marks = Total marks / No of students
Total marks of 10 students = ( Average marks of 10 students ) * ( No of students )
= 10 x 72 = 720
Given , Average marks of another 12 students = 75
Total marks of another 12 students = 12 x 75 = 900
Total marks of the class = 900 + 720 = 1620
Total number of students in the class = 10 + 12 = 22
Overall average of the class = (Total marks of the class) / (Total number of students in the class)
= 1620 / 22
= 810 / 11
= 73.64
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169. A 20 liters mixture of milk and water comprising 60% pure milk is mixed with "x" liters of pure milk. The new mixture comprises 80% milk. What is the value of "x"?

Correct Ans:20
Explanation:
Solution is :
Original mixture comprises 20 liters of milk and water.
Out of the 20 liters, 60% is pure milk.
=> ( 60 / 100 ) x 20 = pure milk
=> 12 liters = pure milk
In 20 liters mixture remaining 8 liters = water
When "x" liters of pure milk is added to 20 liters of mixture
New mixture = ( 20 + x ) liters
Milk in new mixture = ( 12 + x ) liters
Given milk in new mixture = 80% of ( 20 + x )
=> 12 + x = ( 80 / 100 ) * ( 20 + x )
=> 12 + x = ( 4 / 5 ) * ( 20 + x )
=> 5 ( 12 + x ) = 4 ( 20 + x )
=> 60 + 5 x = 80 + 4 x
=> 5 x - 4 x = 80 - 60
=> x = 20 liters
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170. A zookeeper counted the heads of the animals in a zoo and found it to be 80. When he counted the legs of the animals he found it to be 260. If the zoo had either pigeons or horses, how many horses were there in the zoo?

Correct Ans:50
Explanation:
Solution is:
Given , Zoo had either pigeons or horses
Heads of the animals in Zoo = 80
=> pigeons + horses = 80
Let p = number of pigeons
h = number of horses
=> p = 80 - h
Given , Legs of the animals = 260
Each pigeon has 2 legs and each horse has 4 legs
=> 2p + 4h = 260
Substitute p = 80 - h
=> 2 ( 80 - h ) + 4h = 260
=> 160 - 2h + 4h = 260
=> 2h = 260 - 160
=> 2h = 100
h = 50
So , number of horses in the Zoo = 50
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171. How many liters of a 12 litre mixture containing milk and water in the ratio of 2 : 3 be replaced with pure milk so that the resultant mixture contains milk and water in equal proportion?

Correct Ans:2 liters
Explanation:
Solution is:
The mixture contains 40% milk and 60% water in it.
Given , Mixture ( milk + water ) = 12 liters
milk ( m ) / water ( w ) = 2 / 3
=> m / w = 2x liters / 3x liters
so, 2x + 3x = 12 liters
5x = 12
x = 12 / 5
x = 2.4
milk , m = 2x liters
= 2 * 2.4 liters
m = 4.8 liters
water , w = 3x liters
= 3 * 2.4 liters
w = 7.2 liters
That is 4.8 liters of milk and 7.2 liters of water.
Now we are replacing the mixture with pure milk so that the amount of milk and water in the mixture is 50% and 50%.
That is we will end up with 6 liters of milk and 6 liters of water. Water gets reduced by 1.2 liters.
To remove 1.2 liters of water from the original mixture containing 60% water,
we need to remove 1.2 / 0.6 liters of the mixture = 2 liters.
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172. 48 liters of a mixture has 75% alcohol. How much water must be added to it to get 60% alcohol concentration ? (in liters)

Correct Ans:12
Explanation:
Solution is
Given In 48 litres => Alcohol = 75 %
=> Alcohol (in litres) = ( 75 / 100 ) x 48
= 36000 / 100
= 36 litres
Let x litres of water is added to this mixture to get 60 % alcohol concentration
So Total quantity of new mixture = ( 48 + x ) litres

=> 60 = 36 / ( 48 + x ) * 100
=> 60 ( 48 + x ) = 36 * 100
=> 48 + x = 60
=> x = 60 - 48
=> x = 12 litres
Therefore quantity of water added to get 60 % alcohol concentration = 12 litres
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173. 17 liters of mixture has 80% milk. How much milk should be added to the mixture to make it 90% pure ?  (in liters)

Correct Ans:17
Explanation:
Solution is
In mixture, concentration of milk = 80 %
In milk, concentration of milk = 100%

Ratio is 1 : 1
Hence we need to add 17 liters of milk to the 17 liters of mixture.
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174. If the average income of a family of ‘x’ members is Rs. 25000 while average income of another family of 6 members is Rs. 32000, then find the value of ‘x’ if the average income of both families is Rs. 28000

Correct Ans:8
Explanation:
Given
Avg income of family one = 25
Avg income of family two = 32
Avg income of both the families = 28

32 - 28 = 4 ; 28 - 25 = 3
Required ratio is 4 : 3
Ratio of the number members in family 1 and 2 is 4 : 3
2nd family there are 6 members => 3x = 6
=> x = 2
In family 1 the, no.of people = 4x
= 4 x 2
= 8
there should be 8 people in the first family
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175. Two liquids A and B are mixed together in the ratio 2 : 3. The average cost of liquid B is Rs 30 per liter and the average cost of the mixture is Rs. 25 per liter, then find the average cost of liquid A per liter.

Correct Ans:17.5
Explanation:
Solution is
Given liquids A and B = 2 : 3
Average cost of mixture = Rs. 25 / liter
Average cost of liquid B = Rs. 30 / liter
Let Average cost of liquid A = x per liter

According to the alligation equation,
( 30 - 25 ) / ( 25 - x ) = 2 / 3
=> 5 / ( 25 - x ) = 2 / 3
=> 5 x 3 / 2 = ( 25 - x )
=> 15 / 2 = 25 - x
=> 7.5 = 25 - x
=> x = 25 - 7.5
x = 17.5
So, Average cost of liquid A =17.5 per liter
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176. How many kgs of Basmati rice costing Rs.42/kg should a shopkeeper mix with 25 kgs of ordinary rice costing Rs.24 per kg so that he makes a profit of 25% on selling the mixture at Rs.40/kg?

Correct Ans:20
Explanation:
Let the amount of Basmati rice being mixed be x kgs. As the trader makes 25% profit by selling the mixture at Rs.40/kg, his cost /kg of the mixture = Rs.32/kg. i.e. (x * 42) + (25 * 24) = 32 (x + 25) => 42x + 600 = 32x + 800 => 10x = 200 or x = 20 kgs.
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177. Two liquids A and B are mixed together in the ratio 1 : 3. The average cost of liquid B is Rs 30 per liter and the average cost of the mixture is Rs. 25 per liter, then find the average cost of liquid A per liter.

Correct Ans:10
Explanation:
Solution is
Given liquids A and B = 2 : 3
Average cost of mixture = Rs. 25 / liter
Average cost of liquid B = Rs. 30 / liter
Let Average cost of liquid A = x per liter

According to the alligation equation,
( 30 - 25 ) / ( 25 - x ) = 2 / 3
=> 5 / ( 25 - x ) = 2 / 3
=> 5 x 3 / 2 = ( 25 - x )
=> 15 / 2 = 25 - x
=> 7.5 = 25 - x
=> x = 25 - 7.5
x = 17.5
So, Average cost of liquid A =17.5 per liter
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178. Two liquids A and B are mixed together in the ratio 2 : 3. The average cost of liquid B is Rs 30 per liter and the average cost of the mixture is Rs. 25 per liter, then find the average cost of liquid A per liter.

Correct Ans:17.5
Explanation:
Solution is
Given liquids A and B = 2 : 3
Average cost of mixture = Rs. 25 / liter
Average cost of liquid B = Rs. 30 / liter
Let Average cost of liquid A = x per liter

According to the alligation equation,
( 30 - 25 ) / ( 25 - x ) = 2 / 3
=> 5 / ( 25 - x ) = 2 / 3
=> 5 x 3 / 2 = ( 25 - x )
=> 15 / 2 = 25 - x
=> 7.5 = 25 - x
=> x = 25 - 7.5
x = 17.5
So, Average cost of liquid A =17.5 per liter
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179. How many liters of water should be added to a 30 liter mixture containing milk and water in the ratio 7:3 such that the resultant mixture has 40 % water in it

Correct Ans:5
Explanation:
Solution is
Given
In 30 litres of mixture, milk and water ratio is7 : 3
Let m = milk ; w = water
=> m / w = 7 / 3 = 7x liters / 3x litres
=> 7x + 3x =30
=> 10x =30
=> x = 3
m= 7x litres = 21 litres
w= 3x litres = 9 litres
When we add x litres of water the resulting solution contains 21 litres of milk and (9+x) litres of water
Total quantity = 30 + x
Given , percentage of water in this new mixture =40%
i.e 40% of new mixture =water
=> 40/100(30 + x) =9 + x
=> (2/5) (30 + x) = (9 +x)
=> 2(30 + x) = 5 (9 +x)
=> 60 + 2x = 45 + 5x
=> 5x - 2x = 60 - 45 => 3x= 15 => x=5
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180. How many liters of water should be added to a 30 liter mixture of milk and water containing milk and water in the ratio 7:3 such that the resultant mixture has 40 % water in it.

Correct Ans:5
Explanation:
Given :30 Liters of mixture, Milk and water in the ratio 7 : 3 Which means, we have 21 liters of milk and 9 liters of water.
We add water the resulting solution is 21 liters of milk and 9 + x liters of water.
Total quantity = 30 +x.
Water percentage is 40 % = > 40 x (30+x)/100 = 9 + x 4(30+x) = 10(9+x) => 120 + 4x = 90 + 10x => 10x ? 6x = 120-90 6x = 120 ? 90 => 6x = 30 => x = 5
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