1. A rectangular plot has a length of 26 units, and breadth of 14 units. Find the area of the plot ?
SHOW ANSWER
Correct Ans:364
Explanation:
Area of Rectangle = length x breadth
26 x 14= 364
2. For a rectangle length is 26 units, and breadth is 11 units. Can you find its area ?
SHOW ANSWER
Correct Ans:286
Explanation:
Area of Rectangle = length x breadth
26 x 11= 286
3. Given rectangle of length 26 units, and breadth of 8 units. Compute its area ?
SHOW ANSWER
Correct Ans:208
Explanation:
Area of Rectangle = length x breadth
26 x 8= 208
4. A farmer has a square shaped field whose sides measure 56m each. In the middle of his field, he has a Square shaped room (each side measuring 50m). It costs Rs.50 to plough per Sq.m. Find the total cost to plough?
SHOW ANSWER
Correct Ans:31800
Explanation:
Let the side of bigger Square be x and side of smaller square be y. Then area between them = x^2 - y ^2
Substituting x = 56m and y = 50 we get the required area = 56^2 - 50^2 = (56+50) x (56-50) (using a^2-b^2 formulae)
= (106) x (6) = 636
Price = Area x Price per Sq.m = 636 x 50 = 31800
5. A farmer has a square shaped field whose sides measure 48m each. In the middle of his field, he has a Square shaped room (each side measuring 42m). Find the Total Area he can plough ?
SHOW ANSWER
Correct Ans:540
Explanation:
Let the side of bigger Square be x and side of smaller square be y. Then area between them = x^2 - y ^2
Substituting x = 48m and y = 42 we get the required land which can be Ploughed = 48^2 - 42^2 = (48+42) x (48-42) (using a^2-b^2 formulae)
= (90) x (6) = 540
6. A farmer has a square shaped field whose sides measure 40m each. In the middle of his field, he has a Square shaped room (each side measuring 34m) Find the area of cultivable land?
SHOW ANSWER
Correct Ans:444
Explanation:
Let the side of bigger Square be x and side of smaller square be y. Then area between them = x^2 - y ^2
Substituting x = 40m and y = 34 we get the required cultivable land = 40^2 - 34^2 = (40+34) x (40-34) (using a^2-b^2 formulae)
= (74) x (6) = 444
7. A Big Square shaped hall (each side measuring 50m) needs to be fitted with carpet in such a way that there is 2 m even gap between carpet and the walls of the hall. If one Sq.m of carpet costs Rs.44 , find the overall cost required to fit the carpet ?
SHOW ANSWER
Correct Ans:93104
Explanation:
Side of the Carpet =46 {50 - (2 x 2 m)} by eliminating 2m of length at the top and another 2m of length at the bottom from the bigger Square
Area of the Carpet = 46^2 =2116
Price = Area x Price per Sq.m = 2116 x 44 = 93104
8. A Big Square shaped hall (each side measuring 55m) needs to be fitted with carpet in such a way that there is 1 m even gap between carpet and the walls of the hall. Find the overall area of the carpet ?
SHOW ANSWER
Correct Ans:2809
Explanation:
Side of the Carpet =53 {55 - (2 x 1 m)} by eliminating 1m of length at the top and another 1m of length at the bottom from the bigger Square
Area of the Carpet = 53^2 =2809
9. One side of a Square shaped park measures 35m. Walking path measuring 1m needs to be formed along the interior sides of the park. The inner square needs to be ploughed and the charges are Rs.29 per Sq.m. Find the cost required for ploughing?
SHOW ANSWER
Correct Ans:31581
Explanation:
Side of the inner square =33 {35 - (2 x 1 m)} by eliminating 1m of length at the top and another 1m of length at the bottom from the bigger Square
Area of the Inner Square = 33^2 =1089
Price = Area x Price per Sq.m = 1089 x 29 = 31581
10. One side of a Square shaped park measures 40m. Walking path measuring 1m needs to be formed along the interior sides of the park. It cost Rs. 34 per Sq.m to lay walking tiles. Estimate the total amount Required ?
SHOW ANSWER
Correct Ans:5304
Explanation:
Let the side of bigger Square be x and side of smaller square be y. Then area between them = x^2 - y ^2
Substituting x = 40m and y = 38 {40 - (2 x 1 m)} by eliminating 1m of length at the top and another 1m of length at the bottom
We get the required area = 40^2 - 38^2 = (40+38) x (40-38) (using a^2-b^2 formulae)
= (78) x (2) = 156
Price = Area * Per unit Cost = 156 x 34 = 5304
11. One side of a Square shaped park measures 65m. Walking path measuring 1m needs to be formed along the interior sides of the park. Find the area of the inner Square?
SHOW ANSWER
Correct Ans:3969
Explanation:
Side of the inner square =63 {65 - (2 x 1 m)} by eliminating 1m of length at the top and another 1m of length at the bottom from the bigger Square
Area of the Inner Square = 63^2 =3969
12. One side of a Square shaped park measures 35m. Walking path measuring 1m needs to be formed along the interior sides of the park. Find the area of the walking path ?
SHOW ANSWER
Correct Ans:136
Explanation:
Let the side of bigger Square be x and side of smaller square be y. Then area between them = x^2 - y ^2
Substituting x = 35m and y = 33 {35 -(2 x 1 m)} by eliminating 1m of length at the top and another 1m of length at the bottom
- ) we get the required area = 35^2 - 33^2 = (35+33)x(35-33)
= (68) x (2) = 136
13. Each side of a Square shaped park measures. 35m. A Square shaped garden inside the park, measures 29m. Can you find the area in between them ?
SHOW ANSWER
Correct Ans:384
Explanation:
Let the side of bigger Square be x and side of smaller square be y. Then area between them = x^2 - y ^2
Substituting x = 35m and y = 29 we get the required area = 35^2 - 29^2 = (35+29)x(35-29)
= (64) x (6) = 384
14. Given a Square whose sides measure 70m. Another Square measuring 64 is placed inside the bigger Square. Calculate the area between them ?
SHOW ANSWER
Correct Ans:804
Explanation:
Let the side of bigger Square be x and side of smaller square be y. Then area between them = x^2 - y ^2
Substituting x = 70m and y = 64 we get the required area = 70^2 - 64^2 = (70+64)x(70-64)
= (134) x (6) = 804
15. A farmer has a square shaped field whose sides measure 51m each. In the middle of his field, he has a Square shaped room (each side measuring 46m). It costs Rs.46 to plough per Sq.m. Find the total cost to plough?
SHOW ANSWER
Correct Ans:22310
Explanation:
Let the side of bigger Square be x and side of smaller square be y. Then area between them = x^2 - y ^2
Substituting x = 51m and y = 46 we get the required area = 51^2 - 46^2 = (51+46) x (51-46) (using a^2-b^2 formulae)
= (97) x (5) = 485
Price = Area x Price per Sq.m = 485 x 46 = 22310
16. A farmer has a square shaped field whose sides measure 43m each. In the middle of his field, he has a Square shaped room (each side measuring 38m). Find the Total Area he can plough ?
SHOW ANSWER
Correct Ans:405
Explanation:
Let the side of bigger Square be x and side of smaller square be y. Then area between them = x^2 - y ^2
Substituting x = 43m and y = 38 we get the required land which can be Ploughed = 43^2 - 38^2 = (43+38) x (43-38) (using a^2-b^2 formulae)
= (81) x (5) = 405
17. A farmer has a square shaped field whose sides measure 35m each. In the middle of his field, he has a Square shaped room (each side measuring 30m) Find the area of cultivable land?
SHOW ANSWER
Correct Ans:325
Explanation:
Let the side of bigger Square be x and side of smaller square be y. Then area between them = x^2 - y ^2
Substituting x = 35m and y = 30 we get the required cultivable land = 35^2 - 30^2 = (35+30) x (35-30) (using a^2-b^2 formulae)
= (65) x (5) = 325
18. A Big Square shaped hall (each side measuring 45m) needs to be fitted with carpet in such a way that there is 2 m even gap between carpet and the walls of the hall. If one Sq.m of carpet costs Rs.40 , find the overall cost required to fit the carpet ?
SHOW ANSWER
Correct Ans:67240
Explanation:
Side of the Carpet =41 {45 - (2 x 2 m)} by eliminating 2m of length at the top and another 2m of length at the bottom from the bigger Square
Area of the Carpet = 41^2 =1681
Price = Area x Price per Sq.m = 1681 x 40 = 67240
19. A Big Square shaped hall (each side measuring 50m) needs to be fitted with carpet in such a way that there is 1 m even gap between carpet and the walls of the hall. Find the overall area of the carpet ?
SHOW ANSWER
Correct Ans:2304
Explanation:
Side of the Carpet
=> 48 {50 - (2 x 1 m)} by eliminating 1m of length at the top and another 1m of length at the bottom from the bigger Square
Area of the Carpet =>side * side
=> 48 * 48
=> 2304
Area of carpet =2304.
20. One side of a Square shaped park measures 30m. Walking path measuring 1m needs to be formed along the interior sides of the park. The inner square needs to be ploughed and the charges are Rs.25 per Sq.m. Find the cost required for ploughing?
SHOW ANSWER
Correct Ans:19600
Explanation:
Side of the inner square =28 {30 - (2 x 1 m)} by eliminating 1m of length at the top and another 1m of length at the bottom from the bigger Square
Area of the Inner Square = 28^2 =784
Price = Area x Price per Sq.m = 784 x 25 = 19600
Are you seeking for good platform for practicing Mensuration questions in online. This is the right place. The time you spent in Fresherslive will be the most beneficial one for you.
Online Test on Mensuration @ Fresherslive
This page provides important questions on Mensuration along with correct answers and clear explanation, which will be very useful for various Interviews, Competitive examinations and Entrance tests. Here, Most of the Mensuration questions are framed with Latest concepts, so that you may get updated through these Mensuration Online tests. Mensuration Online Test questions are granted from basic level to complex level.
Why To Practice Mensuration Test questions Online @ Fresherslive?
Mensuration questions are delivered with accurate answer. For solving each and every question, very lucid explanations are provided with diagrams wherever necessary.
Practice in advance of similar questions on Mensuration may improve your performance in the real Exams and Interview.
Time Management for answering the Mensuration questions quickly is foremost important for success in Competitive Exams and Placement Interviews.
Through Fresherslive Mensuration questions and answers, you can acquire all the essential idea to solve any difficult questions on Mensuration in short time and also in short cut method.
Winners are those who can use the simplest method for solving a question. So that they have enough time for solving all the questions in examination, correctly without any tense. Fresherslive provides most simplest methods to answer any tough questions. Practise through Fresherslive test series to ensure success in all competitive exams, entrance exams and placement tests.
Why Fresherslive For Mensuration Online Test Preparation?
Most of the job seekers finding it hard to clear Mensuration test or get stuck on any particular question, our Mensuration test sections will help you to success in Exams as well as Interviews. To acquire clear understanding of Mensuration, exercise these advanced Mensuration questions with answers.
You're Welcome to use the Fresherslive Online Test at any time you want. Start your beginning, of anything you want by using our sample Mensuration Online Test and create yourself a successful one. Fresherslive provides you a new opportunity to improve yourself. Take it and make use of it to the fullest. GOODLUCK for Your Bright Future.