# Geometry Questions and Answers updated daily – Aptitude

Geometry Questions: Solved 321 Geometry Questions and answers section with explanation for various online exam preparation, various interviews, Aptitude Category online test. Category Questions section with detailed description, explanation will help you to master the topic.

## Geometry Questions

61. Find the circumference of the semicircle of radius 7.

SHOW ANSWER

Correct Ans:22

Explanation:

Given, radius, r = 7

=> (22/7) * 7

= 22

**Circumference of the semicircle = pi * r**=> (22/7) * 7

= 22

**Thus,****Circumference of the semicircle = 22**
Workspace

62. Find the area of the sector which makes 90 degree at the center for the circle with radius 14 cm

SHOW ANSWER

Correct Ans:154

Explanation:

Given, Ø = 90 deg

= (90 /360) * (22/7) * 14 * 14

= 22 * 7

= 154 cm^2

**Area of sector = (Ø / 360 ) * pi * r^2**= (90 /360) * (22/7) * 14 * 14

= 22 * 7

= 154 cm^2

**Thus, Area of sector = 154 cm^2**
Workspace

63. Find the circumference of the semicircle of radius 2.

SHOW ANSWER

Correct Ans:6.29

Explanation:

Given, radius = 2

= (22/7) * 2

= 6.29

**Circumference of semicircle = pi * r**= (22/7) * 2

= 6.29

**Therefore, Circumference of semicircle = 6.29**
Workspace

64. Find the circumference of the semicircle of radius 21.

SHOW ANSWER

Correct Ans:66

Explanation:

Given, radius = 21

= (22/7) * 21

= 66

Thus,

**Circumference of semicircle = pi * r**= (22/7) * 21

= 66

Thus,

**Circumference of semicircle = 66**
Workspace

65. If the ratio of areas of two circles are 16 : 25, then the ratio of the radii of the circle will be

SHOW ANSWER

Correct Ans:(4 : 5)

Explanation:

Let r1 be the radius of one of the circle and

r2 be the radius of another circle.

Given, ratio of areas of two circles = 16 : 25

=> [pi * (r1)^2] : [pi * (r2)^2] = 16 : 25

=> r1 : r2 = sqrt(16) : srt(25)

=>

r2 be the radius of another circle.

Given, ratio of areas of two circles = 16 : 25

=> [pi * (r1)^2] : [pi * (r2)^2] = 16 : 25

=> r1 : r2 = sqrt(16) : srt(25)

=>

**r1 : r2 = 4 : 5**
Workspace

66. Find the circumference of the semicircle of radius 14.

SHOW ANSWER

Correct Ans:44

Explanation:

Given, radius of semicircle = 14

= (22/7) * 14

= 44

**Circumference of semicircle = pi * r**= (22/7) * 14

= 44

**Thus, Circumference of semicircle = 44**
Workspace

67. Find the area of trapezium whose length of the parallel sides are 12 and 28 cm. If the distance between the parallel sides are given by 25 cm, then the area of the trapezium is

SHOW ANSWER

Correct Ans:500

Explanation:

Workspace

68. Two circles of radius 3 cm and 4 cm, are drawn in such a way that they touch each other exactly at one point. A and B are two points on these two circles. If AB denotes the distance between them, then the maximum value of AB can be

SHOW ANSWER

Correct Ans:16

Explanation:

Workspace

69. A wire in the form of a circle of radius 3.5 m is bent in the form of a rectangle, whose length and breadth are in the ratio of 6 : 5. What is the area of the rectangle?

SHOW ANSWER

Correct Ans:30

Explanation:

Given, circle of radius (r) = 3.5 m

The circular wire is bent to form rectangle, which means

= 2 * (22/7) * 3.5

= 22

=>

Given, length and breadth are in the ratio of 6 : 5

=> length = 6x meters and breadth = 5x meters.

=> 11x = 11

Then, length = 6x meters = 6 meters

and breadth = 5x meters = 5 meters

= 6 X 5

= 30

Therefore,

The circular wire is bent to form rectangle, which means

**Circumference of circle = perimeter of rectangle****Circumference of circle = 2 * pi * r**= 2 * (22/7) * 3.5

= 22

=>

**perimeter of rectangle = 22****=> 2(length + breadth) = 22**Given, length and breadth are in the ratio of 6 : 5

=> length = 6x meters and breadth = 5x meters.

**=> 2(6x + 5x) = 22**=> 11x = 11

**=> x = 1**Then, length = 6x meters = 6 meters

and breadth = 5x meters = 5 meters

**Area of rectangle = length X breadth**= 6 X 5

= 30

Therefore,

**Area of rectangle = 30 meters**
Workspace

70. Find the area of trapezium whose parallel sides are 20 cm and 18 cm long, and the distance between them is 15 cm

SHOW ANSWER

Correct Ans:285

Explanation:

Workspace

71.

A trapezium has a height of 5 cm and parallel sides of length 3 cm and 7 cm respectively. area of trapezium should be

SHOW ANSWER

Correct Ans:25

Explanation:

Workspace

72. Find the area of the circle with equation x^2 + y^2 = 12

SHOW ANSWER

Correct Ans:12pi

Explanation:

Given, equation of circle is: x^2 + y^2 = 12

The center-radius form of the circle equation is in the format

=> x^2 + y^2 = 12

=> (x – 0)^2 + (y – 0)^2 = 12

On comparing this eqn with the standard one: =>

Thus,

= pi * 12

The center-radius form of the circle equation is in the format

**(**, with the center being at the point(*x*–*h*)^{2}+ (*y*–*k*)^{2}=*r*^{2}*h, k*)and the radius being "*r*".=> x^2 + y^2 = 12

=> (x – 0)^2 + (y – 0)^2 = 12

On comparing this eqn with the standard one: =>

**(***x*–*h*)^{2}+ (*y*–*k*)^{2}=*r*^{2}Thus,

**r^2 = 12****Area of circle = pi * r^2**= pi * 12

**= 12 pi****Thus, Area of circle = 12 pi**
Workspace

73. A circle of radius 7 units, make 3 complete revolutions. Find the distance it have covered?

SHOW ANSWER

Correct Ans:132

Explanation:

Given, radius of the circle = 7 units

= 2 * (22/7) * 7 * 3

= 2 * 22 * 3

**Distance covered = circumference of the circle * 3****= 2 * pi * r * 3**= 2 * (22/7) * 7 * 3

= 2 * 22 * 3

**= 132****Therefore, Distance covered = 132**
Workspace

74. Find the area of the circle whose coordinates are (2,3) , (7,1) and (3,5)

SHOW ANSWER

Correct Ans:6

Explanation:

Workspace

75. In a triangle ABC, a circle which touches the edges of all three sides is called

SHOW ANSWER

Correct Ans:in circle

Explanation:

Workspace

76. In a triangle a circle passes through the vertices of the triangle, then the circle is called as

SHOW ANSWER

Correct Ans:cirumcircle

Explanation:

Workspace

77. In triangle ABC of sides a,b and c, the area of the triangle is

SHOW ANSWER

Correct Ans:(bc sin A)/2

Explanation:

Workspace

78. Find the 25 % of sum of all the exterior angles of a cylic quadrilateral.

SHOW ANSWER

Correct Ans:90

Explanation:

Workspace

79. Which of these following points lie on the circle x^2 + y^2 = 25

SHOW ANSWER

Correct Ans:(1,sqrt(24))

Explanation:

Workspace

80. Find the center of the circle whose end points of the diameters are (2,10) and (6,2).

SHOW ANSWER

Correct Ans:(4,6)

Explanation:

Workspace

Are you seeking for good platform for practicing Geometry questions in online. This is the right place. The time you spent in Fresherslive will be the most beneficial one for you.

## Online Test on Geometry @ Fresherslive

This page provides important questions on Geometry along with correct answers and clear explanation, which will be very useful for various Interviews, Competitive examinations and Entrance tests. Here, Most of the Geometry questions are framed with Latest concepts, so that you may get updated through these Geometry Online tests. Geometry Online Test questions are granted from basic level to complex level.

## Why To Practice Geometry Test questions Online @ Fresherslive?

Geometry questions are delivered with accurate answer. For solving each and every question, very lucid explanations are provided with diagrams wherever necessary.

Practice in advance of similar questions on Geometry may improve your performance in the real Exams and Interview.

Time Management for answering the Geometry questions quickly is foremost important for success in Competitive Exams and Placement Interviews.

Through Fresherslive Geometry questions and answers, you can acquire all the essential idea to solve any difficult questions on Geometry in short time and also in short cut method.

Winners are those who can use the simplest method for solving a question. So that they have enough time for solving all the questions in examination, correctly without any tense. Fresherslive provides most simplest methods to answer any tough questions. Practise through Fresherslive test series to ensure success in all competitive exams, entrance exams and placement tests.

## Why Fresherslive For Geometry Online Test Preparation?

Most of the job seekers finding it hard to clear Geometry test or get stuck on any particular question, our Geometry test sections will help you to success in Exams as well as Interviews. To acquire clear understanding of Geometry, exercise these advanced Geometry questions with answers.

You're Welcome to use the Fresherslive Online Test at any time you want. Start your beginning, of anything you want by using our sample Geometry Online Test and create yourself a successful one. Fresherslive provides you a new opportunity to improve yourself. Take it and make use of it to the fullest. GOODLUCK for Your Bright Future.