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Compound Interest Questions
121. What would be the compound interest accrued on an amount of 10000 Rs. at the end of 2 years at the rate of 4 % per annum ?
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Correct Ans:816
Explanation:
Given principal = 10000 No. of years = 2 Rate of interest = 4
Amount = P x (1+r/100)^n, we get Amount = 10000 x (1+4/100)^2 = 10816
C.I = Amount - Principal = 10816 - 10000 = 816
C.I = Amount - Principal = 10816 - 10000 = 816
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122. What would be the compound interest accrued on an amount of 6250 Rs. at the end of 2 years at the rate of 8 % per annum?
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Correct Ans:1040
Explanation:
Given principal = 6250 No. of years = 2 Rate of interest = 8
Amount = P x (1+r/100)^n, we get Amount = 6250 x (1+8/100)^2 = 7290
C.I = Amount - Principal = 7290 - 6250 = 1040
C.I = Amount - Principal = 7290 - 6250 = 1040
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123. What would be the compound interest accrued on an amount of 6500 Rs. at the end of 2 years at the rate of 15 % per annum?
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Correct Ans:2096.25
Explanation:
Given principal = 6500 No. of years = 2 Rate of interest = 15
Amount = P x (1+r/100)^n, we get Amount = 6500 x (1+15/100)^2 = 8596.25
C.I = Amount - Principal = 8596.25 - 6500 = 2096.25
C.I = Amount - Principal = 8596.25 - 6500 = 2096.25
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124. What would be the compound interest accrued on an amount of 5000 Rs. at the end of 2 years at the rate of 9 % per annum?
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Correct Ans:940.5
Explanation:
Given
Principal = 5000 No. of years = 2 Rate of interest = 9
Amount = P x (1+r/100)^n,
we get Amount
= 5000 x (1+9/100)^2
= 5940.5
C.I = Amount - Principal
= 5940.5 - 5000
= 940.5.
Principal = 5000 No. of years = 2 Rate of interest = 9
Amount = P x (1+r/100)^n,
we get Amount
= 5000 x (1+9/100)^2
= 5940.5
C.I = Amount - Principal
= 5940.5 - 5000
= 940.5.
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125. What would be the compound interest obtained on an amount of Rs. 12,500 Rs. at the end of 3 years at the rate of 10% per annum?
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Correct Ans:4137.5
Explanation:
Given principal = 12500 No. of years = 3 Rate of interest = 10 Amount = P x (1+r/100)^n, we get Amount = 12500 x (1+10/100)^3 = 16637.5
C.I = Amount - Principal = 16637.5 - 12500 = 4137.5
C.I = Amount - Principal = 16637.5 - 12500 = 4137.5
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126. What would be the compound interest accrued on an amount of 14000 Rs. at the end of 3 years at the rate of 5 % per annum?
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Correct Ans:2206.75
Explanation:
Given
Principal = 14000 No. of years = 3 Rate of interest = 5
Amount = P x (1+r/100)^n,
we get Amount = 14000 x (1+5/100)^3 = 16206.75
C.I = Amount - Principal
= 16206.75 - 14000 = 2206.75.
Principal = 14000 No. of years = 3 Rate of interest = 5
Amount = P x (1+r/100)^n,
we get Amount = 14000 x (1+5/100)^3 = 16206.75
C.I = Amount - Principal
= 16206.75 - 14000 = 2206.75.
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127. John invested an amount of Rs. 20000 for 2 years at compound interest at the rate of 6 % per annum. Find the amount he receives at the end of 2 years.
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Correct Ans:22472
Explanation:
Given
Principal : P = 20000 Rs. Rate of Interest : r = 6 % Number of years : n = 2
Amount = P x (1 + r/100) ^ n
Amount = 20000 x (1+6/100)^2
= 20000 x (1+3/50)^2
= 20000 x (53/50) x (53/50)
= 22472.
Principal : P = 20000 Rs. Rate of Interest : r = 6 % Number of years : n = 2
Amount = P x (1 + r/100) ^ n
Amount = 20000 x (1+6/100)^2
= 20000 x (1+3/50)^2
= 20000 x (53/50) x (53/50)
= 22472.
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128. Rs. 10000 is borrowed at compound interest at the rate of 4 % annum. What will be the amount to be paid after 2 years?
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Correct Ans:10816
Explanation:
Principal : P = 10000 Rs. Rate of Interest : r = 4 % Number of years : n = 2
Amount = P x (1 + r/100)^n Amount = 10000 x (1+4/100)^2 =10000 x (1+1/25)^2
=10000 x (26/25) x (26/25) =10816
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129. What would be the compound interest accrued on an amount of 5000 Rs. at the end of 2 years at the rate of 9 % per annum ?
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Correct Ans:940.5
Explanation:
Given principal = 5000
No. of years = 2
Rate of interest = 9
Amount = P x (1+r/100)^n, we get Amount = 5000 x (1+9/100)^2 = 5000 x (109/100) x (109/100) = 5940.5
Compound Interest, C. I = Amount - Principal = 5940.5 - 5000 = 940.5
Amount = P x (1+r/100)^n, we get Amount = 5000 x (1+9/100)^2 = 5000 x (109/100) x (109/100) = 5940.5
Compound Interest, C. I = Amount - Principal = 5940.5 - 5000 = 940.5
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130. What would be the compound interest accrued on an amount of 12500 Rs. at the end of 3 years at the rate of 10 % per annum ?
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Correct Ans:4137.5
Explanation:
Given principal = 12500
No. of years = 3
Rate of interest = 10
Amount = P x (1+r/100)^n, we get Amount = 12500 x (1+10/100)^3 = 12500 x (11/10)^3 = 12500 x (11/10)x (11/10)x (11/10) = 16637.5
Compound Interest, C. I = Amount - Principal = 16637.5 - 12500 = 4137.5
Amount = P x (1+r/100)^n, we get Amount = 12500 x (1+10/100)^3 = 12500 x (11/10)^3 = 12500 x (11/10)x (11/10)x (11/10) = 16637.5
Compound Interest, C. I = Amount - Principal = 16637.5 - 12500 = 4137.5
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131. What would be the compound interest accrued on an amount of 14000 Rs. at the end of 3 years at the rate of 5 % per annum ?
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Correct Ans:2206.75
Explanation:
Given principal = 14000
No. of years = 3
Rate of interest = 5 %
Amount = P x (1+r/100)^n, we get Amount = 14000 x (1+5/100)^3 = 14000 x (1 + 1/20)^3 = 14000 x (21/20)^3 = 14000 x (21/20) x (21/20) x (21/20) = 16206.75
Compound Interest = Amount - Principal = 16206.75 - 14000 = 2206.75
Amount = P x (1+r/100)^n, we get Amount = 14000 x (1+5/100)^3 = 14000 x (1 + 1/20)^3 = 14000 x (21/20)^3 = 14000 x (21/20) x (21/20) x (21/20) = 16206.75
Compound Interest = Amount - Principal = 16206.75 - 14000 = 2206.75
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132. John invested an amount of Rs. 20000 for 2 years at compound interest at the rate of 6 % per annum. Find the amount he receives at the end of 2 years.
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Correct Ans:22472
Explanation:
Principal : P = 20000 Rs. Rate of Interest : r = 6 % Number of years : n = 2
Amount = P x (1 + r/100)^n
=> Amount = 20000 x (1+6/100)^2
= 20000 x (1+3/50)^2
= 20000 x (53/50) x (53/50)
= 22472
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133. Rs. 10000 is borrowed at compound interest at the rate of 4 % annum. What will be the amount to be paid after 2 years ?
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Correct Ans:10816
Explanation:
Principal : P = 10000 Rs.
Rate of Interest : r = 4 %
Number of years : n = 2
Amount = P x (1 + r/100)^n
Amount = 10000 x (1+4/100)^2
=10000 x (1+1/25)^2
=10000 x (26/25) x (26/25) =10816
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134. Find the simple interest on Rs. 2000 at 7 % per annum for 4 years
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Correct Ans:560 Rs.
Explanation:
Solution is :
Given
Principal : 2000
Rate of interest : 7
Number of years : 4
Simple Interest = pnr / 100
= ( 2000 x 4 x 7 ) / 100
=560 Rs
Given
Principal : 2000
Rate of interest : 7
Number of years : 4
Simple Interest = pnr / 100
= ( 2000 x 4 x 7 ) / 100
=560 Rs
Workspace
135. What would be the compound interest accrued on an amount of 10000 Rs. at the end of 2 years at the rate of 4 % per annum ?
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Correct Ans:816
Explanation:
Solution is :
Given principal = 10000
No. of years = 2
Rate of interest = 4
Amount = P [ 1 + ( r / 100 )n]
= 10000 x [ 1 +( 4 / 100 )2]
= 10000 x ( 104 / 100 )2
= 10000 x ( 104 / 100 ) x ( 104 / 100 )
= 104 x 104
= 10816
Compound Interest = Amount - Principal
= 10816 - 10000
= 816 Rs
Given principal = 10000
No. of years = 2
Rate of interest = 4
Amount = P [ 1 + ( r / 100 )n]
= 10000 x [ 1 +( 4 / 100 )2]
= 10000 x ( 104 / 100 )2
= 10000 x ( 104 / 100 ) x ( 104 / 100 )
= 104 x 104
= 10816
Compound Interest = Amount - Principal
= 10816 - 10000
= 816 Rs
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136. A person receives a sum of Rs. 2100 as interest for investing some amount at 10% p.a compounding annually for 2 years. Find the amount invested at the beginning
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Correct Ans:10000
Explanation:
Solution is :
Given Compound Interest = Rs.2100
Rate of Interest ( r ) = 10 % p.a
No.of years ( n ) = 2
To find , amount received at the beginning => principal
Compound Interest = P [ 1 + ( r / 100 )n- 1 ]
=> 2100 = P[ 1 + ( 10 / 100 )2- 1 ]
=> 2100 = P[ 1 + ( 1 / 10 )2- 1 ]
=> 2100 = P[ ( 11 / 10 )2- 1 ]
=> 2100 = P[ ( 121 / 100 ) - 1 ]
=> 2100 = P[ 21 / 100 ]
=> 2100 x ( 100 / 21 ) = P
Principal = Rs. 10000
Amount invested at the beginning = Rs. 10000
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137. What would be the compound interest accrued on an amount of 6500 Rs. at the end of 2 years at the rate of 15 % per annum ?
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Correct Ans:2096.25
Explanation:
Solution is :
Given principal = 6500
No. of years = 2
Rate of interest = 15
Amount = P [ 1 + ( r / 100 )n]
= 6500 x [ 1 + ( 15 /100 )2]
= 6500 x [ 1 + ( 3 / 20 )2]
= 6500 x [ 23 / 20 ]2
= 6500 x [ 529 / 400 ]
Amount =8596.25
Compound Interest = Amount - Principal
= 8596.25 - 6500
= 2096.25
Given principal = 6500
No. of years = 2
Rate of interest = 15
Amount = P [ 1 + ( r / 100 )n]
= 6500 x [ 1 + ( 15 /100 )2]
= 6500 x [ 1 + ( 3 / 20 )2]
= 6500 x [ 23 / 20 ]2
= 6500 x [ 529 / 400 ]
Amount =8596.25
Compound Interest = Amount - Principal
= 8596.25 - 6500
= 2096.25
Workspace
138. What would be the compound interest accrued on an amount of 4500 Rs. at the end of 2 years at the rate of 10 % per annum ?
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Correct Ans:945
Explanation:
Solution is :
Given principal = 4500
No. of years = 2
Rate of interest = 10
Amount = P [ 1 + ( r / 100 ) ]n
= 4500 x [ 1 + ( 10 / 100 ) ]2
= 4500 x [ 1 + ( 1 / 10 ) ]2
= 4500 x [ 11 / 10 ]2
= 4500 x [ 121 / 100 ]
Amount = 5445
Compound interest = Amount - principal
= 5445 - 4500
= 945 Rs
Ans is 945
Given principal = 4500
No. of years = 2
Rate of interest = 10
Amount = P [ 1 + ( r / 100 ) ]n
= 4500 x [ 1 + ( 10 / 100 ) ]2
= 4500 x [ 1 + ( 1 / 10 ) ]2
= 4500 x [ 11 / 10 ]2
= 4500 x [ 121 / 100 ]
Amount = 5445
Compound interest = Amount - principal
= 5445 - 4500
= 945 Rs
Ans is 945
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139. Find the simple interest on Rs. 700 at 20 % per annum for 6 years
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Correct Ans:Rs. 840
Explanation:
Solution is :
Given
Principal : 700
Rate of interest : 20
Number of years : 6
Simple Interest = pnr / 100
= ( 700 x 6 x 20 ) / 100
= 7 x 6 x 20
= 840
Given
Principal : 700
Rate of interest : 20
Number of years : 6
Simple Interest = pnr / 100
= ( 700 x 6 x 20 ) / 100
= 7 x 6 x 20
= 840
Workspace
140. What would be the compound interest accrued on an amount of 8000 Rs. at the end of 3 years at the rate of 10 % per annum ?
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Correct Ans:2648
Explanation:
Solution is
Given
principal = 8000
No. of years = 3
Rate of interest = 10
Amount = P x ( 1 + ( r / 100 ) )n
= 8000 x ( 1 + ( 1 / 10 ) )3
= 8000 x ( 11 / 10 )3
= 8000 x ( 1331 / 1000 )
= 8 x 1331
Amount = 10648
Compound Interest = Amount - Principal
= 10648 - 8000
= 2648 Rs
Given
principal = 8000
No. of years = 3
Rate of interest = 10
Amount = P x ( 1 + ( r / 100 ) )n
= 8000 x ( 1 + ( 1 / 10 ) )3
= 8000 x ( 11 / 10 )3
= 8000 x ( 1331 / 1000 )
= 8 x 1331
Amount = 10648
Compound Interest = Amount - Principal
= 10648 - 8000
= 2648 Rs
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