# Compound Interest Questions and Answers updated daily – Aptitude

Compound Interest Questions: Solved 161 Compound Interest Questions and answers section with explanation for various online exam preparation, various interviews, Aptitude Category online test. Category Questions section with detailed description, explanation will help you to master the topic.

## Compound Interest Questions

81. What would be the compound interest accrued on an amount of 8000 Rs. at the end of 3 years at the rate of 10 % per annum ?

Correct Ans:2648
Explanation:
Solution is
Given
principal = 8000
No. of years = 3
Rate of interest = 10
Amount = P x ( 1 + ( r / 100 ) )n
= 8000 x ( 1 + ( 1 / 10 ) )3
= 8000 x ( 11 / 10 )3
= 8000 x ( 1331 / 1000 )
= 8 x 1331
Amount = 10648
Compound Interest = Amount - Principal
= 10648 - 8000
= 2648 Rs

&nb
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82. Find the simple interest on Rs. 1920 at 45 % per annum for 3 months

Correct Ans:Rs. 216
Explanation:
Solution is:
Given
Principal : 1920
Rate of interest : 45
Number of months : 3
Simple interest for 1 year = pnr / 100
= ( 1920 x 1 x 45 ) / 100
= 864
Simple interest for 3 months = ( 3 / 12 ) x SI for 1 year
= ( 3 / 12 ) x 864
= 216
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83. A person receives a sum of Rs. 420 as interest for investing some amount at 10% p.a compounding annually for 2 years. Find the amount invested at the beginning

Correct Ans:2000
Explanation:
Solution is
Given compound interest ( C.I ) = Rs.420
Rate of interest ( r ) = 10 %
Number of years ( n ) = 2
To find , amount invested at the beginning i.e principal (P)
Amount = P [ 1 + ( r / 100 ) ]n
Amount = C.I + P

=> Amount = C.I + P
=> P [ 1 + ( r / 100 ) ]n= C.I + P
=> P [ 1 + ( 10 / 100 ) ]2= 420 + P
=> P [ 110 / 100 ]2= 420 + P
=> P [ 11 / 10 ]2= 420 + P
=> P x 121 / 100 = 420 + P
=> ( 121 P / 100 ) - P = 420
=> ( 121 P - 100 P ) / 100 = 420
=> 21 P / 100 = 420
=> P = ( 420 * 100 ) / 21
= 2000
Amount invested at the beginning, P = 2000 Rs
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84. Find the simple interest on Rs. 1300 at 10 % per annum for 5 years

Correct Ans:Rs. 650
Explanation:
Solution is
Given

Principal : 1300
Rate of interest : 10
Number of years : 5
Simple Interest = pnr / 100
Simple Interest = (1300 x 5 x 10) / 100
= 13 x 5 x 10
= 650
So,Simple Interest = 650
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85. A person receives a sum of Rs. 210 as interest for investing some amount at 10% p.a compounding annually for 2 years. Find the amount invested at the beginning

Correct Ans:1000
Explanation:
Solution is
Given

Compound interest received by the person ( C.I ) = Rs. 210
Rate of interest ( r ) = 10 %
Number of years ( n ) = 2 years
To find, Amount invested at the beginning = principal ( p )
Compound interest ( C.I ) = Amount - Principal
Amount = p ( 1 + r / 100 )n

=> C.I = p [ ( 1 + r / 100 )n- 1 ]
=> 210 = p [ ( 1 + 10 / 100 )2- 1 ]
=> 210 = p [ ( 110 / 100 )2- 1 ]
=> 210 = p [ ( 11 / 10 )2- 1 ]
=> 210 = p [ ( 121 / 100 ) - 1 ]
=> 210 = p [ ( 121 - 100 ) / 100 ]
=> 210 = p [ 21 / 100 ]
=> 210 x ( 100 / 21 ) = p
=> 1000 = p
The amount invested at the beginning = p = 1000 Rs
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86. Find the simple interest on Rs. 2000 at 7 % per annum for 4 years

Correct Ans:560 Rs.
Explanation:
Given
Principal = 2000
Rate of interest = 7
Number of years = 4
Simple Interest = pnr / 100
Simple Interest
= (2000 x 4 x 7) / 100
= 5600 / 100
= 560.
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87. What would be the compound interest accrued on an amount of 12500 Rs. at the end of 3 years at the rate of 10 % per annum ?

Correct Ans:4137.5
Explanation:
Solution is
Given

principal = 12500
No. of years = 3
Rate of interest = 10
Amount = P x ( 1 +( r / 100 ) )n
=12500 x ( 1 + (10 /100 ) )3
= 12500 x ( 110 / 100 )3
= 12500 x ( 11 / 10 )3
= 12500 x ( 1331 / 1000 )
= 125 x ( 1331 / 10 )
Amount = 16637.5
Compound interest = Amount - Principal
= 16637.5 - 12500
&nbs
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88. What would be the compound interest accrued on an amount of 5000 Rs. at the end of 2 years at the rate of 16 % per annum ?

Correct Ans:1728
Explanation:
Given
principal = 5000
No. of years = 2
Rate of interest = 16
Amount = P x (1+r/100)n
we get Amount = 5000 x (1+16/100)2
= 5000 x (116 / 100)2
= 5000 x (116 / 100 ) x (116 / 100)
= 58 x 116
Amount = 6728
Compound interest = Amount - Principal

= 6728 - 5000
= 1728
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89. What would be the compound interest accrued on an amount of 14000 Rs. at the end of 3 years at the rate of 5 % per annum?

Correct Ans:2206.75
Explanation:
Given
principal = 14000
No. of years = 3
Rate of interest = 5
Amount = P x (1+r/100)n
we get Amount = 14000 x (1+5/100)3
= 14000 x (105 / 100)3
= 14000 x (21 / 20)3
= 14000 x (9261 / 8000)
= 64827 / 4
= 16206.75
compound interest = Amount - principal
=16206.75 -14000
=2206.75
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90. John invested an amount of Rs. 20000 for 2 years at compound interest at the rate of 6 % per annum. Find the amount he receives at the end of 2 years.

Correct Ans:22472
Explanation:
Principal : P = 20000 Rs.
Rate of Interest : r = 6 %
Number of years : n = 2

Amount = P x (1 + r/100)^n
= 20000 x (1+6/100)^2
= 20000 x (1+3/50)^2
= 20000 x (53/50) x (53/50)
= 22472

Thus, Amount that Johnreceives at the end of 2 years = Rs.22472
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91. Rs. 10000 is borrowed at compound interest at the rate of 4 % per annum. What will be the amount to be paid after 2 years?

Correct Ans:10816
Explanation:
Principal : P = 10000 Rs.
Rate of Interest : r = 4 %
Number of years : n = 2

Amount = P x (1 + r/100)n
= 10000 x (1+4/100)2
=10000 x (1+1/25)2
=10000 x (26/25) x (26/25)
=10816
Thus, Amount to be paid after 2 years = Rs.10816
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92. What would be the compound interest accrued on an amount of 2500 Rs. at the end of 2 years at the rate of 10 % per annum ?

Correct Ans:3025
Explanation:
Given principal = 2500 No. of years = 2 Rate of interest = 10 Amount = P x (1+r/100)^n, we get Amount = 2500 x (1+10/100)^2 Ans : 3025
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93. What would be the compound interest accrued on an amount of 4500 Rs. at the end of 2 years at the rate of 10 % per annum ?

Correct Ans:5445
Explanation:
Given principal = 4500

No. of years = 2

Rate of interest = 10

Amount = P x (1+r/100)^n,

we get Amount = 4500 x (1+10/100)^2

Ans : 5445
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94. What would be the compound interest accrued on an amount of 11500 Rs. at the end of 2 years at the rate of 10 % per annum ?

Correct Ans:13915
Explanation:
Given
Principal = 11500 No. of years = 2 Rate of interest = 10
Amount = P x (1+r/100)^n,
we get Amount = 11500 x (1+10/100)^2
= 11500 x ( 110 / 100 )^ 2
= 115 x 11 x 11
= 115 x 121
Ans : 13915
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95. What would be the compound interest accrued on an amount of 5000 Rs. at the end of 2 years at the rate of 16 % per annum?

Correct Ans:1728
Explanation:

Given principal = 5000
No. of years = 2
Rate of interest = 16

Amount = P x (1+r/100)^n,
= 5000 x (1+16/100)^2
= 5000 x (1 + 4/25)^2
= 5000 x (29 / 25)^2
= 5000 x (841 / 625)
=6728
=>Amount = Rs.6728

Compound Interest = Amount - Principal

= 6728 - 5000
=1728
Thus,Compound Interest = Rs.1728

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96. What would be the compound interest accrued on an amount of 8000 Rs. at the end of 2 years at the rate of 5 % per annum ?

Correct Ans:8820
Explanation:
Given principal = 8000. No. of years = 2 Rate of interest = 5. Amount = P x (1+r/100)^n, we get Amount = 8000 x (1+5/100)^2 . Ans : 8820
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97. What would be the compound interest accrued on an amount of 6250 Rs. at the end of 2 years at the rate of 8 % per annum?

Correct Ans:1040
Explanation:
Given, principal = 6250
No. of years = 2
Rate of interest = 8

Amount = P x (1+r/100)^n,
=> Amount = 6250 x (1+8/100)^2
= 6250 x (108 / 100)^2
= 6250 x (108 / 100) x (108 / 100)
= 7290

Compound Interest = Amount - Principal
= 7290 - 6250
= 1040
Therefore, Compound Interest = Rs. 1040
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98. What would be the compound interest accrued on an amount of 2500 Rs. at the end of 3 years at the rate of 10 % per annum?

Correct Ans:827.5
Explanation:
Given principal = 2500
No. of years = 3
Rate of interest (r) = 10

Amount = P x (1+r/100)^n
=>Amount = 2500 x (1+10/100)^3
= 2500 x (1+1/10)^3
= 2500 x (11/10)^3
= 2500 x (1331 / 1000)
=3327.5
=>Amount = Rs.3327.5

Compound interest = Amount - Principal
= 3327.5 - 2500
=827.5
Thus, theCompound interest = Rs.827.5
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99. What would be the compound interest accrued on an amount of 6500 Rs. at the end of 2 years at the rate of 15 % per annum ?

Correct Ans:8596.25
Explanation:
Given principal = 6500 No. of years = 2 Rate of interest = 15 Amount = P x (1+r/100)n, we get Amount = 6500 x (1+15/100)2 Ans : 8596.25
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100. What would be the compound interest accrued on an amount of 2500 Rs. at the end of 2 years at the rate of 10 % per annum?

Correct Ans:525
Explanation:
Given principal = 2500
No. of years = 2
Rate of interest = 10

Amount = P x (1+r/100)^n,
=> Amount = 2500 x (1+10/100)^2
= 2500 (11/ 10)^2
= 2500 (121/ 100)
= 25 * 121
= 3025
So, Compound Amount = 3025

Compound Interest = Compound Amount - Principal

=> C.I = 3025 - 2500
=> C.I = 525 Rs.
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