Average and Age Questions and Answers updated daily – Aptitude

Average and Age Questions: Solved 490 Average and Age Questions and answers section with explanation for various online exam preparation, various interviews, Aptitude Category online test. Category Questions section with detailed description, explanation will help you to master the topic.

Average and Age Questions

121. The respective ratio between the present age of Manisha and Deepali is 5 : X. Manisha is 9 years younger than Parineeta. Parineeta's age after 9 years will be 33 years. The difference between Deepali's and Manisha's age is same as the present age of Parineeta. What will come in place of X?




SHOW ANSWER
Correct Ans:None of these
Explanation:
According to the question,
Parineeta's age after 9 years will be 33.
So,the present age of Parineeta = 33 – 9 = 24 years
Its given that, Manisha is 9 years younger than Parineeta.
Hence, the present age of Manisha = 24 – 9 = 15 years
Since, (Deepali’s age - Manisha’s age) = Present age of Parineeta
(Deepali’s age - 15) = 24
So the present age of Deepali = 24 + 15 = 39 years
Since, respective ratio between the present age of Manisha and Deepali is 5 : X
5 : X = 15 : 39
X = (5*39)/15
X = 13 years
Workspace



122. Meetali and Neeraj got married 30 years ago. Meetali is 4 years younger than Neeraj. When they got married the difference between 2 times of the Meetali's age and 1.5 times of the Neeraj's age was 5 years. Find the present age of Meetali and Neeraj.




SHOW ANSWER
Correct Ans:52, 56
Explanation:
Before 30 years,
Let's take Neeraj's age = x years and Meetali's age = (x – 4) years
According to the question,
2(x - 4) - 1.5x = 5
2x - 8 - 1.5x = 5
0.5x = 13
x = 13/0.5
x = 26
Therefore, present age of Meetali = (x - 4) + 30
= (26 - 4) +30 = 52
And present age of Neeraj = x + 30
= 26 + 30 = 56
Workspace



123. Balram is as much younger than Bhairav as Bhairav is older than Virendra. If the sum of the ages of Bhairav and Balram is 50 years, what is the difference between Balram and Bhairav’s age? 




SHOW ANSWER
Correct Ans:Cannot be determined
Explanation:
Common Explanation:
Age of (Bhairav – Balram) = Age of (Bhairav – Virendra)
Age of Balram = Age of Virendra
Also, Age of (Balram + Bhairav) = 50
From all inputs.
Difference between the ages of Bhairav & Balram cannot be determined as the data given are inadequate.
Workspace



124. Mr. Hatim’s total annual gross salary, which was Rs. 10 lakhs per year in 2007, has been reduced by 10% in 2008. In 2007 his family expenditure for food items was 40% of the total annual gross salary. The prices of average food items have increased by 5% between 2007 and 2008. Assuming that the family consumed the same amount of food in 2008, the percentage expenditure on food items, calculated on total annual gross salary in 2008, is approximately:

 




SHOW ANSWER
Correct Ans:47
Explanation:
Given
Halim's Salary in 2008 is => 900000 Rupees
Expenditure in food in the year of 2007 => 400000 Rupees
=>400000 +400000 * 5 / 100
=> 420000.

Percentage Expenditure of food items in 2008
=> 420000 /900000 * 10
=> 47 %.
Workspace



125. Atif's age is 1/6th of his father's age. Atif's father, Kayyum’s age will be twice the age of Ravi's age after 10 years. If Ravi's tenth birthday was celebrated three years before, then what is Atif's present age. 




SHOW ANSWER
Correct Ans:6 years
Explanation:
Let the present age of Ravi = r
Then we have R= 10 + 3 = 13 years as Ravi's 10th Birthday was three years ago
Now we have Ravi's age after 10 years = r + 10
=> 13 + 10
=> 23
Let the present age of Atif And Kayyum will be a and k
k + 10 = 2 * ( 10 + r )
=> k + 10 = 2 * 23
=> k = 46 -10
= 36.
Hence, Age of Atif = k / 6
=> 36 / 6
=> 6 years.
Workspace



126. The average weight of all the 11 players of CSK is 50 kg. If the average of first six lightest weight players of CSK is 49 kg and that of the six heaviest players of CSK is 52 kg. The average weight of the player which lies in the sixth position in the list of players when all the 11 players of CSK are arranged in the order of increasing or decreasing weights. 




SHOW ANSWER
Correct Ans:56 kg
Explanation:
Average of First six players = 49 * 6 = 294
Average of Last six players = 52 * 6 = 312;
Average of all players = 50 * 11 = 550
Average weight of sixth player = 294 + 312 – 550 = 56.

The answer is 56kg.
Workspace



127. In a particular week the average number of people visited the museum is 70. If we exclude the holidays then the average number is increased by 28. Further if we exclude the day which the maximum of 210 visitors visited the museum, then the average become 40. Find the number of holidays in the week.




SHOW ANSWER
Correct Ans:Two
Explanation:
Total no of visitors in a week = 70* 7 = 490
X = no of holidays
Exclude holidays
(7-x)*98 =490
7-x = 5
X = 2
Workspace



128. Tanya's grandfather was 8 times older to her 16 years ago. He would be 3 times of her age 8 years from now. Eight years ago, what was the ratio of Tanya's age to that of her grandfather?
 




SHOW ANSWER
Correct Ans:11:53
Explanation:
Let, Tanya age 16 years ago = x,
Grandfather's age 16 years ago = 8x.

8 years from now, 3(x+16+8) = (8x+16+8)
=> x = 48/5

8 years ago Ratio was:
=> x + 8 / 8x + 8
=> 48 / 5 +( 8 ) / 8 * (48 / 5 ) + 8
=> 88 / 424
=> 11 / 53
the correct answer is 11 / 53.
Workspace



129. A family consists of two grandparents, two parents and three grandchildren. The average age of the grandparents is 67 years, that of the parents is 35 years and that of the grandchildren is 6 years. What is the average age of the family? 




SHOW ANSWER
Correct Ans:31 ( 5 / 7) years
Explanation:
Given
The family consists of two grandparents, two parents and three grandchildren
The average age of two grandparents = 67 years.
=> Total age of two grandparents = (67 * 2) = 134 years

The average age of two parents = 35 years
=> Total age of two parents = (35 * 2) = 70 years

The average age of three grand children = 6 years.
=> Total age of three grand children = (6 * 3) = 18 years.

Required Average age of the family = Total age of (two grandparents + two parents + three grand children) / Total members in the family
= ( 134 + 70 + 18 ) / (2 + 2 + 3)
= 222 / 7
= 31 (5 / 7) years
Workspace



130. If 13:11 is the ratio of present age of Jothi and Viji respectively and 15:9 is the ratio between Jothi's age 4 years hence and Viji's age 4 years ago. Then what will be the ratio of Jothi's age 4 years ago and Viji's age 4 years hence?




SHOW ANSWER
Correct Ans:(11 : 13)
Explanation:
Let the present age of Jothi and Viji be 13X and 11X respectively.

Given, Jothi's age 4 years hence and Viji's age 4 years ago in the ratio 15:9.
That is, (13X + 4) / (11X - 4) = 15 / 9
=> 9 (13X + 4) = 15 (11X - 4)
=> 117X + 36 = 165X - 60
=> 165X - 117X = 60 + 36
=> 48X = 96
=> X = 96 / 48
=> X = 2

Now, Required ratio = (13X - 4) / (11X + 4)
on substituting value of X = 2 we get,
= [13(2)-4] / [11(2)+4]
= 22/26
= 11/13

Hence the answer is 11:13
Workspace



131. The average age of a group of 10 students was 14. The average age increased by 1 years when two new students joined the group. What is the average age of the two new students who joined the group?




SHOW ANSWER
Correct Ans:20
Explanation:
The average age of a group of 10 students is 14.
Therefore, the sum of the ages of all 10 of them = 10 * 14 = 140
When two students joins the group, the average increase by 1. New Average = 15
Now there are 12 students Therefore, sum of all the ages of 12 students = 15 x 12 = 180
Therefore, the sum of the ages of two students who joined = 180 - 140 = 40
And the average age of these two students = 20
Workspace



132. The average age of a group of 10 students was 12. The average age increased by 2 years when two new students joined the group. What is the average age of the two new students who joined the group ?




SHOW ANSWER
Correct Ans:24
Explanation:
The average age of a group of 10 students is 12.
Therefore, the sum of the ages of all 10 of them = 10 * 12 = 120
When two students joins the group, the average increase by 2.
New Average = 14 Now there are 12 students
Therefore, sum of all the ages of 12 students = 168
Therefore, the sum of the ages of two students who joined = 168 - 120 = 48
And the average age of these two students = 24
Workspace



133. The average age of a group of 10 students was 24. The average age increased by 1 years when two new students joined the group. What is the average age of the two new students who joined the group?




SHOW ANSWER
Correct Ans:30
Explanation:
The average age of a group of 10 students is 24.
Therefore, the sum of the ages of all 10 of them = 10 * 24 = 240
When two students joins the group, the average increase by 1. New Average = 25
Now there are 11 students Therefore, sum of all the ages of 12 students = 12 x 25 = 300
Therefore, the sum of the ages of two students who joined = 300 - 240 = 60
And the average age of these two students = 30
Workspace



134. The average age of a group of 10 students was 6. The average age increased by 2 years when two new students joined the group. What is the average age of the two new students who joined the group ?  




SHOW ANSWER
Correct Ans:18
Explanation:
The average age of a group of 10 students is 6.
Therefore, the sum of the ages of all 10 of them = 10 * 6 = 60

When two students joins the group, the average increase by 2.
New Average = 8

Now there are 12 students Therefore, sum of all the ages of 12 students =12 x 8 = 96
Therefore, the sum of the ages of two students who joined = 96 - 60 = 36
And the average age of these two students = 18.
Workspace



135. The average age of a group of 10 students was 10. The average age increased by 1 years when two new students joined the group. What is the average age of the two new students who joined the group? 




SHOW ANSWER
Correct Ans:16
Explanation:
The average age of a group of 10 students is 10.
Therefore, the sum of the ages of all 10 of them = 10 * 10 = 100

When two students joins the group, the average increase by 1.
=> New Average = 11
Now there are 12 students.
Therefore, sum of all the ages of 12 students = 11 x 12 = 132

Therefore, the sum of the ages of two students who joined = 132 - 100 = 32
And the average age of these two students = (32 / 2) = 16
Workspace



136. The average age of a group of 10 students was 22. The average age increased by 1 years when two new students joined the group. What is the average age of the two new students who joined the group?




SHOW ANSWER
Correct Ans:28
Explanation:
The average age of a group of 10 students is 22.
Therefore, the sum of the ages of all 10 of them = 10 * 22 = 220
When two students joins the group, the average increase by 1. New Average = 23
Now there are 12 students Therefore, sum of all the ages of 12 students = 12 x 23 = 276
Therefore, the sum of the ages of two students who joined = 276 - 220 = 56
And the average age of these two students = 28
Workspace



137. The average age of a group of 10 students was 18. The average age increased by 1 year when two new students joined the group. What is the average age of the two new students who joined the group?




SHOW ANSWER
Correct Ans:24
Explanation:
The average age of a group of 10 students is 18.
Therefore, the sum of the ages of all 10 of them = 10 * 18 = 180
When two students joins the group, the average increase by 1. New Average = 19
Now there are 12 students Therefore, sum of all the ages of 12 students = (12 X 19 ) =228
Therefore, the sum of the ages of two students who joined = 228 - 180 = 48
And the average age of these two students = 24
Workspace



138. In the first 30 overs of a cricket game, the run rate was only 4.5. What should be the run rate in the remaining 20 overs to reach the target of 320 runs. ?




SHOW ANSWER
Correct Ans:9.25
Explanation:
Required Run rate = ( 320 - ( 4.5 x 30 ) )/ (20) = ( 185) /(20) = 9.25
Workspace



139. The average age of a group of 10 students was 20. The average age increased by 2 years when two new students joined the group. What is the average age of the two new students who joined the group?




SHOW ANSWER
Correct Ans:32
Explanation:
The average age of a group of 10 students is 20. Therefore, the sum of the ages of all 10 of them = 10 * 20 = 200 When two students joins the group, the average increase by 2. New Average = 22 Now there are 12 students Therefore, sum of all the ages of 12 students = 264 Therefore, the sum of the ages of two students who joined = 264 - 200 = 64 And the average age of these two students = 32
Workspace



140. The average age of a group of 10 students was 20. The average age increased by 2 years when two new students joined the group. What is the average age of the two new students who joined the group ?




SHOW ANSWER
Correct Ans:32
Explanation:
The average age of a group of 10 students is 20.
Therefore, the sum of the ages of all 10 of them = 10 * 20 = 200 When two students joins the group, the average increase by 2. New Average = 22
Now there are 12 students Therefore, sum of all the ages of 12 students = (12 X 22) = 264
Therefore, the sum of the ages of two students who joined = 264 - 200 = 64
And the average age of these two students = 32
Workspace



Are you seeking for good platform for practicing Average and Age questions in online. This is the right place. The time you spent in Fresherslive will be the most beneficial one for you.

Online Test on Average and Age @ Fresherslive

This page provides important questions on Average and Age along with correct answers and clear explanation, which will be very useful for various Interviews, Competitive examinations and Entrance tests. Here, Most of the Average and Age questions are framed with Latest concepts, so that you may get updated through these Average and Age Online tests. Average and Age Online Test questions are granted from basic level to complex level.

Why To Practice Average and Age Test questions Online @ Fresherslive?

Average and Age questions are delivered with accurate answer. For solving each and every question, very lucid explanations are provided with diagrams wherever necessary.
Practice in advance of similar questions on Average and Age may improve your performance in the real Exams and Interview.
Time Management for answering the Average and Age questions quickly is foremost important for success in Competitive Exams and Placement Interviews.
Through Fresherslive Average and Age questions and answers, you can acquire all the essential idea to solve any difficult questions on Average and Age in short time and also in short cut method.
Winners are those who can use the simplest method for solving a question. So that they have enough time for solving all the questions in examination, correctly without any tense. Fresherslive provides most simplest methods to answer any tough questions. Practise through Fresherslive test series to ensure success in all competitive exams, entrance exams and placement tests.

Why Fresherslive For Average and Age Online Test Preparation?

Most of the job seekers finding it hard to clear Average and Age test or get stuck on any particular question, our Average and Age test sections will help you to success in Exams as well as Interviews. To acquire clear understanding of Average and Age, exercise these advanced Average and Age questions with answers.
You're Welcome to use the Fresherslive Online Test at any time you want. Start your beginning, of anything you want by using our sample Average and Age Online Test and create yourself a successful one. Fresherslive provides you a new opportunity to improve yourself. Take it and make use of it to the fullest. GOODLUCK for Your Bright Future.


Online Test for Data Interpretation
Online Test for C Language
FreshersLive - No.1 Job site in India. Here you can find latest 2023 government as well as private job recruitment notifications for different posts vacancies in India. Get top company jobs for both fresher and experienced. Job Seekers can get useful interview tips, resume services & interview Question and answer. Practice online test free which is helpful for interview preparation. Register with us to get latest employment news/rojgar samachar notifications. Also get latest free govt and other sarkari naukri job alerts daily through E-mail...
DMCA.com Protection Status