# Average and Age Questions and Answers updated daily – Aptitude

Average and Age Questions: Solved 490 Average and Age Questions and answers section with explanation for various online exam preparation, various interviews, Aptitude Category online test. Category Questions section with detailed description, explanation will help you to master the topic.

## Average and Age Questions

1. Three years ago, Poorvi was thrice as old as his sister Reena. After three years Poorvi will be twice as old as Reena. What is the present age of Reena?

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Correct Ans:9

Explanation:

Three years ago, Poorvi was thrice as old as his sister Reena. After three years Poorvi will be twice as old as Reena. What is the present age of Reena:

Explanation :

P â€“ 3 = 3 *(R â€“ 3) â€”(1)

P + 3 = 2 *(R + 3) â€”(2)

Solving eqn (1) and (2) R =

Explanation :

P â€“ 3 = 3 *(R â€“ 3) â€”(1)

P + 3 = 2 *(R + 3) â€”(2)

Solving eqn (1) and (2) R =

**9**
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2. The respective ratio between the present age of Monika and Deepak is 5:x. Monika is 9 years younger than Prem. Prem"™s age after 9 years will be 33 years. The difference between Deepak"™s and Monika"™s age is same as the present age of Prem. What is the value of x?

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Correct Ans:13

Explanation:

The respective ratio between the present age of Monika and Deepak is 5:x. Monika is 9 years younger than Prem. Premâ€™s age after 9 years will be 33 years. The difference between Deepakâ€™s and Monikaâ€™s age is same as the present age of Prem. What is the value of x:

Explanation :

Premâ€™s age after 9 years = 33 years

Premâ€™s present age = 33 â€“ 9 = 24 years

Monikaâ€™s present age = 24 â€“ 9 = 15 years

Deepakâ€™s present age = 15 + 24 = 39 years

Ratio between Monika and Deepak = 15 : 39 = 5 : 13

---> X =

Explanation :

Premâ€™s age after 9 years = 33 years

Premâ€™s present age = 33 â€“ 9 = 24 years

Monikaâ€™s present age = 24 â€“ 9 = 15 years

Deepakâ€™s present age = 15 + 24 = 39 years

Ratio between Monika and Deepak = 15 : 39 = 5 : 13

---> X =

**13**
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3. James"™ father was 30 years old when he was born. His mother"™s age was 24 when his sister who is 5 years younger to him, was born. What is the difference between the age of James"™ father and mother?

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Correct Ans:11

Explanation:

Jamesâ€™ father was 30 years old when he was born. His motherâ€™s age was 24 when his sister who is 5 years younger to him, was born. What is the difference between the age of Jamesâ€™ father and mother:

Explanation :

Jamesâ€™age = F â€“ 30

sisterâ€™s age = F â€“ 35

M = 24 + Sisterâ€™s age

M = 24 + F â€“ 35

F â€“ M =

Explanation :

Jamesâ€™age = F â€“ 30

sisterâ€™s age = F â€“ 35

M = 24 + Sisterâ€™s age

M = 24 + F â€“ 35

F â€“ M =

**11**
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4. The average weight of 20 people is increased by 2.2 kg when one man weight 53 kg is replaced by another man. Find the weight of new man?

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Correct Ans:97 Kg

Explanation:

-----> Average = 2.2,

-----> Number of people (n) = 20

-----> Average = ( Total sum/n)

-----> Total weight increased = 2.2*20 = 44 kg

----->

-----> Number of people (n) = 20

-----> Average = ( Total sum/n)

-----> Total weight increased = 2.2*20 = 44 kg

----->

**Weight of new man = 44 + 53 = 97 kg**
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5. An exam was conducted in a state over 222 centres. The average number of applicants per centre was found to be 1560. However, it was later realized that in one centre, the number of applicants was counted as 1857 instead of 1747. What was the correct average number of applicants per centre (upto two decimals)?

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Correct Ans:1559.51

Explanation:

-----> Number of applicants that have been counted extra = 1857 âˆ’ 1747 = 110

-----> Hence, decrease in average = 110/222 = 0.495

-----> Correct average = 1560 âˆ’ 0.495 = 1559.505 = 1559.51

-----> Hence, decrease in average = 110/222 = 0.495

-----> Correct average = 1560 âˆ’ 0.495 = 1559.505 = 1559.51

**Hence, option D is correct.**
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6. The average of eight numbers is 25, out of which average of first two numbers is (39/2) and the average of the next three numbers is(70/3) . The sixth number is less than the seventh and the eighth by 5 and 8 respectively. Find the seventh number.

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Correct Ans:31

Explanation:

---> Sum of eight numbers = 25 * 8 = 200

---> Sum of first two numbers = (39/2) * 2 = 39

---> Sum of first three numbers = (70/3) * 3 = 70

---> Let, the sixth number be x

---> So, sum of sixth, seventh and eighth number = 200 – (39+70) = 200 – 109 = 91

---> = x+x+5+x+8 = 91

---> = x = 26

---> Therefore, seventh number = 26 + 5 = 31

--->

---> Sum of first two numbers = (39/2) * 2 = 39

---> Sum of first three numbers = (70/3) * 3 = 70

---> Let, the sixth number be x

---> So, sum of sixth, seventh and eighth number = 200 – (39+70) = 200 – 109 = 91

---> = x+x+5+x+8 = 91

---> = x = 26

---> Therefore, seventh number = 26 + 5 = 31

--->

**So option (a) is the correct answer.**
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7. The average salary of a company increases by 100 when the salary of the manager, which is Rs. 9500, is included. If the number of employees excluding the manager is the smallest cube divisible by 16, what is the final average of the company?

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Correct Ans:Rs. 3100

Explanation:

----> The smallest cube divisible by 16 is 64.

----> Lets assume the average salary before the manager's salary is included is x

----> After addition of Manager's salary the average increases by 100

----> We can write down the above information in form of an equation as:

----> 64x + 9500 = 65 * (x + 100)

----> Solving for x, we get x = 3000

----> The final average is 3000 + 100 = Rs. 3100

---->

----> Lets assume the average salary before the manager's salary is included is x

----> After addition of Manager's salary the average increases by 100

----> We can write down the above information in form of an equation as:

----> 64x + 9500 = 65 * (x + 100)

----> Solving for x, we get x = 3000

----> The final average is 3000 + 100 = Rs. 3100

---->

**Hence, option D is correct.**
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8. The Average marks obtained by 45 students in an examination is 12. If the average marks of passed students are 14 and that of failed students are 5, then find the number of students who passed the examination?

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Correct Ans:35

Explanation:

------> Let the number of passed students be x,

------> 45 * 12 = 14x + (45 â€“ x) * 5

------> 540 = 14x + 225 â€“ 5x

------> 540 â€“ 225 = 9x

------> 9x = 315

------> X = 35

------>

------> 45 * 12 = 14x + (45 â€“ x) * 5

------> 540 = 14x + 225 â€“ 5x

------> 540 â€“ 225 = 9x

------> 9x = 315

------> X = 35

------>

**Total number of passed students = 35**
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9. Average weight of three friends Amar, Visera and Daman is 70 kg. Another person Vishal joins the group and now the average is 66 kg. If another person Tahir whose weight is 6 kg more than Vishal, joins the group replacing Amar, then average weight of Visera, Daman, Vishal and Tahir becomes 75 kg. What is the weight of Amar (in kg)?

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Correct Ans:24

Explanation:

-----> Total weight of Amar, Visera and Daman = 70 * 3 = 210 kg

-----> Again, Amar + Visera + Daman + Vishal = 66 * 4 = 264 kg ......... (i)

-----> Weight of Vishal = 264 â€“ 210 = 54 kg

-----> Weight of Tahir = 54 + 6 = 60 kg

-----> Now, as per the question

-----> Visera + Daman + Vishal + Tahir = 75 * 4 = 300 kg. ................... (ii)

-----> Subtracting (i) from (ii), we get

-----> Tahir â€“ Amar = 60 â€“ Amar = 300 â€“ 264 = 36

-----> Therefore, weight of Amar = 60 â€“ 36 = 24 kg

----->

-----> Again, Amar + Visera + Daman + Vishal = 66 * 4 = 264 kg ......... (i)

-----> Weight of Vishal = 264 â€“ 210 = 54 kg

-----> Weight of Tahir = 54 + 6 = 60 kg

-----> Now, as per the question

-----> Visera + Daman + Vishal + Tahir = 75 * 4 = 300 kg. ................... (ii)

-----> Subtracting (i) from (ii), we get

-----> Tahir â€“ Amar = 60 â€“ Amar = 300 â€“ 264 = 36

-----> Therefore, weight of Amar = 60 â€“ 36 = 24 kg

----->

**Hence, option D is correct.**
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10. The sum of 8 consecutive odd numbers is 256. Also average of four consecutive even numbers is 100. What is the sum of the smallest odd number and second largest even number?

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Correct Ans:51

Explanation:

---> Let the odd numbers are = a-7, a-5, a-3, a-1, a+1, a+3, a+5,a+7

---> let the even numbers are = b-3,b-1, b+1,b+3

Now,

---> a-7+ a-5 + a-3 + a-1 + a+1 + a+3 + a+5 +a+7 = 8a = 256

---> a = 32

---> smallest odd number is 32-7 = 25

---> similarly, 4b = 100

---> b = 25......second largest even number is 25 + 1 = 26

---> Required Sum = 25+ 26 =

---> let the even numbers are = b-3,b-1, b+1,b+3

Now,

---> a-7+ a-5 + a-3 + a-1 + a+1 + a+3 + a+5 +a+7 = 8a = 256

---> a = 32

---> smallest odd number is 32-7 = 25

---> similarly, 4b = 100

---> b = 25......second largest even number is 25 + 1 = 26

---> Required Sum = 25+ 26 =

**51**
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11. 3 years ago, the ratio of age of A and B is (5: 4). C is 8 years younger than A. The present age of C is 4 times of D"™s present age. Find the present age of B, if the age of D, after 7 years is 12 years?

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Correct Ans:23 years

Explanation:

---> 3 years ago, the ratio of age of A and B = 5: 4 (5x, 4x)

---> The present age of A and B = 5x + 3, 4x + 3

---> Present age of C = Present age of A â€“ 8

---> Present age of D = 12 â€“ 7 = 5

---> Present age of C = 4 * present age of D

---> 4*5 = 20 years

---> Present age of A = 20 + 8 = 28 years

---> 5x + 3 = 28

---> 5x = 25

---> X = 5

--->

---> The present age of A and B = 5x + 3, 4x + 3

---> Present age of C = Present age of A â€“ 8

---> Present age of D = 12 â€“ 7 = 5

---> Present age of C = 4 * present age of D

---> 4*5 = 20 years

---> Present age of A = 20 + 8 = 28 years

---> 5x + 3 = 28

---> 5x = 25

---> X = 5

--->

**The present age of B = 4x + 3 = 23 years**
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12. 6 years ago, the ratio of the ages of Arun and Prathap is 7: 6. Present age of Rajeev is 10 years more than one – sixth of Prathap’s present age. Find the ratio of present age of Prathap and Rajeev, if Arun’s age after 6 years is 40 years?

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Correct Ans:2: 1

Explanation:

----> 6 years ago, the ratio of the ages of Arun and Prathap = 7: 6 (7x, 6x)

----> Present ages of Arun and Prathap = 7x + 6, 6x + 6

----> Present age of Rajeev = (1/6)*Prathap’s present age + 10

----> Arun’s present age = 34 years

----> According to the question,

----> 7x = 28

----> x = 4

----> Prathap’s present age = 6x + 6 = 30

----> Rajeev’s present age = (1/6)*30 + 10 = 15

----> Required ratio = 30: 15 =

----> Present ages of Arun and Prathap = 7x + 6, 6x + 6

----> Present age of Rajeev = (1/6)*Prathap’s present age + 10

----> Arun’s present age = 34 years

----> According to the question,

----> 7x = 28

----> x = 4

----> Prathap’s present age = 6x + 6 = 30

----> Rajeev’s present age = (1/6)*30 + 10 = 15

----> Required ratio = 30: 15 =

**2: 1**
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13. The ratio of the ages of Tina and Rakesh is (9:10) respectively. Ten years ago the ratio of their ages was (4:5) respectively. What is the present age of Rakesh?

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Correct Ans:20yr

Explanation:

---> Let current ages of Tina and Rakesh are X and Y

Given that

---> (X : Y) = (9:10) or (X/ Y) = (9/ 10) â†’ X = (9Y/10)â€¦â€¦ (a)

---> Ten years ago their ratios

---> (X-10: Y-10) = (4:5) o r (X-10/Y-10) = (4/5) â€¦. (b)

---> By putting the value of X from (a) into (b)

---> ([(9y/10)-10]/y-10) = (4/5)

---> ((9y/2) -50) = 4y-40

---> (9y/2)-4y = -40+50

---> ((9y-8y)/2) = 10

---> we get Y = 20

--->

Given that

---> (X : Y) = (9:10) or (X/ Y) = (9/ 10) â†’ X = (9Y/10)â€¦â€¦ (a)

---> Ten years ago their ratios

---> (X-10: Y-10) = (4:5) o r (X-10/Y-10) = (4/5) â€¦. (b)

---> By putting the value of X from (a) into (b)

---> ([(9y/10)-10]/y-10) = (4/5)

---> ((9y/2) -50) = 4y-40

---> (9y/2)-4y = -40+50

---> ((9y-8y)/2) = 10

---> we get Y = 20

--->

**Hence Rakeshâ€™s present age is 20 yr.**
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14. The ratio between Rakesh and Kalai is (17: x). Kalai is 2 years elder than Manoj. Manoj"™s age after 4 years will be 20 years. The difference between Rakesh and Kalai is equal to Manoj"™s age. Find the value of x?

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Correct Ans:9

Explanation:

---> The present age of Rakesh and Kalai = (17: x)

---> Kalai = (Manoj + 2)

---> Manojâ€™s present age = 20 â€“ 4 = 16 years

---> Kalaiâ€™s present age = 16 + 2 = 18

---> Rakeshâ€™s age â€“ Kalaiâ€™s age = Manojâ€™s age

---> Rakeshâ€™s age = 16 + 18 = 34

---> 17â€™s = 34

---> 1â€™s = 2

---> The value of x = (Kalaiâ€™s age/2)

---> = (18/2) =

---> Kalai = (Manoj + 2)

---> Manojâ€™s present age = 20 â€“ 4 = 16 years

---> Kalaiâ€™s present age = 16 + 2 = 18

---> Rakeshâ€™s age â€“ Kalaiâ€™s age = Manojâ€™s age

---> Rakeshâ€™s age = 16 + 18 = 34

---> 17â€™s = 34

---> 1â€™s = 2

---> The value of x = (Kalaiâ€™s age/2)

---> = (18/2) =

**9**
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15. The age of the father is 34 years more than the son"™s age. Ten years hence, the father"™s age will become three times the son"™s age that time. What is the son"™s present age in years?

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Correct Ans:Seven

Explanation:

---> Let the sonâ€™s present age be x years.

---> Then the fatherâ€™s present age is (x + 34) years.

---> Fatherâ€™s age after 10 years = (x + 44) years

---> Sonâ€™s age after 10 years = (x + 10) years

---> (x + 44) = 3(x + 10)

---> x + 44 = 3x + 30

---> 2x = 14

--->

---> Then the fatherâ€™s present age is (x + 34) years.

---> Fatherâ€™s age after 10 years = (x + 44) years

---> Sonâ€™s age after 10 years = (x + 10) years

---> (x + 44) = 3(x + 10)

---> x + 44 = 3x + 30

---> 2x = 14

--->

**x = 7**
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16. There are four friends A, B, C and D. Five years ago the ages of A and B was in the ratio of 5: 8 respectively. 10 years hence, the ages of C and D will be in the ratio 9: 10 respectively. Present age of A is 25% less than the present age of D. Find the difference between the ages of B and C if the average present age of A, B, C and D is 37 years 6 months.

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Correct Ans:10 yrs

Explanation:

Let the ages of A and B five years ago were 5x years and 8x years respectively.

So, the present ages of A and B are '5x + 5' years and '8x + 5' years respectively.

Given that present age of A is 25% less than the present age of D.

Present age of D = (5x + 5)*(100/75) = (20x + 20)/3 years

Age of D after 10 years = [(20x + 20)/3] + 10 = (20x + 50)/3 years

10 years hence, ratio of ages of C and D = 9 : 10

Age of C after 10 years = [(20x + 50)/3]*(9/10) = 6x + 15 years

Present age of C = 6x + 15 - 10 = 6x + 5 years

As per the question,

Present age of A + Present age of B + Present age of C + Present age of D = Total age of all

5x + 5 + 8x + 5 + 6x + 5 + (20x + 20)/3 = 4*37.5

15x + 15 + 24x + 15 + 18x + 15 + 20x + 20 = 450

77x + 65 = 450

77x = 385

x = 5

So, present age of B = 8(5) + 5 = 45 years

Present age of C = 6(5) + 5 = 35 years

Required difference = 45 - 35 = 10 years.

So, the present ages of A and B are '5x + 5' years and '8x + 5' years respectively.

Given that present age of A is 25% less than the present age of D.

Present age of D = (5x + 5)*(100/75) = (20x + 20)/3 years

Age of D after 10 years = [(20x + 20)/3] + 10 = (20x + 50)/3 years

10 years hence, ratio of ages of C and D = 9 : 10

Age of C after 10 years = [(20x + 50)/3]*(9/10) = 6x + 15 years

Present age of C = 6x + 15 - 10 = 6x + 5 years

As per the question,

Present age of A + Present age of B + Present age of C + Present age of D = Total age of all

5x + 5 + 8x + 5 + 6x + 5 + (20x + 20)/3 = 4*37.5

15x + 15 + 24x + 15 + 18x + 15 + 20x + 20 = 450

77x + 65 = 450

77x = 385

x = 5

So, present age of B = 8(5) + 5 = 45 years

Present age of C = 6(5) + 5 = 35 years

Required difference = 45 - 35 = 10 years.

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17. The sum of the ages of A, B, and C is 54 years. The ratio of the ages of A and C is 1:2. B"™s father age is twice the age of B. Sum of the ages of A and C is equal to B"™s father age. Calculate the age of B.

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Correct Ans:18 yrs

Explanation:

Given:

The ratio of the ages of A and C is 1 : 2.

Let the age of A be 'x' and age of C be '2x'.

Sum of the ages of A and C is equal to B's father age.

Hence, B's father age = x + 2x = 3x

B's father age is twice the age of B.

Then B's age = (1/2)*3x = 1.5x

Also given that the sum of the ages of A, B, and C is 54 years.

x + 1.5x + 2x = 54

4.5x = 54

x = 54/4.5

x = 12

Therefore, B's age = 1.5*12 = 18 yrs.

The ratio of the ages of A and C is 1 : 2.

Let the age of A be 'x' and age of C be '2x'.

Sum of the ages of A and C is equal to B's father age.

Hence, B's father age = x + 2x = 3x

B's father age is twice the age of B.

Then B's age = (1/2)*3x = 1.5x

Also given that the sum of the ages of A, B, and C is 54 years.

x + 1.5x + 2x = 54

4.5x = 54

x = 54/4.5

x = 12

Therefore, B's age = 1.5*12 = 18 yrs.

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18. The ratio of the ages of veer and Vikram 15 years ago was 2 :1 and their ages difference 5 years ago was 10 years, then find out the ratio of ages of Veer and Vikram 15 years hence?

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Correct Ans:(5 : 4)

Explanation:

Let the present age of Veer be 'x' years and the present age of Vikram be 'y' years.

15 years ago, ratio of their ages = 2 : 1

(x - 15)/(y - 15) = 2/1

x - 15 = 2y - 30

x - 2y = -15 ...(i)

Given that their ages difference 5 years ago was 10 years. So, age difference between them will be same.

x - y = 10 ...(ii)

By solving the equation (i) and (ii),

x = 35 yrs; y = 25 yrs

15 years hence,

Age of Veer = 35 + 15 = 50 yrs

Age of Vikram = 25 + 15 = 40 yrs

Ratio of their ages after 15 yrs = 50 : 40 = 5 : 4.

15 years ago, ratio of their ages = 2 : 1

(x - 15)/(y - 15) = 2/1

x - 15 = 2y - 30

x - 2y = -15 ...(i)

Given that their ages difference 5 years ago was 10 years. So, age difference between them will be same.

x - y = 10 ...(ii)

By solving the equation (i) and (ii),

x = 35 yrs; y = 25 yrs

15 years hence,

Age of Veer = 35 + 15 = 50 yrs

Age of Vikram = 25 + 15 = 40 yrs

Ratio of their ages after 15 yrs = 50 : 40 = 5 : 4.

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19. Rithika's present age is four times her son's present age and two fifth of her father's present age. The average present age of all of them is 40 years. Find the sum of Rithika's son's present age and Rithika's father's present age?

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Correct Ans:88 years

Explanation:

Given, Rithika's present age = 4 * Rithika's son's present age

---> The ratio of present age of Rithika and her son's age = 4 : 1

---> Rithika's present age = 4x

---> Rithika's son's present age = x

Given, Rithika's present age = (2/5) * Rithika's father's present age

----> 4x = (2/5) * Rithika's father's present age

---> 2x = (1/5) * Rithika's father's present age

---> 10x = Rithika's father's present age

Also, Given that, Average present age of all of them = 40 years

---> (Rithika's present age + her son's present age + her father's present age)/3 = 40

---> (4x + x + 10x)/3 = 40

---> 15x/3 = 40

---> 5x = 40

--->

Therefore, Rithika's son's present age = x = 8 years

Rithika's father's present age = 10x = 10 * 8 = 80 years

Now,

---> The ratio of present age of Rithika and her son's age = 4 : 1

---> Rithika's present age = 4x

---> Rithika's son's present age = x

Given, Rithika's present age = (2/5) * Rithika's father's present age

----> 4x = (2/5) * Rithika's father's present age

---> 2x = (1/5) * Rithika's father's present age

---> 10x = Rithika's father's present age

Also, Given that, Average present age of all of them = 40 years

---> (Rithika's present age + her son's present age + her father's present age)/3 = 40

---> (4x + x + 10x)/3 = 40

---> 15x/3 = 40

---> 5x = 40

--->

**x = 8**Therefore, Rithika's son's present age = x = 8 years

Rithika's father's present age = 10x = 10 * 8 = 80 years

Now,

**sum of Rithika's son's present age and Rithika's father's present age**= 8 + 80 =**88 years**
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20. The mean temperature from the 9th to the 16th of January, both days inclusive, was 11.6 degree Celsius and from the 10th to 17th January was 12.2 degree Celsius. The temperature on the 9th January was 10.8 degree Celsius. What was the temperature on the 17th January?

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Correct Ans:15.6 degree Celsius

Explanation:

Given, mean temperature from 9th to 16th January = 11.6° C

Total no. of days from 9th to 16th January = 8

--->

= 11.6° C * 8

=

Given, mean temperature from 10th to 17th January = 12.2° C

Total no. of days from 10th to 17th January = 8

---> Total temperature from 10th to 17th January = 12.2° C * 8

= 97.6° C

Given, Temperature on 9th January = 10.8° C

Now,

= 10.8° C + 97.6° C

=

Then,

= 108.4° C - 92.8° C

=

Total no. of days from 9th to 16th January = 8

--->

**Total temperature from 9th to 16th January**= mean temperature from 9th to 16th January * Total no. of days from 9th to 16th January= 11.6° C * 8

=

**92.8° C**Given, mean temperature from 10th to 17th January = 12.2° C

Total no. of days from 10th to 17th January = 8

---> Total temperature from 10th to 17th January = 12.2° C * 8

= 97.6° C

Given, Temperature on 9th January = 10.8° C

Now,

**Total temperature from 9th to 17th of January**= Temperature on 9th January + Total temperature from 10th to 17th January= 10.8° C + 97.6° C

=

**108.4° C**Then,

**Temperature on 17th January**= Total temperature from 9th to 17th of January - Total temperature from 9th to 16th January= 108.4° C - 92.8° C

=

**15.6° C**
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