1. In the first 30 overs of a cricket game, the run rate was only 6.4. What should be the run rate in the remaining 20 overs to reach the target of 225 runs. ?
SHOW ANSWER
Correct Ans:1.65
Explanation:
Given
In, first30 overs of a cricket game.
Run rate = 6.4
Required Run rate in the remaining 20 overs to reach the target of 225 runs
Required Run rate
= ( 225 - ( 6.4 x 30 ) ) / (20)
= ( 33) / (20)
= 1.65.
2. In the first 10 overs of a cricket game, the run rate was only 5.6. What should be the run rate in the remaining 40 overs to reach the target of 254 runs. ?
SHOW ANSWER
Correct Ans:5
Explanation:
Given
Target = 254 runs
First 10 overs, run rate = 5.6
Remaining Overs = 40.
Required Run rate
= ( 254 - ( 5.6 x 10 ) / (40)
= ( 198 ) /(40)
=4.95
3. The average of 32 numbers is zero. Of them, at the most how many may be greater than zero. ?
SHOW ANSWER
Correct Ans:31
Explanation:
Average of 32 numbers is = 0
Therefore sum of all 32 numbers = 0
It is quite possible that 31 of these numbers may be positive and if their sum is a then 32th number is (-a)
4. In the first 30 overs of a cricket game, the run rate was only 5. What should be the run rate in the remaining 20 overs to reach the target of 250 runs. ?
SHOW ANSWER
Correct Ans:5
Explanation:
Required Run rate = ( 250 - ( 5 x 30 ) )/ (20)
= ( 100) /(20) = 5
5. In the first 25 overs of a cricket game, the run rate was only 2.2. What should be the run rate in the remaining 25 overs to reach the target of 225 runs. ?
SHOW ANSWER
Correct Ans:6.8
Explanation:
"Required Run rate = ( 225 - ( 2.2 x 25 ) )/ (25)
= ( 170) /(25) = 6.8 "
6. The average of 30 numbers is zero. Of them, at the most how many may be greater than zero?
SHOW ANSWER
Correct Ans:29
Explanation:
Average of 30 numbers is = 0
Therefore sum of all 30 numbers = 0
It is quite possible that 29 of these numbers may be positive and if their sum is "a" then 30th number is "(-a)"
7. In the first 30 overs of a cricket game, the run rate was only 7. What should be the run rate in the remaining 20 overs to reach the target of 325 runs. ?
SHOW ANSWER
Correct Ans:5.75
Explanation:
Required Run rate = ( 325 - ( 7 x 30 ) )/ (20)
= ( 115) /(20) = 5.75
8. In the first 10 overs of a cricket game, the run rate was only 1.8. What should be the run rate in the remaining 20 overs to reach the target of 215 runs?
SHOW ANSWER
Correct Ans:9.9
Explanation:
Required Run rate
= ( 215 - ( 1.8 x 10 ) ) / (20)
= ( 197) / (20)
= 9.85.
9. The average of 28 numbers is zero. Of them, at the most how many may be greater than zero?
SHOW ANSWER
Correct Ans:27
Explanation:
Average of 28 numbers is = 0
Therefore sum of all 28 numbers = 0
It is quite possible that 27 of these numbers may be positive and if their sum is "a" then 28th number is "(-a)"
10. In the first 10 overs of a cricket game, the run rate was only 7.6. What should be the run rate in the remaining 40 overs to reach the target of 212 runs?
SHOW ANSWER
Correct Ans:3.4
Explanation:
Given
First 10 overs in a cricket game
Run rate = 7.6
Required run rate in the remaining 40 overs to reach the target of 212 runs
Required Run rate
= ( 212 - ( 7.6 x 10 ) ) / (40)
= ( 136) / (40)
= 3.4.
11. In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the run rate in the remaining 40 overs to reach the target of 282 runs?
SHOW ANSWER
Correct Ans:6.3
Explanation:
Required Run rate = ( 282 - ( 3.2 x 10 ) ) / (40)
= ( 250) / (40) = 6.25
12. The average of 26 numbers is zero. Of them, at the most how many may be greater than zero?
SHOW ANSWER
Correct Ans:25
Explanation:
Average of 26 numbers is = 0
Therefore sum of all 26 numbers = 0
It is quite possible that 25 of these numbers may be positive and if their sum is "a" then 26th number is "(-a)"
13. In the first 10 overs of a cricket game, the run rate was only 8.2. What should be the run rate in the remaining 40 overs to reach the target of 106 runs?
SHOW ANSWER
Correct Ans:0.6
Explanation:
Required Run rate = ( 106 - ( 8.2 x 10 ) )/ (40)
= ( 24) /(40) = 0.6
14. The average of 24 numbers is zero. Of them, at the most how many may be greater than zero?
SHOW ANSWER
Correct Ans:23
Explanation:
Average of 24 numbers is = 0
Therefore sum of all 24 numbers = 0
It is quite possible that 23 of these numbers may be positive and if their sum is "a" then 24th number is "(-a)"
15. In the first 30 overs of a cricket game, the run rate was only 1.9. What should be the run rate in the remaining 20 overs to reach the target of 98 runs?
SHOW ANSWER
Correct Ans:2.05
Explanation:
Required Run rate = ( 98 - ( 1.9 x 30 ) )/ (20)
= ( 41) /(20) = 2.05
16. The average weight of 8 persons increases by 1.5 kg when a person weighting 65 kg is replaced by a new person. What could be the weight of the new person?
SHOW ANSWER
Correct Ans:77
Explanation:
Let the average weight of 8 persons be 'x' kg
and the weight of the new person be 'y' kg
so, (8x - 65 + y) / 8 = x+1.5
=> y = 65 + 8 * 1.5 = 77 kgs
Weight of the new person = 77 kgs.
17. The average of 8 numbers is zero. Of them, at the most how many may be greater than zero?
SHOW ANSWER
Correct Ans:7
Explanation:
Average of 8 numbers is = 0
Therefore sum of all 8 numbers = 0
It is quite possible that 7 of these numbers may be positive and if their sum is "a" then 8th number is "(-a)".
18. In the first 35 overs of a cricket game, the run rate was only 6.4. What should be the run rate in the remaining 15 overs to reach the target of 410 runs?
SHOW ANSWER
Correct Ans:12.4
Explanation:
Required Run rate = ( 410 - ( 6.4 x 35 ) )/ (15)
= ( 186) /(15) = 12.4
19. The average of 12 numbers is 24. If each number be multiplied by 6. Find the average of new set of numbers?
SHOW ANSWER
Correct Ans:144
Explanation:
New Average = Old Average x 6 = 24 x 6 = 144
20. The average of 22 numbers is zero. Of them, at the most how many may be greater than zero?
SHOW ANSWER
Correct Ans:21
Explanation:
Average of 22 numbers is = 0
Therefore sum of all 22 numbers = 0
It is quite possible that 21 of these numbers may be positive and if their sum is "a" then 22nd number is "(-a)"
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