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# Aptitude Questions And Answers Sample Test 9

Sample Aptitude Test 9 for you to Practice. Evaluate your Aptitude Test 9 test answering skills by trying the online Aptitude Sample Test 9 and know your score.

## Aptitude Test 9

You have scored 3 out of 10
You Scored:2
Total Questions:2
Attended Questions:2
1. A baby crawls diagonally in a Square shaped room. Baby covers a distance of 40dm. Find the Perimeter of the Square shaped room ?

Explanation:

Diagonal distance crawled by Baby is 40dm
Perimeter of the room (in shape of Square)= (2 x Diagonal x ?2 )
=> (40x 2 x ?2 ) =80(?2)sq.dm

2. The sum of the present ages of a father and his son is 60 years. Six years ago, father's age was five times the age of the son. After 6 years, son's age will be:

Explanation:

Let the present age of father = x years.
Given,present age offather and son = 60 years
=> Present age of son = 60 -present age offather =60 - x

Given Six years ago,father's age = 5 * (son's age)

=> x - 6 = 5 * (60 - x -6)
=> x - 6 = 5 * (54 - x)
=> x - 6 = 270 - 5x
=> x + 5x = 270 + 6
=> 6x = 276
=> x = 46

So,present age of father = x years = 46 years.
Present age of son= 60 -x = (60 - 46) = 14 years

After 6 years,age of son = 14 + 6 = 20 years.

3. Eight people are planning to share equally the cost of a rental car. If one person withdraws from the arrangement and the others share equally the entire cost of the car, then the share of each of the remaining persons increased by

Explanation:

When there are 8 people, the share of each person is 1/8 => (Original Share)
When there are 7 people, the share of each person is 1/7

Increase in the share of each person is 1/7 – 1/8 = 1 / 56
1 / 56 ==> Which is 1/7 of 1/8 ==> 1/7 of the original share of each person.

4. Find the next number in the the below series

20, 31, 45, 62, _____

Explanation:

In the given series, 20, 31, 45, 62 ,
Consecutive numbers increase by 11 ,14 ,17.
Following the same pattern, the next number should increase by 20.
When we add 20 to the last number (i.e 62) we get 20+62=82

5. Can you find the answer for the below equation

38 + 44 / 30 - 32 * 37

Explanation:

Given Question is 38 + 44 / 30 - 32 * 37
when we apply BODMAS RULE to the above question, we get (Bracket Of Division) 38 + ( 44 / 30 ) - 32 * 37 = 38 + 1.46- 32 * 37 = -1144.53

6. Find the HCF of 32 , 22 ?

Explanation:

The fastest way to find the correct answer is by elimination rule :
Check whether each of the given choices divides both the numbers. If any of the given choices doesn’t divide both the numbers, then you can eliminate that particular choice and move to the next choice. Answer will be the HIGHEST Number that exactly divides both given numbers.

Please Note : There may be a scenario when two or more numbers in the choice will exactly divide both the numbers, in that case , please choose the Highest among the numbers.

7. Which number should come in place of the missing Number ?

95, 114, 133, X , 171, 190

Explanation:

The given series is -- 95, 114, 133, X , 171, 190
Consecutive numbers increases by 19
Following this pattern, the Missing Number X should increase by 19 from the previous number.
When we add 19 to the number before X (i.e 133) we get 133+19=152

8. Find the next number in the the below series

9, 20, 34, 51, _____

Explanation:

In the given series, 9, 20, 34, 51 ,
Consecutive numbers increase by 11 ,14 ,17.
Following the same pattern, the next number should increase by 20.
When we add 20 to the last number (i.e 51) we get 20+51=71

9. Can you find the approximate value for the below equation

64.99 / 59.99 + 58.01 * 57.99 - 54.01

Explanation:

Given Question is 64.99 / 59.99 + 58.01 * 57.99 - 54.01
when we apply BODMAS RULE and round it off, we get => ( 65 / 60 ) + 58 * 58 - 54 = 1+58*58-54 = 3311

10. A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 27, then how old is B?

Explanation:

Given
Let C's age be x years.
Then, B's age = 2x years.
A's age = (2x + 2) years.
(2x + 2) + 2x + x = 27
5x = 25
x = 5.
Hence, B's age
= 2x
= 2 * 5
= 10 years.

11. In the question, two equations numbered I and II are given. Solve both the equations and give answer:

30x2 + 11x + 1 = 0
42y2 + 13y + 1 = 0

Explanation:

Given,30x2 + 11x + 1 = 0
=> 30x2 + 6x + 5x + 1 = 0
=> 6x (5x + 1) + 1(5x + 1) = 0
=>(5x + 1) (6x + 1) = 0
=> x = -1/5, -1/6
=> x = -0.2, -0.16

Given, 42y2+ 13y + 1 = 0
=> 42y2 + 6y + 7y + 1 = 0
=> 6y (7y + 1) + 1(7y + 1) = 0
=>(7y + 1) (6y + 1) = 0
=> y = -1/7, -1/6
=> y = -0.14, -0.16

Put on number line:
-0.2, -0.16, -0.16, -0.14
Thus, X ≤ Y

12. A sum fetched a total simple interest of Rs. 4016.25 at the rate of 9 p.c.p.a. in 5 years. What is the sum?

Explanation:

Given
Simple interest = Rs. 4016.25 , Rate = 9 p.c.p.a. N= 5 years.
We know that, Simple interest, SI = (p x r x t) / 100
=> Principal = S.I * 100 / (r * t)
= Rs. ( 100 * 4016.25 / 9 * 5)
= Rs. ( 401625 / 45 )
= Rs. 8925
Sum =Rs. 8925.

13. If x + y = 24 and xy= 100, What is the value of x2 + y2 = ?.

Explanation:

( x + y)2 = x2+y2+2xy ---->(1)
=> 242 = x2 + y2 + 2(100)
=> 242 = 576

substituting both the values (576 , 200) in eqn(1)

=> x2+y2
= 576 -200
= 376.
Thus the value ofx2+ y2= 376.

14. What would be the compound interest accrued on an amount of 6250 Rs. at the end of 2 years at the rate of 12 % per annum ?

Explanation:

Given
Principal = 6250 No. of years = 2 Rate of interest = 12
Amount = P x (1+r/100)^n,
we get Amount = 6250 x (1+12/100)^2
= 6250 x 112 / 100
= 5 * 56 * 28
= 7840
C.I = Amount - Principal
= 7840 - 6250
= 1590.

15. Evaluate tan 11 x tan 23 x tan 79 x tan 67

16. Find the next number in the the below series

5, 17, 36, 62, _____

Explanation:

In the given series, 5, 17, 36, 62 ,

Consecutive numbers increase by 12 ,19 ,26.

Following the same pattern, the next number should increase by 33.

When we add 33 to the last number (i.e 62) we get 33+62=95

17. Find the approximate value for the expression
14.003 - 5.004 + 5.999 / 2.998 * 4.002

Explanation:

Given Question is 14.003 - 5.004 + 5.999 / 2.998 * 4.002
when we apply BODMAS RULE to the above question,
Step - 1 : (Bracket Of Division) = (14 - 5) + ( 6 / 3 ) * 4 = (14 - 5) + (2 * 4)
Step - 2 : 9 + 8 = 17

18. The fourth proportional to 5, 8, 25 is ________

Explanation:

Given
Let the fourth proportional to 5, 8, 25 be x.
Then, 5 : 8 : 25 : x
=> 5x = (8 x 25)
=> x = (8 x 25)/5
= 40

19. We can express the number 1681 as the sum of first ___?___ odd natural numbers.

Explanation:

The number 1681 = 412 can always be expressed as sum of first 41 odd natural number

20. Can you find the answer for the below equation

74 - 392 / 388 * 397 + 380

Explanation:

Given Question is 74 - 392 / 388 * 397 + 380
when we apply BODMAS RULE to the above question, we get 74 - ( 392 / 388 ) * 397 + 380 = 74 - 1.01* 397 + 380 = 52.91

21. A Field Observer measures the length and breadth of a empty land (land in the shape of Rectangle) is 50x40m. Price per Sq.m in that region is 600. How much does it cost to buy the land (Exclude registration and other misc. charges )?

Explanation:

Given Length = 50m & Breadth = 40m
Area of Rectangle = Length x Breadth => 50 x =40 = 2000
Price = Area x Cost Per Sq.m = 2000 x 600 = 1200000

22. Can you find the answer for the below equation

118 - 100 + 111 * 110 / 103

Explanation:

Given Question is 118 - 100 + 111 * 110 / 103
when we apply BODMAS RULE to the above question, we get
=118 - 100 + 111* ( 110/ 103 )
= 118 - 100 + 111* 1.06
= 136.54.

23. What is 14.5% of 4000?

Explanation:

Solution is
14.5% of 4000 = (14.5/100 ) x 4000 = 580

24. A Computer program gave the following output. Can you predict the next number that the computer program would generate as output ?

199, 214, 229, 244, _____

Explanation:

The given series is -- 199, 214, 229, 244
Consecutive numbers increases by 15
Following this pattern, the Missing Number should increase by 15 from the previous number.
When we add 15 to the last number (i.e 244) we get 244+15=259

25. The simple interest on a sum of money is Rs. 150. What is the sum?
I. The interest rate is 10% p.a.
II. The sum earned simple interest in 10 years.

26. A baby crawls diagonally in a Square shaped room. Baby covers a distance of 40dm. To protect the child against fall, parents decide to lay play mat on the floor. Play mat costs Rs.44 per Sq.dm. How much do parents need to spend to make the floor child proof ?

Explanation:

Diagonal distance crawled by Baby is 40dm
Area of the room (in shape of Square)= (Diagonal^2) / 2
=> (40^2)/2 =800sq.dm
Price = Area x Cost Per Sq.dm = 800 x 44 = 35200

27. Can you find the approximate value for the below equation

13.99 + 5.01 / 9.99 * 7.01 - 4.99

Explanation:

Given Question is 13.99 + 5.01 / 9.99 * 7.01 - 4.99
when we apply BODMAS RULE and round it off, we get => 14 + ( 5 / 10 ) * 7 - 5 = 14 + 1* 7 - 5 = 13

28. Find the next number in the the below series

12, 43, 76, 111, _____

Explanation:

In the given series, 12, 43, 76, 111 ,

Consecutive numbers increase by 31 ,33 ,35.

Following the same pattern, the next number should increase by 37.

When we add 37 to the last number (i.e 111) we get 37+111=148

29. Can you find the answer for the below equation

159 - 584 * 586 / 591 + 578

Explanation:

Given Question is 159 - 584 * 586 / 591 + 578
when we apply BODMAS RULE to the above question, we get 159 - 584 * ( 586/ 591 ) + 578 = 159 - 584 * 0.99+ 578 = 157.94

30. Can you find the answer for the below equation

68 / 64 + 66 - 63 * 62

Explanation:

Given Question is 68 / 64 + 66 - 63 * 62
when we apply BODMAS RULE to the above question, we get (Bracket Of Division) ( 68 / 64 ) + 66 - 63 * 62 = 1.06+66-63*62 = -3838.94

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