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Sample Aptitude Test 6 for you to Practice. Evaluate your Aptitude Test 6 test answering skills by trying the online Aptitude Sample Test 6 and know your score.

You have scored 3 out of 10

You Scored:2

Total Questions:2

Attended Questions:2

Correct Answered:2

1. Find the area of the base circle in the cylinder of height 15 cm and volume 600 cu. cm ?

Explanation:

we know that,

Volume of the cylinder = πr^{2}h = 600 cu.cm

Height of the cylinder = 15 cm

The area of the base of the circle =πr^{2}

= 600/15 = 40 sq.cm

Volume of the cylinder = πr

Height of the cylinder = 15 cm

The area of the base of the circle =πr

= 600/15 = 40 sq.cm

2. Find the next number in the the below series

8, 24, 42, 62, _____

8, 24, 42, 62, _____

Explanation:

In the given series, 8, 24, 42, 62 ,

Consecutive numbers increase by 16 ,18 ,20.

Following the same pattern, the next number should increase by 22.

When we add 22 to the last number (i.e 62) we get 22+62=84

Consecutive numbers increase by 16 ,18 ,20.

Following the same pattern, the next number should increase by 22.

When we add 22 to the last number (i.e 62) we get 22+62=84

3. Find the next number in the the below series

17, 38, 60, 83, _____

17, 38, 60, 83, _____

Explanation:

In the given series, 17, 38, 60, 83 ,

Consecutive numbers increase by 21 ,22 ,23.

Following the same pattern, the next number should increase by 24.

When we add 24 to the last number (i.e 83) we get 24+83=107

Consecutive numbers increase by 21 ,22 ,23.

Following the same pattern, the next number should increase by 24.

When we add 24 to the last number (i.e 83) we get 24+83=107

4. Given a Square whose diagonal is 70 units. Compute its Perimeter ?

Explanation:

Given diagonal is 70 units

Perimeter of Square = (2 x Diagonal x sqrt(2) ) => (70x 2 x sqrt(2)) =140 sqrt(2)

Perimeter of Square = (2 x Diagonal x sqrt(2) ) => (70x 2 x sqrt(2)) =140 sqrt(2)

5. Read the statements and decide whether the data provided in the statements are sufficient to answer the question.

What is the profit percentage if a discount of 10% is offered on an article?

I. Had there been no discount offered, the profit earned on the sale the article would be 40%.

II. The discount offered on the article is 14% of the cost price.

III. The cost price of the article is Rs.1000.

What is the profit percentage if a discount of 10% is offered on an article?

I. Had there been no discount offered, the profit earned on the sale the article would be 40%.

II. The discount offered on the article is 14% of the cost price.

III. The cost price of the article is Rs.1000.

6. Find the next number in the the below series

15, 40, 68, 99, _____

15, 40, 68, 99, _____

Explanation:

In the given series, 15, 40, 68, 99 ,

Consecutive numbers increase by 25 ,28 ,31.

Following the same pattern, the next number should increase by 34.

When we add 34 to the last number (i.e 99) we get 34+99=133

Consecutive numbers increase by 25 ,28 ,31.

Following the same pattern, the next number should increase by 34.

When we add 34 to the last number (i.e 99) we get 34+99=133

7. A football team won 10 games from the total they played. This was 40 % of the total. How many games were played in all?

Explanation:

Let k be the total number of games played.

Given, 40 % of k =10

=> (40 / 100) * k = 10

=> k = 10 * (100 / 40)

=> k = 100 / 4

=>** k = 25**

Therefore,** total number of games played = 25**

Given, 40 % of k =10

=> (40 / 100) * k = 10

=> k = 10 * (100 / 40)

=> k = 100 / 4

=>

Therefore,

8. An article was bought for Rs. 4800. Its price was marked up by 15 %. Thereafter it was sold at a discount of 8 % on the marked price. Find the amount of discount given ?

Explanation:

Marked Price = 4800 x 115/100 = 5520
Discount = 441.6

9. A sum of Rs. 5000 is lent for 4 years at the rate of 12% per annum. Find the interest. ?

Explanation:

Given

Principal, p = 5000, time, n=4 years and rate of interest, r = 12 %

**Simple Interest, SI = (p x n x r) / 100 **

= (5000 x 4 x 12)/100

= 50 x 4 x 12

= 200 x 12

=2400

Principal, p = 5000, time, n=4 years and rate of interest, r = 12 %

= (5000 x 4 x 12)/100

= 50 x 4 x 12

= 200 x 12

=2400

10. Can you find the approximate value for the below equation

25.01 + 18.99 - 26.01 / 20.99 * 22.01

25.01 + 18.99 - 26.01 / 20.99 * 22.01

Explanation:

Given Question is 25.01 + 18.99 - 26.01 / 20.99 * 22.01

when we apply BODMAS RULE and round it off, we get => 25 + 19 - ( 26/ 21 ) * 22 = 25 + 19 - 1* 22 = 17

when we apply BODMAS RULE and round it off, we get => 25 + 19 - ( 26/ 21 ) * 22 = 25 + 19 - 1* 22 = 17

11. The ratio of number of boys and girls in a school of 720 students is 7:5. How many more girls should be admitted to make the ratio 1:1?

Explanation:

Given, boys : girls = 7 : 5

Let, the total number of boys = 7x

and total number of girls= 5x

Given, total students = 720

=> 7x + 5x = 720

=> 12x = 720

=> x = 60

so, total number of boys = 7x = 7 * 60 = 420

and total number of girls= 5x = 5 * 60 = 300

Let "y" be the number of girls added to make the ratio 1 : 1

=> 420 / (300 + y) = 1/1

=> 420 = (300 + y)

=> y = 420 - 300

=> y = 120

So, 120 more girls should be admitted to make the ratio** 1:1**

Let, the total number of boys = 7x

and total number of girls= 5x

Given, total students = 720

=> 7x + 5x = 720

=> 12x = 720

=> x = 60

so, total number of boys = 7x = 7 * 60 = 420

and total number of girls= 5x = 5 * 60 = 300

Let "y" be the number of girls added to make the ratio 1 : 1

=> 420 / (300 + y) = 1/1

=> 420 = (300 + y)

=> y = 420 - 300

=> y = 120

So, 120 more girls should be admitted to make the ratio

12. How much part of a day is 45 minutes ?

Explanation:

45 minutes = 3/4 of an hour.

An hour = 1 / 24 of day 3/4 of hour

= 3/ (4 x 24) of day

= 1/32 of the day.

An hour = 1 / 24 of day 3/4 of hour

= 3/ (4 x 24) of day

= 1/32 of the day.

13. 8988 / 8 / 4 = ?

Explanation:

Given Exp. = 8988 x 1/8 x 1/4 = 2247 / 8 = 280.875

14. In the below given sequence, what should be the Missing number ?

25, 44.7, 64.4, X , 103.8, 123.5

25, 44.7, 64.4, X , 103.8, 123.5

Explanation:

The given series is -- 25, 44.7, 64.4, X , 103.8, 123.5

Consecutive numbers increases by 19.7

Following this pattern, the Missing Number X should increase by 19.7 from the previous number.

When we add 19.7 to the number before X (i.e 64.4) we get 64.4+19.7=84.1

Consecutive numbers increases by 19.7

Following this pattern, the Missing Number X should increase by 19.7 from the previous number.

When we add 19.7 to the number before X (i.e 64.4) we get 64.4+19.7=84.1

15. A total amount of Rs. 1800 is to be divided among A,B and C in such a way that half of A’s part, one third of B’s part and one fourth of C’s part is equal. Then A’s part is :

Explanation:

Given, A + B +C = 1800 ----> (1)

(1/2) A = (1/3) B = (1/4) C

=> B = (3/2) A -----> (2)

and C = (4/2) A -----> (3)

Substitute (2) and (3) in (1) => A + (3/2)A + (4/2)A = 1800

=> (2A + 3A + 4A) / 2 = 1800

=> 9A = 1800 * 2

=> A = 200 * 2

=> A = 400

16. Area of the base of a cuboid 49 sq m, area of side face and other side face are 64 sq m and 25 sq m respectively. Find the volume of the cuboid.

Explanation:

Let l, b and h be the length, breadth and height of the cuboid respectively.

According to given data, Area of the base of a cuboid = l x b = 49 , ----> (1)

Area of the one side face = b x h = 64 ------> (2)

Area of the other side face = h x l = 25 -----> (3)

On multiplying the above equations we get

l x b x b x h x l x h = 49 x 64 x 25

=> (l x b x h)^2 = 49 x 64 x 25

=> l x b x h = 7 x 8 x 5 = 280

Volume of the cuboid = l x b x h = 280

According to given data, Area of the base of a cuboid = l x b = 49 , ----> (1)

Area of the one side face = b x h = 64 ------> (2)

Area of the other side face = h x l = 25 -----> (3)

On multiplying the above equations we get

l x b x b x h x l x h = 49 x 64 x 25

=> (l x b x h)^2 = 49 x 64 x 25

=> l x b x h = 7 x 8 x 5 = 280

Volume of the cuboid = l x b x h = 280

17. Find the next number in the the below series

17, 22, 30, 41, _____

17, 22, 30, 41, _____

Explanation:

In the given series, 17, 22, 30, 41 ,

Consecutive numbers increase by 5 ,8 ,11.

Following the same pattern, the next number should increase by 14.

When we add 14 to the last number (i.e 41) we get 14+41=55

Consecutive numbers increase by 5 ,8 ,11.

Following the same pattern, the next number should increase by 14.

When we add 14 to the last number (i.e 41) we get 14+41=55

18. Can you find the answer for the below equation

73 - 152 * 157 + 160 / 149

73 - 152 * 157 + 160 / 149

Explanation:

Given Question is 73 - 152 * 157 + 160 / 149

when we apply BODMAS RULE to the above question, we get 73 - 152 * 157+ ( 160/ 149 ) = 73 - 152 * 157+ 1.07 = -23789.93

when we apply BODMAS RULE to the above question, we get 73 - 152 * 157+ ( 160/ 149 ) = 73 - 152 * 157+ 1.07 = -23789.93

19. If the radius of two circles are in the ratio 3 : 4 then the ratio of their areas, will be

Explanation:

Let r1 and r2 be the radius of the circle. Ratio of the area = pi x r12 : pi x r22 = r12 : r22 = 3 x 3 : 4 x 4 = 9 : 16

20. In the below given sequence, what should be the Missing number ?

129, 104, 79, X , 29, 4

129, 104, 79, X , 29, 4

Explanation:

The given series is -- 129, 104, 79, X , 29, 4

Consecutive numbers decreases by 25

Following this pattern, the Missing Number X should decrease by 25 from the previous number.

When we subtract 25 to the number before X (i.e 79) we get 79--25=54

Consecutive numbers decreases by 25

Following this pattern, the Missing Number X should decrease by 25 from the previous number.

When we subtract 25 to the number before X (i.e 79) we get 79--25=54

21. Can you find the approximate value for the below equation

33.99 - 38.01 + 22.99 / 23.01 * 14.99

33.99 - 38.01 + 22.99 / 23.01 * 14.99

Explanation:

Given Question is 33.99 - 38.01 + 22.99 / 23.01 * 14.99

when we apply BODMAS RULE and round it off, we get => 34 - 38 + ( 23/ 23 ) * 15 = 34 - 38 + 1* 15 = 11

when we apply BODMAS RULE and round it off, we get => 34 - 38 + ( 23/ 23 ) * 15 = 34 - 38 + 1* 15 = 11

22. Can you find the answer for the below equation

92 + 84 - 96 / 85 * 83

92 + 84 - 96 / 85 * 83

Explanation:

Given Question is 92 + 84 - 96 / 85 * 83

when we apply BODMAS RULE to the above question, we get (Bracket Of Division) 92 + 84 - ( 96/ 85 ) * 83 = 92 + 84 - 1.12* 83 = 82.26

when we apply BODMAS RULE to the above question, we get (Bracket Of Division) 92 + 84 - ( 96/ 85 ) * 83 = 92 + 84 - 1.12* 83 = 82.26

23. What should come in place of _____ in the below number series?

173, 149, 125, 101, _____

173, 149, 125, 101, _____

Explanation:

The given series is -- 173, 149, 125, 101

Consecutive numbers decreases by 24

Following this pattern, the Missing Number should decrease by 24 from the previous number.

When we subtract 24 to the last number (i.e 101) we get 101--24=77

Consecutive numbers decreases by 24

Following this pattern, the Missing Number should decrease by 24 from the previous number.

When we subtract 24 to the last number (i.e 101) we get 101--24=77

24. In the first 35 overs of a cricket game, the run rate was only 6.4. What should be the run rate in the remaining 15 overs to reach the target of 410 runs?

Explanation:

Required Run rate = ( 410 - ( 6.4 x 35 ) )/ (15)

= ( 186) /(15) = 12.4

= ( 186) /(15) = 12.4

25. Can you find the answer for the below equation

146 / 372 * 362 + 367 - 358

146 / 372 * 362 + 367 - 358

Explanation:

Given Question is 146 / 372 * 362 + 367 - 358

when we apply BODMAS RULE to the above question, we get (Bracket Of Division)

=( 146 / 372 ) * 362 + 367 - 358

= 0.39*362+367-358

= 151.08.

when we apply BODMAS RULE to the above question, we get (Bracket Of Division)

=( 146 / 372 ) * 362 + 367 - 358

= 0.39*362+367-358

= 151.08.

26. In the first 25 overs of a cricket game, the run rate was only 1.3. What should be the run rate in the remaining 25 overs to reach the target of 287 runs?

Explanation:

Required Run rate = ( 287 - ( 1.3 x 25 ) )/ (25)
= ( 254.5) /(25) = 10.18

27. In the trapezium ABCD, find the sum of the angle A and D

28. If two numbers are in the ratio 6: 13 and their least common multiple is 312, the sum of the numbers is

Explanation:

Let the two numbers be 6k and 13k

LCM of 6k and 13k = 78k 78k = 312 => k = 4

Sum of the numbers 6k + 13k = 19k = 76

LCM of 6k and 13k = 78k 78k = 312 => k = 4

Sum of the numbers 6k + 13k = 19k = 76

29. Can you find the answer for the below equation

15 * 56 - 48 / 55 + 50

15 * 56 - 48 / 55 + 50

Explanation:

Given Question is 15 * 56 - 48 / 55 + 50

when we apply BODMAS RULE to the above question, we get (Bracket Of Division) 15 * 56 - ( 48/ 55 ) + 50 = 15 * 56 - 0.87+ 50 = 889.13

when we apply BODMAS RULE to the above question, we get (Bracket Of Division) 15 * 56 - ( 48/ 55 ) + 50 = 15 * 56 - 0.87+ 50 = 889.13

30. What should come in place of X in the below number series?

77, 62, 47, X , 17, 2

77, 62, 47, X , 17, 2

Explanation:

The given series is -- 77, 62, 47, X , 17, 2

Consecutive numbers decreases by 15

Following this pattern, the Missing Number X should decrease by 15 from the previous number.

When we subtract 15 to the number before X (i.e 47) we get 47--15=32

Consecutive numbers decreases by 15

Following this pattern, the Missing Number X should decrease by 15 from the previous number.

When we subtract 15 to the number before X (i.e 47) we get 47--15=32

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