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Aptitude Questions And Answers Sample Test 5


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Aptitude Test 5


You have scored 3 out of 10
You Scored:2
Total Questions:2
Attended Questions:2
Correct Answered:2
1. A person invested in all Rs.2600 at 4%,6% and 8% p.a. simple interest .At the end of the year ,he got the same interest in all the three cases .The money invested at 4% is:



Explanation:

Let x , y and x be his investments at 4%, 6% and 8% respectively

Simple Interest on x at 4% for 1 year = Simple Interest on y at 6% for 1 year= Simple Interest on z at 8% for 1 year
=> x * 4 * 1 / 100 = y * 6 * 1 / 100 = z * 8 * 1 / 100
=> 4x = 6y = 8z
=> 2x = 3y = 4z
Hence we have y = 2x / 3, z = 2x / 4 => x /2

We know that x + y + z = 2600
x + 2x / 3 + x / 2 = 2600
=> 6 x + 4x + 3x = 2600
=> 13 x = 2600 x 6
=> x = 2600 x 6 / 13
=> x = 200 x 6
=> x = 1200

Money invested at 4% = Rs.1200


2. Find the next number in the the below series

6, 19, 39, 66, _____



Explanation:

In the given series, 6, 19, 39, 66 ,

Consecutive numbers increase by 13 ,20 ,27.

Following the same pattern, the next number should increase by 34.

When we add 34 to the last number (i.e 66) we get 34+66=100


3. If the number 517*324 is completely divisible by 3, then the smallest whole number in the place of * will be:



Explanation:

Sum of digits = (5 + 1 + 7 + x + 3 + 2 + 4) = (22 + x), which must be divisible by 3. x = 2.


4. Can you find the answer for the below equation

101 / 287 - 283 + 284 * 279



Explanation:

Given Question is 101 / 287 - 283 + 284 * 279
when we apply BODMAS RULE to the above question, we get (Bracket Of Division) ( 101 / 287 ) - 283 + 284 * 279 = 0.35-283+284*279 = 78953.35


5. Evaluate: x^3 - 6x^2 + 11x - 7 when x = 2



Explanation:

Substitute x = 2 in the given eqn: x^3 - 6x^2 + 11x – 7
=> (2)^3 – 6*(2)^2 + 11*(2) – 7
= 8 – 24 + 22 – 7
= -1


6. 555 + 55 – 444 + 333 – 9 =?



Explanation:

555 + 55 – 444 + 333 – 9 = (555 + 55 + 333) – (444 + 9)
= 943 – 453
= 490


7. Sam walks in a Rectangle shaped park. Sam observes the length and breadth to be 10m & 5m respectively. To plough the given Rectangle Park, a merchant charges Rs.12 per Sq.m. How much money have to be paid to the merchant?



Explanation:

Given Length = 10m & Breadth = 5m
Area of Rectangle = Length x Breadth => 10 x =5 = 50
Price = Area x Cost Per Sq.m = 50 x 12 = 600


8. Find the next number in the the below series

27, 42, 58, 75, _____



Explanation:

In the given series, 27, 42, 58, 75 ,

Consecutive numbers increase by 15 ,16 ,17.

Following the same pattern, the next number should increase by 18.

When we add 18 to the last number (i.e 75) we get 18+75=93


9. Find the next number in the the below series

7, 22, 39, 58, _____



Explanation:

In the given series, 7, 22, 39, 58 ,

Consecutive numbers increase by 15 ,17 ,19.

Following the same pattern, the next number should increase by 21.

When we add 21 to the last number (i.e 58) we get 21+58=79


10. Length and breadth of a rectangular plot is 35m & 46m respectively. Find the difference between area and perimeter  ?



Explanation:

Difference between area & perimeter = (length x breadth ) - (2 x (length + breadth) )
= (35 * 46) - (2 ( 35 + 46))
= 1610 - ( 2 * 81)
= 1610 - 162
= 1448


11. A train overtakes two persons who are walking in the same direction in which the train is going, at the rate of 2 kmph and 4 kmph and passes them completely in 9 and 10 seconds respectively. The length of the train is:



Explanation:

2 kmph = ( 2x 5/18 ) m/sec = 5/9 m/sec 4 kmph = ( 4x 5/18 ) m/sec = 10/9 m/sec Let the length of the train be x metres and its speed by y m/sec. Then, ( x / y - 5/9 ) = 9 and ( x / y - 10 /9 ) = 10 . Therefore 9y - 5 = x and 10(9y - 10) = 9x => 9y - x = 5 and 90y - 9x = 100. On solving, we get: x = 50. Therefore Length of the train is 50 m.


12. Can you find out the approximate value for the following expression:

9228.789 − 5021.832 + 1496.989 = ?



Explanation:

Given expression is:
9228.789 − 5021.832 + 1496.989 = ?

On taking the round-off values, we get,
9230 − 5020 + 1500 = ?
= 4210 + 1500
= 5710
The nearest value in the given options is 5700.
So the number is 5700


13. Given tan x + cot x = 2 , then evaluate the expression tan^ 6 (x) + cot^ 6 (x) = ? 



Explanation:

Given, tan x + cot x = 2
Since, cot x = 1/ tan x
=> tan x + (1/tan x) = 2
=> (tan^2 x + 1) / tan x = 2
=> tan^2 x + 1 = 2 tan x
=> tan^2 x - 2 tan x + 1 = 0
=> (tan x - 1)^2 = 0
=> (tan x - 1) = 0
=> tan x = 1

Now, tan^6 (x) + cot^6 (x) = tan^6 (x) + (1/tan^6 x)
= (tan x)^6 + (1/tan x)^6
On substituting tan x = 1 in the above expression, we get
= (1)^6 + (1/1)^6
= 1 + 1
=> tan^6 (x) + cot^6 (x) = 2


14. Find the interest on Rs. 800 at 10% per annum for 219 days. 



Explanation:

Principal, p = 800 Rs.
Rate of interest, r = 10% and
t = 219 days = 219/365 years

Simple interest = p x t x r / 100
= (800 x 219 x 10) / (365 x 100)
= (800 x 3 x 10) / ( 5 x 100)
= (8 x 3 x 10) / 5
= 240/5
= 48
Interest to be paid is 48 Rs


15. Can you find the answer for the below equation

41 / 37 + 39 - 36 * 35



Explanation:

Given Question is 41 / 37 + 39 - 36 * 35
when we apply BODMAS RULE to the above question, we get (Bracket Of Division) ( 41 / 37 ) + 39 - 36 * 35 = 1.1+39-36*35 = -1219.89


16. Find the value of sec x, if sec x + tanx = 3





17. In an arithmetic progression the first term is 8 and its common difference is 3. If the general term is an, find a42 - a31.



Explanation:

Given a = 8 and common difference = 3.
General Term an = a +(n-1)d => an = 8 + 3(n-1) = 3n + 5
a42 = 126 + 5=131
a31 = 93 + 5 = 98
a42 - a31 = 33


18. Can you find the approximate value for the below equation

64.99 / 59.99 + 58.01 * 57.99 - 54.01



Explanation:

Given Question is 64.99 / 59.99 + 58.01 * 57.99 - 54.01
when we apply BODMAS RULE and round it off, we get => ( 65 / 60 ) + 58 * 58 - 54 = 1+58*58-54 = 3311


19. Area of the base of a cuboid 9 sq m, area of side face and other side face are 16 sq m and 25 sq m respectively. Find the volume of the cuboid



Explanation:

Let l, b and h be the length, breadth and height of the cuboid respectively.
Given, Area of the base of a cuboid = l x b = 9 , Area of the side face = b x h = 16 Area of the other side face = h x l = 25
On multiplying the above equations we get l x b x b x h x l x h = 9 x 16 x 25 (l x b x h)^2 = 9 x 16 x 25 l x b x h = 3 x 4 x 5 = 60
Volume of the cuboid = l x b x h = 60


20. One Side of a Square measures 15 units. Can you find the Sum of Area and Perimeter of the square ?



Explanation:

Sum of area & perimeter = (length x breadth ) + (2 x (length + breadth) )


21. In an arithmetic progression the first term is 9 and its common difference is 6. If the general term is an , find a17 - a11.



Explanation:

Given a = 9 and common difference = 6.
General Term an = a +(n-1)d => an = 9 + 6(n-1) = 6n + 3
a17 = 102 + 3=105
a11 = 66 + 3 = 69
a17 - a11 = 36


22. Can you find the approximate value for the below equation

57.01 * 77.01 / 63.99 - 74.99 + 65.01 



Explanation:

Given Question is 57.01 * 77.01 / 63.99 - 74.99 + 65.01
when we apply BODMAS RULE and round it off, we get => 57 * ( 77 / 64 ) - 75 + 65 = 57 * 1- 75 + 65 = 59


23. Find the simple interest on Rs. 1900 at 21 % per annum for 6 years



Explanation:

Principal : 1900 Rate of interest : 21 Number of years : 6 Simple Interest = pnr/100 Simple Interest = (1900 x 6 x 21) / 100 Simple Interest = 2394


24. Can you find the approximate value for the below equation

121.99 - 126.01 + 110.99 / 111.01 * 102.99



Explanation:

Given Question is 121.99 - 126.01 + 110.99 / 111.01 * 102.99
when we apply BODMAS RULE and round it off, we get => 122 - 126 + ( 111/ 111 ) * 103 = 122 - 126 + 1* 103 = 99


25. Petrol & Kerosene are mixed in the ratio of 3:8. Total Volume of the mixture is 300 litres. Find the composition of Petrol in the overall mixture? 



Explanation:

Given Petrol & Kerosene are in the ratio of 3:8
Given volume of mixture = 300 litres
Quantity of Petrol = 3/(3+8) x 300 = 81.82


26. Can you find the answer for the below equation

106 * 192 + 190 / 193 - 192



Explanation:

Given Question is 106 * 192 + 190 / 193 - 192
when we apply BODMAS RULE to the above question, we get (Bracket Of Division) 106 * 192 + ( 190/ 193 ) - 192 = 106 * 192 + 0.98- 192 = 20160.98


27. Can you find the answer for the below equation

98 / 278 - 274 + 275 * 270



Explanation:

Given Question is 98 / 278 - 274 + 275 * 270
when we apply BODMAS RULE to the above question, we get (Bracket Of Division) ( 98 / 278 ) - 274 + 275 * 270 = 0.35-274+275*270 = 73976.35


28. Find the volume of a cuboid with dimension 22 cm by 12 cm by 7.5 cm



Explanation:

Length of the cuboid be l, breadth of the cuboid be b and height of the cuboid be h.
Volume of the cuboid is, V = l x b x h V = 22 x 12 x 7.5 = 1980 cu cm.


29. Can you find the approximate value for the below equation

97.01 + 90.99 - 98.01 / 92.99 * 94.01 



Explanation:

Given Question is 97.01 + 90.99 - 98.01 / 92.99 * 94.01
when we apply BODMAS RULE and round it off, we get => 97 + 91 - ( 98/ 93 ) * 94 = 97 + 91 - 1* 94 = 89


30. Which number should come in place of the missing Number ?

67, 86, 105, X , 143, 162



Explanation:

The given series is -- 67, 86, 105, X , 143, 162
Consecutive numbers increases by 19
Following this pattern, the Missing Number X should increase by 19 from the previous number.
When we add 19 to the number before X (i.e 105) we get 105+19=124




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