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Sample Aptitude Test 5 for you to Practice. Evaluate your Aptitude Test 5 test answering skills by trying the online Aptitude Sample Test 5 and know your score.

You have scored 3 out of 10

You Scored:2

Total Questions:2

Attended Questions:2

Correct Answered:2

1. Given | x - 7 | < 1 , then find the values what x can take?

Explanation:

Given | x - 7 | < 1

=> -1 < x-7 < 1

=> -1 + 7 < x < 1 + 7

=>**6 < x < 8**

=> -1 < x-7 < 1

=> -1 + 7 < x < 1 + 7

=>

2. Evaluate the expression : 3 + 6 - 10 / 4 + 3 * 2 - 2

3. What would be the compound interest accrued on an amount of 5000 Rs. at the end of 2 years at the rate of 16 % per annum?

Explanation:

Given principal = 5000

No. of years = 2

Rate of interest = 16

**Amount = P x (1+r/100)^n,**

= 5000 x (1+16/100)^2

= 5000 x (1 + 4/25)^2

= 5000 x (29 / 25)^2

= 5000 x (841 / 625)

=6728

=>**Amount = Rs.6728
Compound Interest = Amount - Principal**

= 6728 - 5000

Thus,Compound Interest = Rs.1728

4. Can you find the approximate value for the below equation

133.01 - 145.99 / 120.01 + 127.99 * 112.99

133.01 - 145.99 / 120.01 + 127.99 * 112.99

Explanation:

Given Question is 133.01 - 145.99 / 120.01 + 127.99 * 112.99

when we apply BODMAS RULE and round it off, we get => 133 - ( 146 / 120 ) + 128 * 113 = 133 - 1+ 128 * 113 = 14593

when we apply BODMAS RULE and round it off, we get => 133 - ( 146 / 120 ) + 128 * 113 = 133 - 1+ 128 * 113 = 14593

5. Can you find the answer for the below equation

37 * 218 / 204 - 215 + 206

37 * 218 / 204 - 215 + 206

Explanation:

Given Question is 37 * 218 / 204 - 215 + 206

when we apply BODMAS RULE to the above question, we get (Bracket Of Division) 37 * ( 218 / 204 ) - 215 + 206 = 37 * 1.06- 215 + 206 = 30.54

when we apply BODMAS RULE to the above question, we get (Bracket Of Division) 37 * ( 218 / 204 ) - 215 + 206 = 37 * 1.06- 215 + 206 = 30.54

6. A, B started a business by investing Rs.3000/- and Rs.5000/-. A is working and B is sleeping partner. A gets 10% of profits for managing, the rest being divided in proportion to their capitals out of a total profit of Rs.8,000/-. Then find the A's total.

Explanation:

Given, A's invested amount = Rs.3000/-

B's invested amount = Rs.5000/-

Then, A's share : B's share = 3 : 5

=>**Total parts = 3 + 5 = 8**

Given, Total profit = Rs.8000/-

From which A gets 10%

so, 10 % of 8000 = 800/-

**A's Salary = Rs.800/**-

Remaining profit amount = Rs.7200/-

Total parts = 8

8 parts -----> Rs.7200/-

1 part ------> Rs.900/-

A's share ===> Rs.900/- * 3 parts = Rs.2700/-

**A's total = A's share + A's salary**

= Rs.2700 + Rs.800

=** Rs.3500/-**

B's invested amount = Rs.5000/-

Then, A's share : B's share = 3 : 5

=>

Given, Total profit = Rs.8000/-

From which A gets 10%

so, 10 % of 8000 = 800/-

Remaining profit amount = Rs.7200/-

Total parts = 8

8 parts -----> Rs.7200/-

1 part ------> Rs.900/-

A's share ===> Rs.900/- * 3 parts = Rs.2700/-

= Rs.2700 + Rs.800

=

7. A train 800 m long is running at a speed of 78 km/hr. If it crosses a tunnel in 1 minute, then the length of the tunnel is:

Explanation:

Given, **Length of the train = 800 m**

Speed of the train = 78 km/hr (convert km/hr to m/sec)

= 78 * (5/18) m /sec

= 21.667 m /sec

=>**Speed of the train = 21.667 m /sec**

Time taken by the train to cross the tunnel = 1 min =**60 sec**

__To find the length of the tunnel:__

**Time taken by train to cross tunnel = (Length of tunnel + Length of train) / speed of the train**

=> 60 = (Length of tunnel + 800) / 21.667

=> 60 * 21.667 = Length of tunnel + 800

=> 1300 = Length of tunnel + 800

=> 1300 – 800 = Length of tunnel

=> 500 = Length of tunnel

**Thus, the Length of tunnel = 500 m**

Speed of the train = 78 km/hr (convert km/hr to m/sec)

= 78 * (5/18) m /sec

= 21.667 m /sec

=>

Time taken by the train to cross the tunnel = 1 min =

=> 60 = (Length of tunnel + 800) / 21.667

=> 60 * 21.667 = Length of tunnel + 800

=> 1300 = Length of tunnel + 800

=> 1300 – 800 = Length of tunnel

=> 500 = Length of tunnel

8. If a:b=5:12 and b:c=11:4 then find a:b:c

Explanation:

a:b = 5 x 11 : 12 x 11 = 55 : 132
b:c = 11 x 12 : 4 x 12 = 132 : 48

a:b:c = 55 : 132 : 48

a:b:c = 55 : 132 : 48

9. Petrol & Kerosene are mixed in the ratio of 7:10. Total Volume of the mixture is 500 litres. Find the composition of Petrol in the overall mixture?

Explanation:

Given Petrol & Kerosene are in the ratio of 7:10
Given volume of mixture = 500 litres
Quantity of Petrol = 7/(7+10) x 500
= 205.88

10. Can you find the approximate value for the below equation

Explanation:

11. Find the next number in the the below series

10, 20, 32, 46, _____

10, 20, 32, 46, _____

Explanation:

In the given series, 10, 20, 32, 46 ,

Consecutive numbers increase by 10 ,12 ,14.

Following the same pattern, the next number should increase by 16.

When we add 16 to the last number (i.e 46) we get 16+46=62

Consecutive numbers increase by 10 ,12 ,14.

Following the same pattern, the next number should increase by 16.

When we add 16 to the last number (i.e 46) we get 16+46=62

12. The sum of the digits of a two-digit number is 15 and the difference between the digits is 3. What is the two-digit number?

Explanation:

Let the ten's digit be x and unit's digit be y.

Then, x + y = 15 and x - y = 3 or y - x = 3.

Solving x + y = 15 and x - y = 3,

we get: x = 9, y = 6.

Solving x + y = 15 and y - x = 3, we get: x = 6, y = 9.

So, the number is either 96 or 69. Hence, the number cannot be determined

Then, x + y = 15 and x - y = 3 or y - x = 3.

Solving x + y = 15 and x - y = 3,

we get: x = 9, y = 6.

Solving x + y = 15 and y - x = 3, we get: x = 6, y = 9.

So, the number is either 96 or 69. Hence, the number cannot be determined

13. The profit earned by selling an article for Rs. 600 is equal to the loss incurred when the same article is sold for Rs. 400. What should be the sale price of the article for making 25% profit?

Explanation:

Let the cost price be Rs. k

Now, as per the question,

600 - k = k - 400

=> 2k = 1000

=>**k = 500**

Again, selling price of the article for making 25 % profit

= (500 x 125) /100

= 125 * 5

=**Rs. 625**

Now, as per the question,

600 - k = k - 400

=> 2k = 1000

=>

Again, selling price of the article for making 25 % profit

= (500 x 125) /100

= 125 * 5

=

14. Two tailors X and Y are paid a total of Rs. 550 per week by their employer. If X is paid 120 percent of the sum paid to Y, how much is Y paid per week?

Explanation:

Let, the sum paid to Tailor X per week be Rs. **X**

and the sum paid to Tailor Y per week be Rs.**Y**

Given, Two tailors X and Y are paid a total of Rs. 550 per week

=>** X + Y = 550 -**-->** eqn (1)**

Given, X is paid 120 percent of the sum paid to Y

=> X = 120 % of Y

=> X = (120 / 100) * Y

=>** X = (6 / 5) * Y**

On substituting this value for X in eqn (1), we get

=> (6 / 5) * Y + Y = 550

=> (6Y + 5Y) / 5 = 550

=> 11Y = 550 * 5

=> 11Y = 2750

=> Y = 2750 / 11

=>** Y = 250 Rs**.

Thus,**the sum paid to Tailor Y per week be Rs. 250**

and the sum paid to Tailor Y per week be Rs.

Given, Two tailors X and Y are paid a total of Rs. 550 per week

=>

Given, X is paid 120 percent of the sum paid to Y

=> X = 120 % of Y

=> X = (120 / 100) * Y

=>

On substituting this value for X in eqn (1), we get

=> (6 / 5) * Y + Y = 550

=> (6Y + 5Y) / 5 = 550

=> 11Y = 550 * 5

=> 11Y = 2750

=> Y = 2750 / 11

=>

Thus,

15. Can you find the answer for the below equation

59 + 65 * 61 - 63 / 67

59 + 65 * 61 - 63 / 67

Explanation:

Given Question is 59 + 65 * 61 - 63 / 67

when we apply BODMAS RULE to the above question, we get (Bracket Of Division) 59 + 65 * 61- ( 63/ 67 ) = 59 + 65 * 61- 0.94 = 4023.06

when we apply BODMAS RULE to the above question, we get (Bracket Of Division) 59 + 65 * 61- ( 63/ 67 ) = 59 + 65 * 61- 0.94 = 4023.06

16. What would be the compound interest accrued on an amount of 11500 Rs. at the end of 2 years at the rate of 10 % per annum ?

Explanation:

Given

Principal = 11500 No. of years = 2 Rate of interest = 10

**Amount = P x (1+r/100)^n, **

we get Amount = 11500 x (1+10/100)^2

= 11500 x ( 110 / 100 )^ 2

= 115 x 11 x 11

= 115 x 121

Ans :**13915**

Principal = 11500 No. of years = 2 Rate of interest = 10

we get Amount = 11500 x (1+10/100)^2

= 11500 x ( 110 / 100 )^ 2

= 115 x 11 x 11

= 115 x 121

Ans :

17. Can you find the answer for the below equation

121 * 722 / 708 - 719 + 710

121 * 722 / 708 - 719 + 710

Explanation:

Given Question is 121 * 722 / 708 - 719 + 710

when we apply BODMAS RULE to the above question, we get (Bracket Of Division) 121 * ( 722 / 708 ) - 719 + 710 = 121 * 1.01- 719 + 710 = 114.39

when we apply BODMAS RULE to the above question, we get (Bracket Of Division) 121 * ( 722 / 708 ) - 719 + 710 = 121 * 1.01- 719 + 710 = 114.39

18. Find the next number in the the below series

5, 26, 54, 89, _____

5, 26, 54, 89, _____

Explanation:

In the given series, 5, 26, 54, 89 ,

Consecutive numbers increase by 21 ,28 ,35.

Following the same pattern, the next number should increase by 42.

When we add 42 to the last number (i.e 89) we get 42+89=131

Consecutive numbers increase by 21 ,28 ,35.

Following the same pattern, the next number should increase by 42.

When we add 42 to the last number (i.e 89) we get 42+89=131

19. Can you find the approximate value for the below equation

36.99 + 40.01 * 37.99 - 44.01 / 46.01

36.99 + 40.01 * 37.99 - 44.01 / 46.01

Explanation:

Given Question is 36.99 + 40.01 * 37.99 - 44.01 / 46.01

when we apply BODMAS RULE and round it off, we get => 37 + 40 * 38- ( 44/ 46 ) = 37 + 40 * 38- 1 = 1556

when we apply BODMAS RULE and round it off, we get => 37 + 40 * 38- ( 44/ 46 ) = 37 + 40 * 38- 1 = 1556

20. Can you find the approximate value for the below equation

87.99 + 91.01 * 88.99 - 95.01 / 97.01

87.99 + 91.01 * 88.99 - 95.01 / 97.01

Explanation:

Given Question is 87.99 + 91.01 * 88.99 - 95.01 / 97.01

when we apply BODMAS RULE and round it off, we get => 88 + 91 * 89- ( 95/ 97 ) = 88 + 91 * 89- 1 = 8186

when we apply BODMAS RULE and round it off, we get => 88 + 91 * 89- ( 95/ 97 ) = 88 + 91 * 89- 1 = 8186

21. Can you find the answer for the below equation

92 - 144 + 152 / 153 * 144

92 - 144 + 152 / 153 * 144

Explanation:

Given Question is 92 - 144 + 152 / 153 * 144

when we apply BODMAS RULE to the above question, we get 92 - 144 + ( 152/ 153 ) * 144 = 92 - 144 + 0.99* 144 = 91.06

when we apply BODMAS RULE to the above question, we get 92 - 144 + ( 152/ 153 ) * 144 = 92 - 144 + 0.99* 144 = 91.06

22. Can you find the answer for the below equation

148 + 152 * 140 / 147 - 144

148 + 152 * 140 / 147 - 144

Explanation:

Given Question is 148 + 152 * 140 / 147 - 144

when we apply BODMAS RULE to the above question, we get (Bracket Of Division) 148 + 152 * ( 140/ 147 ) - 144 = 148 + 152 * 0.95- 144 = 148.76

when we apply BODMAS RULE to the above question, we get (Bracket Of Division) 148 + 152 * ( 140/ 147 ) - 144 = 148 + 152 * 0.95- 144 = 148.76

23. One Side of a Square measures 18 units. Can you find the Difference between Area and Perimeter of the square ?

Explanation:

Difference between area & perimeter = (Side x side ) - (4 x Side)

24. Find the next number in the the below series

10, 27, 46, 67, _____

10, 27, 46, 67, _____

Explanation:

In the given series, 10, 27, 46, 67 ,

Consecutive numbers increase by 17 ,19 ,21.

Following the same pattern, the next number should increase by 23.

When we add 23 to the last number (i.e 67) we get 23+67=90

Consecutive numbers increase by 17 ,19 ,21.

Following the same pattern, the next number should increase by 23.

When we add 23 to the last number (i.e 67) we get 23+67=90

25. If 23 % of "a" is 46, then "a" = ?

Explanation:

(23/100) x 46 = 200

26. A particular student has scored an average marks of 69.25 in all his 20 subjects. Find the Total Score he has obtained in all his subjects?

Explanation:

Use the below formula to find the Total, when Average and Total No. of Students is provided
Total = Average * Total Students/People
Total = Average * Total Number of Students)
Average Weight = ( 69.25 x 20) = 1385

27. Suppose triangle(ABC) be a right-angled triangle where angle(A) = 90 deg, and AD perpendicular to BC. If triangle(ABC) = 40 cm^2, triangle(ACD) = 10 cm^2 and AC = 9 cm, then the length of BC is

28. A began a business with Rs.5000/- and was joined afterwards by B with Rs.4000/-. If the profits at the end of the year were divided in the ratio 3:1, B joined the business after:?

Explanation:

1) Share's ratio is always equal to profit ratio

2) When two ratios are equal, then the cross products of the ratios are equal.

That is, for the proportion, a:b = c:d , a x d = b x c

**A **= 5000/- per 12 Months **B** = 4000/- per x Months 4000 * 12 : 5000 * 8 = 3 : 1

=> 6 : 5 = 3 : 1

=> 3x = 15

=>** x = 5 Months**

Then,**B **joined the** business after** = 12 - x ==> 12 - 5 ==> **after 7 Months.**

2) When two ratios are equal, then the cross products of the ratios are equal.

That is, for the proportion, a:b = c:d , a x d = b x c

=> 6 : 5 = 3 : 1

=> 3x = 15

=>

Then,

29. In the first 10 overs of a cricket game, the run rate was only 6.2. What should be the run rate in the remaining 40 overs to reach the target of 414 runs ?

Explanation:

Given

In, first 10 overs of a cricket game.

Run rate = 6.2

Required Run rate in the remaining 40 overs to reach the target of 414 runs

Required Run rate

=( 414 - ( 6.2 x 10 ) / (40)

= 414 - 6.20 / 40

= ( 352) / (40)

=**8.8**

In, first 10 overs of a cricket game.

Run rate = 6.2

Required Run rate in the remaining 40 overs to reach the target of 414 runs

Required Run rate

=( 414 - ( 6.2 x 10 ) / (40)

= 414 - 6.20 / 40

= ( 352) / (40)

=

30. Can you find the answer for the below equation

20 + 24 * 12 / 19 - 16

20 + 24 * 12 / 19 - 16

Explanation:

Given Question is 20 + 24 * 12 / 19 - 16

when we apply BODMAS RULE to the above question, we get (Bracket Of Division)

=20 + 24 * ( 12/ 19 ) - 16

= 20 + 24 * 0.63- 16

= 19.16.

when we apply BODMAS RULE to the above question, we get (Bracket Of Division)

=20 + 24 * ( 12/ 19 ) - 16

= 20 + 24 * 0.63- 16

= 19.16.

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