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Aptitude Test 4
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Aptitude Questions And Answers Sample Test 4
Sample Aptitude Test 4 for you to Practice. Evaluate your Aptitude Test 4 test answering skills by trying the online Aptitude Sample Test 4 and know your score.
Aptitude Test 4
You have scored 3 out of 10
You Scored:
2
Total Questions:
2
Attended Questions:
2
Correct Answered:
2
1. The labelled price of a product is Rs. 7500. If it is sold at 20% discount and the dealer earns 25% profit, Find its cost price.
Rs. 4800
Rs. 5000
Rs. 4400
Rs. 5200
None of These
Explanation:
Given,labelled price = Rs. 7500
Discount = 20% oflabelled price
=>
Discount Amount=
(20 / 100) * 7500 = 1500 Rs.
S.P =labelled price - Discount Amount
= 7500 - 1500
= 6000 Rs.
Given, Profit = 25 %
then,
Cost Price (C.P) = [100 / (100 + profit%)] * S.P
=>
C.P = (100/125) x 6000 = Rs. 4800
Thus, Cost price = Rs.4800
Workspace
2. Output of a particular program follows the below pattern. Can you find the Missing number?
112, 141, 170, X , 228, 257
198
197
201
199
None of these
Explanation:
The given series is -- 112, 141, 170, X , 228, 257
Consequtive numbers increases by 29
Following this pattern, the Missing Number X should increase by 29 from the previous number.
When we add 29 to the number before X (i.e 170) we get 170+29=199
Workspace
3. If two numbers are in the ratio 6: 13 and their least common multiple is 312, the sum of the numbers is
75
57
76
67
None of these
Explanation:
Let the two numbers be 6k and 13k
LCM of 6k and 13k = 78k 78k = 312 => k = 4
Sum of the numbers 6k + 13k = 19k = 76
Workspace
4. The average age of a group of 10 students was 14. The average age increased by 1 years when two new students joined the group. What is the average age of the two new students who joined the group?
20
10.5
14
14.5
11.5
Explanation:
The average age of a group of 10 students is 14. Therefore, the sum of the ages of all 10 of them = 10 * 14 = 140 When two students joins the group, the average increase by 1. New Average = 15 Now there are 12 students Therefore, sum of all the ages of 12 students = 180 Therefore, the sum of the ages of two students who joined = 180 - 140 = 40 And the average age of these two students = 20
Workspace
5. Fifth number is missing in the below series. Can you find the fifth number in the below series ?
179, 196, 213, 230, _____
246
245
249
247
None of these
Explanation:
The given series is -- 179, 196, 213, 230
Consecutive numbers increases by 17
Following this pattern, the Missing Number should increase by 17 from the previous number.
When we add 17 to the last number (i.e 230) we get 230+17=247
Workspace
6. Find the simple interest on Rs. 2000 at 7 % per annum for 2 years
Rs. 280
Rs. 260
Rs. 285
Rs. 292
None of These
Explanation:
Solution is
Given
Principal : 2000
Rate of interest : 7
Number of years : 2
Simple interest = pnr/100
Simple Interest = (2000 x 2 x 7) / 100
Simple Interest =
280
Answer is280
Workspace
7. Can you find the answer for the below equation
26 / 58 + 57 * 56 - 53
3145.45
3139.45
3143.45
3136.45
3141.45
Explanation:
Given Question is 26 / 58 + 57 * 56 - 53
when we apply BODMAS RULE to the above question, we get (Bracket Of Division) ( 26 / 58 ) + 57 * 56 - 53 = 0.44+57*56-53 = 3139.45
Workspace
8. Find the approximate value for the expression
47.003 - 58.998 + 27.001 / 33.999 * 6.002
-7
-17
-37
-27
None of these
Explanation:
Given Question is 47.003 - 58.998 + 27.001 / 33.999 * 6.002
when we apply BODMAS RULE to the above question,
Step - 1 : (Bracket Of Division) 47 - 59 + ( 27 / 34 ) * 6 = 47 - 59 + 0.794 * 6
Step - 2 : 47 - 59 + ( 0.794 * 6 ) = 47 - 59 + 4.764 = -7.24 = (approx) -7
Workspace
9. Can you find the approximate value for the below equation
117.99 / 112.99 + 111.01 * 110.99 - 107.01
12191
12215
12243
12199
12262
Explanation:
Given Question is 117.99 / 112.99 + 111.01 * 110.99 - 107.01
when we apply BODMAS RULE and round it off, we get => ( 118 / 113 ) + 111 * 111 - 107 = 1+111*111-107 = 12215
Workspace
10. Find the next number in the the below series
11, 30, 52, 77, _____
104
105
106
103
None of these
Explanation:
In the given series, 11, 30, 52, 77 ,
Consecutive numbers increase by 19 ,22 ,25.
Following the same pattern, the next number should increase by 28.
When we add 28 to the last number (i.e 77) we get 28+77=105
Workspace
11. Find the area of the circle whose center is (3,6) and it passes through (4,6)
pi
2 pi
3 pi
4 pi
None of the above
Workspace
12. Can you find the approximate value for the below equation
39.99 / 50.99 * 37.01 - 44.01 + 33.01
18
2
46
-6
65
Explanation:
Given Question is 39.99 / 50.99 * 37.01 - 44.01 + 33.01
when we apply BODMAS RULE and round it off, we get => ( 40 / 51 ) * 37 - 44 + 33 = 1*37-44+33 = 18
Workspace
13. What would be the compound interest accrued on an amount of 6500 Rs. at the end of 2 years at the rate of 15 % per annum ?
8589.25
8589.75
8596.25
2096.25
None of These
Explanation:
Solution is :
Given principal = 6500
No. of years = 2
Rate of interest = 15
Amount = P [ 1 + ( r / 100 )
^{n}
]
= 6500 x [ 1 + ( 15 /100 )
^{2}
]
= 6500 x [ 1 + ( 3 / 20 )
^{2}
]
= 6500 x [ 23 / 20 ]
^{2}
= 6500 x [ 529 / 400 ]
Amount =
8596.25
Compound Interest = Amount - Principal
= 8596.25 - 6500
= 2096.25
Workspace
14. If a:b=5:3, b:c=10:7 and c:d = 5:7 then find a:b:c:d
250 : 150 : 105 : 174
250 : 105 : 150 : 147
250 : 150 : 105 : 137
250 : 150 : 105 : 147
None of these
Explanation:
Solution is :
a : b = 5 x 10 : 3 x 10 = 50 : 30
b : c = 10 x 3 : 3 x 7 = 30 : 21
a : b : c = 50 : 30 : 21
a x 5 : b x 5 : c x 5 = 250 : 150 : 105
c : d = 5 : 7
c x 21 : d x 21 = 105 : 147
a : b : c : d = 250 : 150 : 105 : 147
Workspace
15. Find the value of tan x, if sec x + tanx = 15
(202/15)
(187/15)
(73/7)
(112/15)
None of these
Workspace
16. Can you find the answer for the below equation
155 * 708 / 697 + 706 - 699
170.45
161.45
164.45
168.45
166.45
Explanation:
Given Question is 155 * 708 / 697 + 706 - 699
when we apply BODMAS RULE to the above question, we get (Bracket Of Division) 155 * ( 708 / 697 ) + 706 - 699 = 155 * 1.01+ 706 - 699 = 164.45
Workspace
17. A football team won 10 games from the total they played. This was 40 % of the total. How many games were played in all?
25
30
20
50
None of these
Explanation:
Let k be the total number of games played.
Given, 40 % of k =10
=> (40 / 100) * k = 10
=> k = 10 * (100 / 40)
=> k = 100 / 4
=>
k = 25
Therefore,
total number of games played = 25
Workspace
18. Eight people are planning to share equally the cost of a rental car. If one person withdraws from the arrangement and the others share equally the entire cost of the car, then the share of each of the remaining persons increased by
One-ninth
One-eighth
One-seventh
Seven-eighths
None of these
Explanation:
When there are 8 people, the share of each person is 1/8 => (Original Share)
When there are 7 people, the share of each person is 1/7
Increase in the share of each person is 1/7 – 1/8 = 1 / 56
1 / 56 ==> Which is 1/7 of 1/8 ==>
1/7 of the original share of each person.
Workspace
19. If perimeter of a rectangle is 180 m and the difference between the length and the breadth is 8 metres, what is the area of the rectangle?
2116 sq m
2047 sq m
2090 sq m
2009 sq m
None of These
Explanation:
Let x = length of the rectangle and breadth = (x – 8) m
Given , perimeter of the rectangle = 180 m perimeter of the rectangle = 2 * (l+b) => 2(x + x - 8)= 180? => (2x - 8) = 90? =>2x = 90 + 8 = 98 => x = 49 m?
Breadth = 49 – 8 = 41 m
Area of the rectangle = l * b = 49 x 41 = 2009 sq. m
Workspace
20. The difference between compound interest and simple interest on an amount of Rs.15,000 for 2 years in Rs.96 .What is the rate of interest per annum?
10
12
8
9
None of these
Workspace
21. Find the approximate value for the expression
12.998 + 13.001 / 55.003 * 14.999 - 11.002
36
6
16
26
None of these
Explanation:
Given Question is 12.998 + 13.001 / 55.003 * 14.999 - 11.002
when we apply BODMAS RULE to the above question,
Step - 1 : (Bracket Of Division) 13 + ( 13 / 55 ) * 15 - 11 = 13 + 0.236 * 15 - 11
Step - 2 : 13 + ( 0.236 * 15 ) - 11 = 13 + 3.54 -11 = 5.54 = (approx) 6
Workspace
22. Find the approximate value for the expression
15.998 - 10.002 + 18.999 * 6.003 / 42.001
9
29
19
39
None of these
Explanation:
Given Question is 15.998 - 10.002 + 18.999 * 6.003 / 42.001 when we apply BODMAS RULE to the above question,
Step - 1 : (Bracket Of Division) 16 - 10 + 19 * ( 6 / 42 ) = 6 + 19 * 0.143 Step - 2 : 6 + ( 19 * 0.143 ) = 6 + 2.717 = 8.72 = (approx) 9
Workspace
23. Evaluate x^2 - 27 x + 180 at x = 15
130
-120
120
0
None of the above
Explanation:
Subs x = 15 in the given eqn x^2 - 27 x + 180
=> (15)^2 – 27*(15) + 180
=> 225 – 405 + 180
=> 405 – 405
=> 0
So, Ans is 0
Workspace
24. If a:b=3:10 and b:c=12:11 then find a:b:c
0.788888889
0.792303241
0.778668981
18:30:55
None of These
Explanation:
a:b = 3x 12 : 10x 12 = 36 : 120 b:c = 12x 10 : 11x 10 = 120 : 110 a:b:c = 36 : 120 : 110 a:b:c = 18 : 60 : 55
Workspace
25. Can you find the value for the expression:
(35)^2 / [(125)^ (1/3)] + (25)^2 / 125
200
250
100
150
None of the above
Explanation:
Given expression is
(35)^2 / [(125)^ (1/3)] + (25)^2 / 125
= (1225 / 5) + (625 / 125)
= 245 + 5
=
250
Workspace
26. Find the next number in the the below series
16, 43, 72, 103, _____
135
134
133
136
None of these
Explanation:
In the given series, 16, 43, 72, 103 ,
Consecutive numbers increase by 27 ,29 ,31.
Following the same pattern, the next number should increase by 33.
When we add 33 to the last number (i.e 103) we get 33+103=136
Workspace
27. 27^20 / 27^10 = 3^k, then k = ?
27
12
30
31
None of these
Explanation:
27^20 ? 27^10 = 3^k => 27^10 = 3^k => (3^3)10 = 3^k => 3^30 = 3^k.
Workspace
28. I. 8X^2 + 22X + 15= 0
II. 4Y^2 + 16Y + 15 = 0
If X > Y
If X < Y
If X >= Y
If X <= Y
If X = Y or relation cannot be established
Explanation:
(4x+5)(2x+3) =0
X=-5/4, -3/2
(2y+5)(2xy+3) =0
y=-5/2, -3/2
-5/4,-3/2,-3/2,-5/3 => xxyy
X >= Y
Workspace
29. Find the next number in the the below series
22, 40, 59, 79, _____
101
102
100
97
None of these
Explanation:
In the given series, 22, 40, 59, 79 ,
Consecutive numbers increase by 18 ,19 ,20.
Following the same pattern, the next number should increase by 21.
When we add 21 to the last number (i.e 79) we get 21+79=100
Workspace
30. The labelled price of a product is Rs. 3000. If it is sold at 20% discount and the dealer earns 25% profit, Find its cost price.
Rs. 1920
Rs. 1940
Rs. 1960
Rs. 1820
None of these
Explanation:
S.P of the product = (80/100) x 3000 = Rs. 2400
Proft = 25 % => C.P = (100/125) x 2400 = Rs. 1920
Workspace
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