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Sample Aptitude Test 3 for you to Practice. Evaluate your Aptitude Test 3 test answering skills by trying the online Aptitude Sample Test 3 and know your score.

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You Scored:2

Total Questions:2

Attended Questions:2

Correct Answered:2

1.

**Question: **What is Nitin's rank from the top in a class of forty students?

**Statements:**

- There are ten students between Nitin and Deepak.
- Deepak is twentieth from the top.

Explanation:

Since there are ten students between Nitin and Deepak, so Nitin may be eleven ranks above or below Deepak.

Thus, Nitin may be**9th or 31st** from the top.

The exact rank of Nitin can’t be found from both the given statements.

Therefore,**Neither Statement I nor Statement II is sufficient** to answer.

Thus, Nitin may be

The exact rank of Nitin can’t be found from both the given statements.

Therefore,

2. Compute : 14% of 3602 + 63 % of 3414.

Explanation:

14 % of 3602 = 504.28
63 % of 3414 = 2150.82
Adding these two values we get = 2655.1

3. Evaluate the expression :

2 + 2 - 2 +33 - 33 / 3 * 3 - 3

2 + 2 - 2 +33 - 33 / 3 * 3 - 3

4. Given a Square whose diagonal is 45 units. Painter charges Rs.40 per Sq.units. Find the cost to Paint the Square?

Explanation:

Given diagonal is 45 units

Area of Square = (Diagonal^2) / 2 => (45^2)/2 =1012.5

Price = Area x Cost Per Sq.units = 1012.5 x 40 = 40500

Area of Square = (Diagonal^2) / 2 => (45^2)/2 =1012.5

Price = Area x Cost Per Sq.units = 1012.5 x 40 = 40500

5. What is 11.5% of 5000?

Explanation:

11.5% of 5000

= (11.5/100 ) x 5000

= 575

Answer is

6. Find the volume of the prism which has base area 21 sq. units and height to be given as 12units.

7. What principal will amount to Rs. 16000 in 6 years at 10% simple interest?

Explanation:

Let the principal be Rs. p,

Rate of interest is 10% and time = 6 years.

Amount received at the end of 6 years = 16000 Rs.

**Amount = Principal + S.I = p + (p x r x t)/100**

= 16000 = p + (p x 10 x 6) / 100

= p + 6p/10

= 16p/10 P

= 16000 x (10/16)

= 1000 x 10

= 10000 Rs.

**Principal = Rs. 10000.**

Rate of interest is 10% and time = 6 years.

Amount received at the end of 6 years = 16000 Rs.

= 16000 = p + (p x 10 x 6) / 100

= p + 6p/10

= 16p/10 P

= 16000 x (10/16)

= 1000 x 10

= 10000 Rs.

8. Which number should come in place of the missing Number ?

95, 114, 133, X , 171, 190

95, 114, 133, X , 171, 190

Explanation:

The given series is -- 95, 114, 133, X , 171, 190

Consecutive numbers increases by 19

Following this pattern, the Missing Number X should increase by 19 from the previous number.

When we add 19 to the number before X (i.e 133) we get 133+19=152

Consecutive numbers increases by 19

Following this pattern, the Missing Number X should increase by 19 from the previous number.

When we add 19 to the number before X (i.e 133) we get 133+19=152

9. Can you find the answer for the below equation

150 + 156 / 142 - 144 * 149

150 + 156 / 142 - 144 * 149

Explanation:

Given Question is 150 + 156 / 142 - 144 * 149

when we apply BODMAS RULE to the above question, we get (Bracket Of Division) 150 + ( 156 / 142 ) - 144 * 149 = 150 + 1.09- 144 * 149 = -21304.9

when we apply BODMAS RULE to the above question, we get (Bracket Of Division) 150 + ( 156 / 142 ) - 144 * 149 = 150 + 1.09- 144 * 149 = -21304.9

10. Find the next number in the the below series

7, 27, 50, 76, _____

7, 27, 50, 76, _____

Explanation:

In the given series, 7, 27, 50, 76 ,

Consecutive numbers increase by 20 ,23 ,26.

Following the same pattern, the next number should increase by 29.

When we add 29 to the last number (i.e 76) we get 29+76=105

Consecutive numbers increase by 20 ,23 ,26.

Following the same pattern, the next number should increase by 29.

When we add 29 to the last number (i.e 76) we get 29+76=105

11. Evaluate: sin(17) cos(73)+sin(73) cos (17)

Explanation:

Given expression is: sin(17) cos(73)+sin(73) cos (17)

By the Formula:

**sin A cos B + cos A sin B = sin (A + B)**

Here, A = 17 and B = 73

=> sin(17) cos(73)+sin(73) cos (17) = sin (17 + 73)

= sin (90)

= 1

**Thus, sin(17) cos(73)+sin(73) cos (17) = 1**

By the Formula:

Here, A = 17 and B = 73

=> sin(17) cos(73)+sin(73) cos (17) = sin (17 + 73)

= sin (90)

= 1

12. Output of a particular program follows the below pattern. Can you find the Missing number ?

79, 94, 109, X , 139, 154

79, 94, 109, X , 139, 154

Explanation:

The given series is -- 79, 94, 109, X , 139, 154

Consecutive numbers increases by 15

Following this pattern, the Missing Number X should increase by 15 from the previous number.

When we add 15 to the number before X (i.e 109) we get 109+15=124

Consecutive numbers increases by 15

Following this pattern, the Missing Number X should increase by 15 from the previous number.

When we add 15 to the number before X (i.e 109) we get 109+15=124

13. In an arithmetic progression the first term is 9 and its common difference is 3. If the general term is (a_n) , find a_41 - a_24.

Explanation:

Given a = 9 and common difference = 3.

General Term a_n = a +(2n-1)d a - n

= 9 + 3(2n-1)

= 3n + 6 a -41

=> 123 + 6 = 129 a - 24

= 72 + 6

= 78 a - 24

**a = 51**

General Term a_n = a +(2n-1)d a - n

= 9 + 3(2n-1)

= 3n + 6 a -41

=> 123 + 6 = 129 a - 24

= 72 + 6

= 78 a - 24

14. Find the Missing number in the the below series

133, 160, 187, X , 241, 268

133, 160, 187, X , 241, 268

Explanation:

The given series is -- 133, 160, 187, X , 241, 268

Consecutive numbers increases by 27

Following this pattern, the Missing Number X should increase by 27 from the previous number.

When we add 27 to the number before X (i.e 187) we get 187+27=214

Consecutive numbers increases by 27

Following this pattern, the Missing Number X should increase by 27 from the previous number.

When we add 27 to the number before X (i.e 187) we get 187+27=214

15. In the given series, can you find the Missing number?

143, 120, 97, X , 51, 28

143, 120, 97, X , 51, 28

Explanation:

The given series is -- 143, 120, 97, X , 51, 28

Consecutive numbers**decreases by 23**

Following this pattern, the Missing Number X should decrease by 23 from the previous number.

When we subtract 23 to the number before X (i.e 97) we get 97 - 23 = 74

Consecutive numbers

Following this pattern, the Missing Number X should decrease by 23 from the previous number.

When we subtract 23 to the number before X (i.e 97) we get 97 - 23 = 74

16. The average of 12 numbers is zero. Of them, at the most how many may be greater than zero?

Explanation:

Average of 12 numbers is = 0

Therefore sum of all 12 numbers = 0

It is quite possible that 11 of these numbers may be positive and if their sum is "a" then 12th number is "(-a)"

Therefore sum of all 12 numbers = 0

It is quite possible that 11 of these numbers may be positive and if their sum is "a" then 12th number is "(-a)"

17. Ram and Shyam can complete a work together in 20 days. If Ram alone complete the work in 36 days, find the number of days Shyam alone will take to complete the task.

Explanation:

Let the time taken by Ram alone to complete the work = R days = 36 days

the time taken by Shyam alone to complete the work = S days

Given, the time taken by Ram and Shyam = R + S days = 20 days

=>**1/(R + S) = (1/R) + (1/S)**

=> 1 / 20 = (1 / 36) + (1 / S)

=> 1 / S = (1 / 20) - (1 / 36)

=> 1 / S = (36 - 20) / (20 * 36)

=> 1 / S = 16 / 720

Taking reciprocal on both sides

=> S = 720 / 16

**=> S = 45 days.**

Thus,**the time taken by Shyam alone to complete the work = 45 days.**

the time taken by Shyam alone to complete the work = S days

Given, the time taken by Ram and Shyam = R + S days = 20 days

=>

=> 1 / 20 = (1 / 36) + (1 / S)

=> 1 / S = (1 / 20) - (1 / 36)

=> 1 / S = (36 - 20) / (20 * 36)

=> 1 / S = 16 / 720

Taking reciprocal on both sides

=> S = 720 / 16

Thus,

18. Can you find the answer for the below equation

21 + 14 - 16 * 18 / 22

21 + 14 - 16 * 18 / 22

Explanation:

Given Question is 21 + 14 - 16 * 18 / 22

when we apply BODMAS RULE to the above question, we get (Bracket Of Division) 21 + 14 - 16* ( 18/ 22 ) = 21 + 14 - 16* 0.81 = 21.91

when we apply BODMAS RULE to the above question, we get (Bracket Of Division) 21 + 14 - 16* ( 18/ 22 ) = 21 + 14 - 16* 0.81 = 21.91

19. Below Numbers follow a particular pattern. Can you find the Missing number in the below pattern?

83, 94, 105, X , 127, 138

83, 94, 105, X , 127, 138

Explanation:

The given series is -- 83, 94, 105, X , 127, 138

Consecutive numbers increases by 11

Following this pattern, the Missing Number X should increase by 11 from the previous number.

When we add 11 to the number before X (i.e 105) we get 105+11=116

Consecutive numbers increases by 11

Following this pattern, the Missing Number X should increase by 11 from the previous number.

When we add 11 to the number before X (i.e 105) we get 105+11=116

20. Can you find the answer for the below equation

53 / 112 + 111 * 110 - 107

53 / 112 + 111 * 110 - 107

Explanation:

Given Question is 53 / 112 + 111 * 110 - 107

when we apply BODMAS RULE to the above question, we get (Bracket Of Division) ( 53 / 112 ) + 111 * 110 - 107 = 0.47+111*110-107 = 12103.47

when we apply BODMAS RULE to the above question, we get (Bracket Of Division) ( 53 / 112 ) + 111 * 110 - 107 = 0.47+111*110-107 = 12103.47

21. If sum of two angles in a cyclic quadrilateral is 165 degree, then the sum of the other two angles is = ?

22. Find the curved surface area of the cone if the radius and height are 2 units and 16 units respectively.

23. Can you find the answer for the below equation

70 - 100 + 108 / 109 * 100

70 - 100 + 108 / 109 * 100

Explanation:

Given Question is 70 - 100 + 108 / 109 * 100

when we apply BODMAS RULE to the above question, we get 70 - 100 + ( 108/ 109 ) * 100 = 70 - 100 + 0.99* 100 = 69.08

when we apply BODMAS RULE to the above question, we get 70 - 100 + ( 108/ 109 ) * 100 = 70 - 100 + 0.99* 100 = 69.08

24. Can you find the approximate value for the below equation

108.99 / 116.01 * 106.99 + 111.01 - 102.99

108.99 / 116.01 * 106.99 + 111.01 - 102.99

Explanation:

Given Question is 108.99 / 116.01 * 106.99 + 111.01 - 102.99

when we apply BODMAS RULE and round it off, we get => ( 109 / 116 ) * 107 + 111 - 103 = 1*107+111-103 = 109

when we apply BODMAS RULE and round it off, we get => ( 109 / 116 ) * 107 + 111 - 103 = 1*107+111-103 = 109

25. Find the next number in the the below series

15, 22, 32, 45, _____

15, 22, 32, 45, _____

Explanation:

In the given series, 15, 22, 32, 45 ,

Consecutive numbers increase by 7 ,10 ,13.

Following the same pattern, the next number should increase by 16.

When we add 16 to the last number (i.e 45) we get 16+45=61

Consecutive numbers increase by 7 ,10 ,13.

Following the same pattern, the next number should increase by 16.

When we add 16 to the last number (i.e 45) we get 16+45=61

26. Find the next number in the the below series

18, 46, 75, 105, _____

18, 46, 75, 105, _____

Explanation:

In the given series, 18, 46, 75, 105 ,

Consecutive numbers increase by 28 ,29 ,30.

Following the same pattern, the next number should increase by 31.

When we add 31 to the last number (i.e 105) we get 31+105=136

Consecutive numbers increase by 28 ,29 ,30.

Following the same pattern, the next number should increase by 31.

When we add 31 to the last number (i.e 105) we get 31+105=136

27. Can you find the approximate value for the below equation

63.01 + 65.99 * 68.01 / 71.01 - 77.99

63.01 + 65.99 * 68.01 / 71.01 - 77.99

Explanation:

Given Question is 63.01 + 65.99 * 68.01 / 71.01 - 77.99

when we apply BODMAS RULE and round it off, we get => 63 + 66 * ( 68/ 71 ) - 78 = 63 + 66 * 1- 78 = 48

when we apply BODMAS RULE and round it off, we get => 63 + 66 * ( 68/ 71 ) - 78 = 63 + 66 * 1- 78 = 48

28. Find the area of the circle whose diameter is 10 cm

29. Find the next number in the the below series

20, 31, 45, 62, _____

20, 31, 45, 62, _____

Explanation:

In the given series, 20, 31, 45, 62 ,

Consecutive numbers increase by 11 ,14 ,17.

Following the same pattern, the next number should increase by 20.

When we add 20 to the last number (i.e 62) we get 20+62=82

Consecutive numbers increase by 11 ,14 ,17.

Following the same pattern, the next number should increase by 20.

When we add 20 to the last number (i.e 62) we get 20+62=82

30. Can you find the answer for the below equation

145 / 296 + 295 * 294 - 291

145 / 296 + 295 * 294 - 291

Explanation:

Given Question is 145 / 296 + 295 * 294 - 291

when we apply BODMAS RULE to the above question, we get (Bracket Of Division) ( 145 / 296 ) + 295 * 294 - 291 = 0.48+295*294-291 = 86439.49

when we apply BODMAS RULE to the above question, we get (Bracket Of Division) ( 145 / 296 ) + 295 * 294 - 291 = 0.48+295*294-291 = 86439.49