Would you like to submit the test? |

Sample Aptitude Test 3 for you to Practice. Evaluate your Aptitude Test 3 test answering skills by trying the online Aptitude Sample Test 3 and know your score.

You have scored 3 out of 10

You Scored:2

Total Questions:2

Attended Questions:2

Correct Answered:2

1. Two trains of equal length are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 36 seconds. The length of each train in meters is

Explanation:

Length of both the train be x meter,

Distance covered = 2x

Relative speed = 46 - 36 (same direction)

= 10 kmph

To convert kmph to m /sec

= 10 x (5/18) m/sec

= 25 / 9 m/sec

We know that** Distance = Speed x Time**

=> (2x /36) = 25/9

=>** x=50 m.**

Distance covered = 2x

Relative speed = 46 - 36 (same direction)

= 10 kmph

To convert kmph to m /sec

= 10 x (5/18) m/sec

= 25 / 9 m/sec

We know that

=> (2x /36) = 25/9

=>

2. If the ratio of boys to girls in a class is B and the ratio of girls to boys is G, then 3 (B + G) is ?

Explanation:

Let No.of Boys = x, No. of Girls = y

Given, x/ y = B and y/x = G

3(B+G) = 3 ( y/x + x/y ) = 3 (x^{2}+y^{2}) / xy > 3

Given, x/ y = B and y/x = G

3(B+G) = 3 ( y/x + x/y ) = 3 (x

3. Find the next number in the the below series

19, 26, 36, 49, _____

19, 26, 36, 49, _____

Explanation:

In the given series, 19, 26, 36, 49 ,

Consecutive numbers increase by 7 ,10 ,13.

Following the same pattern, the next number should increase by 16.

When we add 16 to the last number (i.e 49) we get 16+49=65

Consecutive numbers increase by 7 ,10 ,13.

Following the same pattern, the next number should increase by 16.

When we add 16 to the last number (i.e 49) we get 16+49=65

4. Petrol & Kerosene are mixed in the ratio of 3:14. Total Volume of the mixture is 300 litres. Find the composition of Petrol in the overall mixture?

Explanation:

Given Petrol & Kerosene are in the ratio of 3:14

Given volume of mixture = 300 litres

Quantity of Petrol = 3/(3+14) x 300 = 52.94

Given volume of mixture = 300 litres

Quantity of Petrol = 3/(3+14) x 300 = 52.94

5. Can you find the approximate value for the below equation

88.99 / 99.99 * 86.01 - 93.01 + 82.01

88.99 / 99.99 * 86.01 - 93.01 + 82.01

Explanation:

Given Question is 88.99 / 99.99 * 86.01 - 93.01 + 82.01

when we apply BODMAS RULE and round it off, we get => ( 89 / 100 ) * 86 - 93 + 82 = 1*86-93+82 = 66

when we apply BODMAS RULE and round it off, we get => ( 89 / 100 ) * 86 - 93 + 82 = 1*86-93+82 = 66

6. 543 + 676 – 455 – 321 = ?

Explanation:

543 + 676 – 455 – 321 = 1219 - 776

= 443

= 443

7. There were 22 students in a particular Class. The class teacher knows the overall height of all the students in the class is 1200. Can you find the average height of students in the class?

Explanation:

Use the below formula to find the average height of students in the class
Average Height = ( Total Height of all students in the Class / Total Number of Students)
Average Height = ( 1200/22) = 54.55

8. Find the simple interest on Rs. 1300 at 10 % per annum for 5 years

Explanation:

Principal : 1300 . Rate of interest : 10
Number of years : 5 Simple Interest = pnr/100
Simple Interest = (1300 x 5 x 10) / 100 Simple Interest = 650

9. Can you find the answer for the below equation

165 - 290 + 298 / 299 * 290

165 - 290 + 298 / 299 * 290

Explanation:

Given Question is 165 - 290 + 298 / 299 * 290

when we apply BODMAS RULE to the above question, we get 165 - 290 + ( 298/ 299 ) * 290 = 165 - 290 + 0.99* 290 = 164.03

when we apply BODMAS RULE to the above question, we get 165 - 290 + ( 298/ 299 ) * 290 = 165 - 290 + 0.99* 290 = 164.03

10. Find the discount percentage which is equivalent for two successive discount of 10 % on a product worth Rs. 10,800

Explanation:

Given,two successive discount of 10 %.

Let, x = First discount = 10%, y = seconddiscount = 10%

Total Discount % = (x + y - [xy/100])%

= (10 + 10 - [10x10/100])%

= (20 - [100/100])%

= (20 - 1)%

=**19%**

Total Discount % which is equivalent for two successive discount of 10 % = 19%

Let, x = First discount = 10%, y = seconddiscount = 10%

Total Discount % = (x + y - [xy/100])%

= (10 + 10 - [10x10/100])%

= (20 - [100/100])%

= (20 - 1)%

=

Total Discount % which is equivalent for two successive discount of 10 % = 19%

11. Below Numbers follow a particular pattern. Can you find the Missing number in the below pattern?

30, 46.4, 62.8, X , 95.6, 112

30, 46.4, 62.8, X , 95.6, 112

Explanation:

The given series is -- 30, 46.4, 62.8, X , 95.6, 112

Consecutive numbers increases by 16.4

Following this pattern, the Missing Number X should increase by 16.4 from the previous number.

When we add 16.4 to the number before X (i.e 62.8) we get 62.8+16.4=79.2

Consecutive numbers increases by 16.4

Following this pattern, the Missing Number X should increase by 16.4 from the previous number.

When we add 16.4 to the number before X (i.e 62.8) we get 62.8+16.4=79.2

12. A tennis court has a length of 29 units, and breadth of 20 units. Find the area of the tennis court ?

Explanation:

Area of Rectangle = length x breadth 29 x 20= 580

13. A Big Square shaped hall needs to be fitted with carpet. The Diagonals measure 40m. One Sq.m of carpet costs Rs.36. Find the total cost involved?

Explanation:

Diagonal of the big Square shaped hall is given as 40m.

In order to find how many Sq.m of carpet is required to fill the hall, we need to find the area of the square shaped hall .

Area of the Square shaped hall = (Diagonal^2) / 2

= (40^2)/2 =800 sq.m

Price = Area x Cost Per Sq.m = 800 x 36 = 28800

In order to find how many Sq.m of carpet is required to fill the hall, we need to find the area of the square shaped hall .

Area of the Square shaped hall = (Diagonal^2) / 2

= (40^2)/2 =800 sq.m

Price = Area x Cost Per Sq.m = 800 x 36 = 28800

14. Compute : 1% of 1348 + 62 % of 4288.

Explanation:

1 % of 1348 = 13.48
62 % of 4288 = 2658.56
Adding these two values we get = 2672.04

15. What will be the least number which when doubled will be exactly divisible by 12, 18, 21 and 30 ?

Explanation:

L.C.M. of 12, 18, 21 30 2 | 12 - 18 - 21 - 30
----------------------------
= 2 x 3 x 2 x 3 x 7 x 5 = 1260. 3 | 6 - 9 - 21 - 15
----------------------------
Required number = (1260 ÷ 2) | 2 - 3 - 7 - 5

= 630.

= 630.

16. What is the two-digit number whose first digit is "a" and the second digit is "b"?. The number is greater than 9.

I. The number is multiple of 53.

II. The sum of the digits 'a" and "b" is 8.

I. The number is multiple of 53.

II. The sum of the digits 'a" and "b" is 8.

Explanation:

__From statement I:__

A two digit number, greater than 9 and multiple of 53 should be 53 itself.

Because, 2 x 53 = 106 (3 digit number).

Therefore, I alone sufficient to answer.

__From statement II:__

A two digit number, greater than 9 and sum of the digit is 8.

It can be 17, 26, 35, 44, 53, 62, 71, 80.

So we cannot determine the required answer from the statement II alone.

**Thus, I alone give the answer while II alone not sufficient to answer.**

17. Output of a particular program follows the below pattern. Can you find the next number ?

181, 159, 137, 115, _____

181, 159, 137, 115, _____

Explanation:

The given series is -- 181, 159, 137, 115

Consecutive numbers decreases by 22

Following this pattern, the Missing Number should decrease by 22 from the previous number.

When we subtract 22 to the last number (i.e 115) we get 115--22=93

Consecutive numbers decreases by 22

Following this pattern, the Missing Number should decrease by 22 from the previous number.

When we subtract 22 to the last number (i.e 115) we get 115--22=93

18. A tennis court has a length of 29 units, and breadth of 20 units. Find the area of the tennis court?

Explanation:

Area of Rectangle = length x breadth

29 x 20= 580

29 x 20= 580

19. Can you find the answer for the below equation

150 + 156 / 142 - 144 * 149

150 + 156 / 142 - 144 * 149

Explanation:

Given Question is 150 + 156 / 142 - 144 * 149

when we apply BODMAS RULE to the above question, we get (Bracket Of Division) 150 + ( 156 / 142 ) - 144 * 149 = 150 + 1.09- 144 * 149 = -21304.9

when we apply BODMAS RULE to the above question, we get (Bracket Of Division) 150 + ( 156 / 142 ) - 144 * 149 = 150 + 1.09- 144 * 149 = -21304.9

20. The value of cos^2x - sin^2x = 0, then tan x = ?

21. What would be the amount to be paid on the principal of 6500 Rs. at the end of 2 years at compound interest at the rate of 15 % per annum?

Explanation:

Given principal = Rs. 6500

No. of years = 2

Rate of interest = 15

**Amount = P x (1+r/100)**^{n},

= 6500 x (1+15/100)^{2}

= 6500 x (115/100)^{2}

= 8596.25

**Ans : 8596.25**

No. of years = 2

Rate of interest = 15

= 6500 x (1+15/100)

= 6500 x (115/100)

= 8596.25

22. Given rectangle of length 31 units, and breadth of 8 units. Compute its area ?

Explanation:

Area of Rectangle = length x breadth

31 x 8= 248

31 x 8= 248

23. In the given series, can you find the Missing number ?

25, 40.2, 55.4, X , 85.8, 101

25, 40.2, 55.4, X , 85.8, 101

Explanation:

The given series is -- 25, 40.2, 55.4, X , 85.8, 101

Consecutive numbers increases by 15.2

Following this pattern, the Missing Number X should increase by 15.2 from the previous number.

When we add 15.2 to the number before X (i.e 55.4) we get 55.4+15.2=70.6

Consecutive numbers increases by 15.2

Following this pattern, the Missing Number X should increase by 15.2 from the previous number.

When we add 15.2 to the number before X (i.e 55.4) we get 55.4+15.2=70.6

24. If Suresh sells an article at a price of ?9300, he incurs a loss of ?3100. At what price should he sell the article so that he gets a profit of 25%?

Explanation:

CP of the article = ?(93003100)
=?6200
SP = (6200*125)/100 = ?7750

25. Can you find the approximate value for the below equation

97.01 - 108.99 * 89.01 + 92.99 / 81.99

97.01 - 108.99 * 89.01 + 92.99 / 81.99

Explanation:

Given Question is 97.01 - 108.99 * 89.01 + 92.99 / 81.99

when we apply BODMAS RULE and round it off, we get => 97 - 109 * 89+ ( 93/ 82 ) = 97 - 109 * 89+ 1 = -9603

when we apply BODMAS RULE and round it off, we get => 97 - 109 * 89+ ( 93/ 82 ) = 97 - 109 * 89+ 1 = -9603

26. The smallest prime number is:

Explanation:

The smallest prime number is 2.

27. Can you find the approximate value for the below equation

56.99 * 53.99 - 45.99 / 52.01 + 47.01

56.99 * 53.99 - 45.99 / 52.01 + 47.01

Explanation:

Given Question is 56.99 * 53.99 - 45.99 / 52.01 + 47.01

when we apply BODMAS RULE and round it off, we get => 57 * 54 - ( 46/ 52 ) + 47 = 57 * 54 - 1+ 47 = 3123

when we apply BODMAS RULE and round it off, we get => 57 * 54 - ( 46/ 52 ) + 47 = 57 * 54 - 1+ 47 = 3123

28. Find the next number in the the below series

15, 29, 46, 66, _____

15, 29, 46, 66, _____

Explanation:

In the given series, 15, 29, 46, 66 ,

Consecutive numbers increase by 14 ,17 ,20.

Following the same pattern, the next number should increase by 23.

When we add 23 to the last number (i.e 66) we get 23+66=89

Consecutive numbers increase by 14 ,17 ,20.

Following the same pattern, the next number should increase by 23.

When we add 23 to the last number (i.e 66) we get 23+66=89

29. Evaluate the Expression:

15.99% of 900 - 2.01% of 780

15.99% of 900 - 2.01% of 780

Explanation:

16% of 900 = 144

2% of 780= 15.6

Subtracting the above 2 results, we get 144-15.6 = 128.4 = (approx) 128

2% of 780= 15.6

Subtracting the above 2 results, we get 144-15.6 = 128.4 = (approx) 128

30. Find the approximate value for the expression

54.998 * 2.003 + 42.001 / 16.003 - 17.998

54.998 * 2.003 + 42.001 / 16.003 - 17.998

Explanation:

Given Question is 54.998 * 2.003 + 42.001 / 16.003 - 17.998 when we apply BODMAS RULE to the above question,

Step - 1 : (Bracket Of Division) ( 55 * 2 ) + ( 42 / 16 ) - 18 = 110 + 2.625 - 18 Step - 2 : 110 + 2.625 - 18 = 94.63 = (approx) 95

Step - 1 : (Bracket Of Division) ( 55 * 2 ) + ( 42 / 16 ) - 18 = 110 + 2.625 - 18 Step - 2 : 110 + 2.625 - 18 = 94.63 = (approx) 95