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Sample Aptitude Test 2 for you to Practice. Evaluate your Aptitude Test 2 test answering skills by trying the online Aptitude Sample Test 2 and know your score.

You have scored 3 out of 10

You Scored:2

Total Questions:2

Attended Questions:2

Correct Answered:2

1. Can you find the approximate value for the below equation

83.01 * 79.01 - 74.99 + 79.99 / 76.01

83.01 * 79.01 - 74.99 + 79.99 / 76.01

Explanation:

Given Question is 83.01 * 79.01 - 74.99 + 79.99 / 76.01

when we apply BODMAS RULE and round it off, we get => 83 * 79 - 75+ ( 80/ 76 ) = 83 * 79 - 75+ 1 = 6485

when we apply BODMAS RULE and round it off, we get => 83 * 79 - 75+ ( 80/ 76 ) = 83 * 79 - 75+ 1 = 6485

2. Find the discount percentage which is equivalent for two successive discount of 10 % on a product worth Rs. 10,800

Explanation:

Given,two successive discount of 10 %.

Let, x = First discount = 10%, y = seconddiscount = 10%

Total Discount % = (x + y - [xy/100])%

= (10 + 10 - [10x10/100])%

= (20 - [100/100])%

= (20 - 1)%

=**19%**

Total Discount % which is equivalent for two successive discount of 10 % = 19%

Let, x = First discount = 10%, y = seconddiscount = 10%

Total Discount % = (x + y - [xy/100])%

= (10 + 10 - [10x10/100])%

= (20 - [100/100])%

= (20 - 1)%

=

Total Discount % which is equivalent for two successive discount of 10 % = 19%

3. Can you find the answer for the below equation

32 + 38 * 34 - 36 / 40

32 + 38 * 34 - 36 / 40

Explanation:

Given Question is 32 + 38 * 34 - 36 / 40

when we apply BODMAS RULE to the above question, we get (Bracket Of Division) 32 + 38 * 34- ( 36/ 40 ) = 32 + 38 * 34- 0.9 = 1323.1

when we apply BODMAS RULE to the above question, we get (Bracket Of Division) 32 + 38 * 34- ( 36/ 40 ) = 32 + 38 * 34- 0.9 = 1323.1

4. Petrol & Kerosene are mixed in the ratio of 7:14. Total Volume of the mixture is 500 litres. Find the composition of Petrol in the overall mixture?

Explanation:

Given Petrol & Kerosene are in the ratio of 7:14
Given volume of mixture = 500 litres
Quantity of Petrol = 7/(7+14) x 500
= 166.67

5. Expression sin (180+x) = ?

6. Can you find the answer for the below equation

159 - 584 * 586 / 591 + 578

159 - 584 * 586 / 591 + 578

Explanation:

Given Question is 159 - 584 * 586 / 591 + 578

when we apply BODMAS RULE to the above question, we get 159 - 584 * ( 586/ 591 ) + 578 = 159 - 584 * 0.99+ 578 = 157.94

when we apply BODMAS RULE to the above question, we get 159 - 584 * ( 586/ 591 ) + 578 = 159 - 584 * 0.99+ 578 = 157.94

7. Can you find the missing number in the below series:

30, 45, 75, 105, 165 ?

30, 45, 75, 105, 165 ?

Explanation:

Given series is:

30, 45, 75, 105, 165 ?

=> 15 * 2 = 30

=> 15 * 3 = 45

=> 15 * 5 = 75

=> 15 * 7 = 105

=> 15 * 11 = 165

=> 15 * 13 =**195**

Thus each number in the given series is obtained by**"multiplying each prime number by 15"**.

30, 45, 75, 105, 165 ?

=> 15 * 2 = 30

=> 15 * 3 = 45

=> 15 * 5 = 75

=> 15 * 7 = 105

=> 15 * 11 = 165

=> 15 * 13 =

Thus each number in the given series is obtained by

8. The difference b/w two parallel sides of a trapezium is 8 cm and the perpendicular distance b/w them is 38 cm. Find the lengths of the parallel sides, if the area of the trapezium is 950 cm 2 .

9. A man purchased a cow for Rs. 1500 and sold it the same day for Rs. 2700, allowing the buyer a credit of 4 years. If the rate of interest be 5% per annum, then the man has a gain of (?) Rupees:

Explanation:

Cost Price = 1500

Selling Price = Rs. (2700 x 100) / (100 + 10 x 4)

= 2250

**Gain = S.P - C.P **

=> Gain =2250 -1500

=>** Gain =750 Rs**

Selling Price = Rs. (2700 x 100) / (100 + 10 x 4)

= 2250

=> Gain =2250 -1500

=>

10. What annual payment will discharge a debt of Rs.1025 due in 2 years at the rate of 5% compound interest ?

11. Can you find the approximate value for the below equation

54.01 + 56.99 * 59.01 / 62.01 - 68.99

54.01 + 56.99 * 59.01 / 62.01 - 68.99

Explanation:

Given Question is 54.01 + 56.99 * 59.01 / 62.01 - 68.99

when we apply BODMAS RULE and round it off, we get => 54 + 57 * ( 59/ 62 ) - 69 = 54 + 57 * 1- 69 = 39

when we apply BODMAS RULE and round it off, we get => 54 + 57 * ( 59/ 62 ) - 69 = 54 + 57 * 1- 69 = 39

12. An accurate clock shows 9 'o' clock in the morning. Through how many degrees will the hour hand rotate when the clock shows 3 'o' clock in the afternoon?

Explanation:

Angle traced by the hour hand in 6 hours = (360/12) x 6 = 180 Degree

13. Find the curved surface area of the cone if the radius and height are 43 units and 16 units respectively.

Explanation:

Given, radius = 43 units

Height = 16 units

**Curved surface area of the cone = pi * r * L**

**where, L = sqrt(r^2 + h^2)**

=> L = sqrt(43^2 + 16^2)

=> L = sqrt(1849+ 256)

=> L = sqrt(2105)

=>**L = 45.88**

Subs L = 45.88 in the formula: Curved surface area of the cone = pi * r * L

**=> ****Curved surface area of the cone = **(22/7) * 43 * 45.88

**=> ****Curved surface area of the cone = 6200.39**

Height = 16 units

=> L = sqrt(43^2 + 16^2)

=> L = sqrt(1849+ 256)

=> L = sqrt(2105)

=>

Subs L = 45.88 in the formula: Curved surface area of the cone = pi * r * L

14. Can you find the approximate value for the below equation

105.01 - 93.99 + 98.01 * 97.99 / 90.01

105.01 - 93.99 + 98.01 * 97.99 / 90.01

Explanation:

Given Question is 105.01 - 93.99 + 98.01 * 97.99 / 90.01

when we apply BODMAS RULE and round it off, we get => 105 - 94 + 98* ( 98/ 90 ) = 105 - 94 + 98* 1 = 118

when we apply BODMAS RULE and round it off, we get => 105 - 94 + 98* ( 98/ 90 ) = 105 - 94 + 98* 1 = 118

15. In the below given sequence, what should be the Missing number ?

133, 108, 83, X , 33, 8

133, 108, 83, X , 33, 8

Explanation:

The given series is -- 133, 108, 83, X , 33, 8

Consecutive numbers decreases by 25

Following this pattern, the Missing Number X should decrease by 25 from the previous number.

When we subtract 25 to the number before X (i.e 83) we get 83--25=58

Consecutive numbers decreases by 25

Following this pattern, the Missing Number X should decrease by 25 from the previous number.

When we subtract 25 to the number before X (i.e 83) we get 83--25=58

16. Find the approximate value for the expression

11.002 + 15.003 - 25.998 * 4.999 / 2.001

11.002 + 15.003 - 25.998 * 4.999 / 2.001

Explanation:

Given Question is 11.002 + 15.003 - 25.998 * 4.999 / 2.001

when we apply BODMAS RULE to the above question,

Step - 1 : (Bracket Of Division) 11 + 15 - 26 * ( 5 / 2 ) = 11 + 15 - 26 * 2.5

Step - 2 : 11 + 15 - ( 26 * 2.5 ) = 26 - 65 = -39

when we apply BODMAS RULE to the above question,

Step - 1 : (Bracket Of Division) 11 + 15 - 26 * ( 5 / 2 ) = 11 + 15 - 26 * 2.5

Step - 2 : 11 + 15 - ( 26 * 2.5 ) = 26 - 65 = -39

17. Can you find the answer for the below equation

22 + 28 / 14 - 16 * 21

22 + 28 / 14 - 16 * 21

Explanation:

Given Question is 22 + 28 / 14 - 16 * 21

when we apply BODMAS RULE to the above question, we get (Bracket Of Division) 22 + ( 28 / 14 ) - 16 * 21 = 22 + 2- 16 * 21 = -312

when we apply BODMAS RULE to the above question, we get (Bracket Of Division) 22 + ( 28 / 14 ) - 16 * 21 = 22 + 2- 16 * 21 = -312

18. A man is 24 years older than his son. In two years, his age will be twice the age of his son. The present age of his son is:

Explanation:

Let the son's present age be x years.

Then, man's present age = (x + 24) years.

Therefore, (x + 24) + 2

= 2(x + 2) x + 26

= 2x + 4 x = 22.

Thus**22 years**is present age of son.

Then, man's present age = (x + 24) years.

Therefore, (x + 24) + 2

= 2(x + 2) x + 26

= 2x + 4 x = 22.

Thus

19. Can you find the approximate value for the below equation

30.99 * 31.01 + 32.99 - 33.01 / 34.99

30.99 * 31.01 + 32.99 - 33.01 / 34.99

Explanation:

Given Question is 30.99 * 31.01 + 32.99 - 33.01 / 34.99

when we apply BODMAS RULE and round it off, we get => 31 * 31 + 33- ( 33/ 35 ) = 31 * 31 + 33- 1 = 993

when we apply BODMAS RULE and round it off, we get => 31 * 31 + 33- ( 33/ 35 ) = 31 * 31 + 33- 1 = 993

20. Compute : 14% of 4120 + 27 % of 2366.

Explanation:

14 % of 4120 = 576.8
27 % of 2366 = 638.82
Adding these two values we get = 1215.62

21. A rectangular plot has a length of 26 units, and breadth of 14 units. Find the area of the plot ?

Explanation:

Area of Rectangle = length x breadth

26 x 14= 364

26 x 14= 364

22. Can you find the answer for the below equation

97 / 382 - 375 * 378 + 371

97 / 382 - 375 * 378 + 371

Explanation:

Given Question is 97 / 382 - 375 * 378 + 371

when we apply BODMAS RULE to the above question, we get (Bracket Of Division) ( 97 / 382 ) - 375 * 378 + 371 = 0.25-375*378+371 = -141378.75

when we apply BODMAS RULE to the above question, we get (Bracket Of Division) ( 97 / 382 ) - 375 * 378 + 371 = 0.25-375*378+371 = -141378.75

23. What is the two-digit number whose first digit is "a" and the second digit is "b"?. The number is greater than 9.

I. The number is multiple of 71.

II. The sum of the digits "a" and "b" is 8.

I. The number is multiple of 71.

II. The sum of the digits "a" and "b" is 8.

Explanation:

__From statement I:__

A two digit number, greater than 9 and multiple of 71 should be 71 itself.

Because, 2 x 71 = 142 (3 digit number).

Therefore, I alone sufficient to answer.

__From statement II:__

A two digit number, greater than 9 and sum of the digit is 8.

It can be 17, 26, 35, 44, 53, 62, 71, 80.

So we cannot determine the required answer from the statement II alone.

**Thus, I alone give the answer while II alone not sufficient to answer.**

24. What would be the amount to be paid on the principal of 5000 Rs. at the end of 2 years at compound interest at the rate of 9 % per annum?

Explanation:

Given principal = 5000

No. of years = 2

Rate of interest = 9

**Amount = P x (1+r/100)^n, **

we get Amount = 5000 x (1+9/100)^2

= 5000 * (109/100)^2

= 5940.5

Ans :**5940.5**

No. of years = 2

Rate of interest = 9

we get Amount = 5000 x (1+9/100)^2

= 5000 * (109/100)^2

= 5940.5

Ans :

25. A toy is in the form of a cylinder, find the lateral surface area if the radius and height of toy is given to be 7 and 10 cm respectively.

Explanation:

Total Surface area = 2 pi r h

= 2 x (22/7) x 7 x (10) = 44 x 10 = 440

= 2 x (22/7) x 7 x (10) = 44 x 10 = 440

26. The least number, which when divided by 12, 15, 20 and 54 leaves in each case a remainder of 8 is:

Explanation:

Required number = (L.C.M. of 12, 15, 20, 54) + 8
= 540 + 8
= 548.

27. A train covers a distance of 12 km in 10 minutes .If it takes 6 seconds to pass a telegraph post,then the length of the train is:

28. Evaluate the expression: 2 + 5 * 6 - 7 * 8 / 4 + 6

Explanation:

Given Question is 2 + 5 * 6 - 7 * 8 / 4 + 6

when we apply BODMAS RULE to the above question, we get

2 + 5 * 6 - 7 ***(8 / 4)** + 6

= 2 +**(5 * 6)** – **(7 * 2)** + 6

= 2 + 30 – 14 + 6

= 38 – 14

=**24**

when we apply BODMAS RULE to the above question, we get

2 + 5 * 6 - 7 *

= 2 +

= 2 + 30 – 14 + 6

= 38 – 14

=

29. Find the next number in the the below series

5, 23, 48, 80, _____

5, 23, 48, 80, _____

Explanation:

In the given series, 5, 23, 48, 80 ,

Consecutive numbers increase by 18 ,25 ,32.

Following the same pattern, the next number should increase by 39.

When we add 39 to the last number (i.e 80) we get 39+80=119

Consecutive numbers increase by 18 ,25 ,32.

Following the same pattern, the next number should increase by 39.

When we add 39 to the last number (i.e 80) we get 39+80=119

30. Find the next number in the the below series

11, 39, 69, 101, _____

11, 39, 69, 101, _____

Explanation:

In the given series, 11, 39, 69, 101 ,

Consecutive numbers increase by 28 ,30 ,32.

Following the same pattern, the next number should increase by 34.

When we add 34 to the last number (i.e 101) we get 34+101=135

Consecutive numbers increase by 28 ,30 ,32.

Following the same pattern, the next number should increase by 34.

When we add 34 to the last number (i.e 101) we get 34+101=135

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