# Volume and Surface Area Questions and Answers updated daily – Aptitude

12 Volume and Surface Area Questions and answers section with explanation for various online exam preparation, various interviews, Aptitude Volume and Surface Area online test. Volume and Surface Area Questions with detailed description, explanation will help you to master the topic.

## Volume and Surface Area Questions

1. 12 spheres of the same size are made from melting a solid cylinder of 16 cm diameter and 2 cm height. Find the diameter of each sphere.

Correct Ans:4 cm
Explanation:

2. The surface area of a sphere is same as the curved surface area of a right circular cylinder whose height and diameter are 12 cm each. The radius of the sphere is:

Correct Ans:6 cm
Explanation:

3. The radii of two cones are in ratio 2:1, their volumes are equal. Find the ratio of their heights.

Correct Ans:1:4
Explanation:

4. The slant height of a conical mountain is 2.5 km and the area of its base is 1.54 km square. The height of mountain is :

Correct Ans:2.4 km
Explanation:

5. 66 cubic centimetres of silver is drawn into a wire 1 mm in diameter. The length if the wire in meters will be:

Correct Ans:84 m
Explanation:

6. How many cubes of 10 cm edge can be put in a cubical box of 1 m edge.

Correct Ans:1000 cubes
Explanation:

7. The cost of the paint is Rs. 36.50 per kg. If 1 kg of paint covers 16 square feet, how much will it cost to paint outside of a cube having 8 feet each side.

Correct Ans:876
Explanation:
We will first calculate the Surface area of cube, then we will calculate the quantity of paint required to get answer.
Here we go,

Surface area =6a2=6∗82=384sq feetQuantity required =38416=24kgCost of painting =36.50∗24=Rs.876

8. A swimming pool 9 m wide and 12 m long is 1 m deep on the shallow side and 4 m deep on the deeper side. Its volume is:

Correct Ans:270
Explanation:
Volume will be length * breadth * height, but in this case two heights are given so we will take average,

Volume=(12∗9∗(1+42))m312∗9∗2.5m3=270m3

9. How many bricks, each measuring 25cm*11.25cm*6cm, will be needed to build a wall 8m*6m*22.5m

Correct Ans:6400
Explanation:
To solve this type of question, simply divide the volume of wall with the volume of brick to get the numbers of required bricks
So lets solve this

Number of bricks =
Volume of wallVolume of 1 brick=800∗600∗22.525∗11.25∗6=6400

10. A boat having a length 3 m and breadth 2 m is floating on a lake. The boat sinks by 1 cm when a man gets into it. The mass of the man is :

Correct Ans:60 kg
Explanation:
In this type of question, first we will calculate the volume of water displaces then will multiply with the density of water.
Volume of water displaced = 3*2*0.01 = 0.06 m cube

Mass of Man = Volume of water displaced * Density of water

= 0.06 * 1000 = 60 kg

11. A cistern 6 m long and 4 m wide contains water up to a breadth of 1 m 25 cm. Find the total area of the wet surface.

Correct Ans:49 m sqaure
Explanation:
Area of the wet surface =
2[lb+bh+hl] - lb = 2 [bh+hl] + lb
= 2[(4*1.25+6*1.25)]+6*4 = 49 m square

12. Find the surface area of a 10cm*4cm*3cm brick.

Correct Ans:164 cm square
Explanation:
Surface area of a cuboid = 2(lb+bh+hl) cm square
So,
Surface area of a brick = 2(10*4+4*3+3*10) cm square
= 2(82) cm square = 164 cm square

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