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CSIR UGC NET 2019 Check for Exam Pattern and Syllabus

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Updated: Oct 04,2019 14:06 IST
CSIR UGC NET 2019 Check for Exam Pattern and Syllabus
CSIR UGC NET 2019 Check for Exam Pattern and Syllabus

CSIR UGC NET December 2019 Exam will be conducted by the National Testing Agency (NTA) which is self-sustaining, autonomous organization to conduct Test on behalf of UGC has planned to organize the CSIR UGC NET 2019 test on 15th of December 2019 for determining the eligibility of Indian Nationals for the award of Junior Research Fellowships (JRF) and for determining eligibility for Lectureship (LS)/ Assistant Professorship.

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CSIR UGC NET 2019

Council of Scientific and Industrial Research headquartered in New Delhi is one of the largest research and development organization in India. And it is one of the world’s largest publicly funded R&D organizations. It is a pioneer in contribution to Science and Technology is notable and Human Resource Development Group (HRDG) which gets the big brains for this organization through various grants, fellowship schemes, etc. 
CSIR UGC NET Exam is conducted for both Junior Research Fellowship (JRF) and Lectureship (LS). National Eligibility Test (NET) is a test conducted by National Testing Agency (NTA) to determine eligibility for JRF and LS. In Early of January 2019, Council of Scientific and Industrial Research (CSIR) has released the official notification for the UGC NET 2019 examination scheduled to be conducted on December month of 2019, on the official website - csirhrdg.res.in. As per the official CSIR UGC NET December 2019 notification, the examination is likely to be conducted on 15th December, 2019, in offline mode for selecting eligible candidates for the honor of JRF and LS in the areas of Chemical Sciences, Earth, Atmospheric, Ocean and Planetary Sciences, Life Sciences, Mathematical Sciences, Physical Sciences. Candidates can download the CSIR UGC NET Syllabus 2019 from the official site or by following steps or by direct link given below. The posts JRF and LS/ Assistant Professorship is for certain subject areas falling under the faculty of Science & Technology like Chemical Sciences, Earth, Atmospheric, Ocean and Planetary Sciences, Life Sciences, Mathematical Sciences, and Physical Sciences. The exam will be conducted in online mode at selected Examination Centers spread across the country.


Any Important Details & Dates for CSIR UGC NET 2019?

Based on the Notification of CSIR we have provisioned the important events and their scheduled dates and details in this section.

Event

Date

Name of the Organization

Council of Scientific and Industrial Research Human Resource Development Group (CSIR HRDG)

Post Name

Junior Research Fellowships (JRF)  
Lectureship (LS)/ Assistant Professorship

Category

Syllabus

Exam Date

15th December 2019

Selection Process

1.Written Test

2.Personal Interview

Job Location

Across India

Official Site

www.csirhrdg.res.in


What is the CSIR UGC NET Syllabus? 

On Completion of Registration the aspirants must start preparing for the exam and on that aspect below syllabus is released in the CSIR Official Site

CSIR UGC NET December 2019 Exam Pattern

CHEMICAL SCIENCES

PART A

PART B

PART C

Total

Total questions

20

40

60

120

Max No of Questions to attempt

15

35

25

75

Marks for each correct answer

2

2

4

200

Marks for each incorrect answer

(Negative marking)

0.5

0.5

1

-

The candidate is required to answer a maximum of 15, 35 and 25 questions from Part-A, Part-B, and Part-C respectively. If more than the required number of questions are answered, only the first 15, 35 and 25 questions in Part A, Part B, and Part C respectively will be taken up for evaluation.

CSIR UGC NET December 2019 Exam Pattern

EARTH, ATMOSPHERIC, OCEAN AND

PLANETARY SCIENCES

PART A

PART B

PART C

Total

Total questions

20

50

80

150

Max No of Questions to attempt

15

35

25

75

Marks for each correct answer

2

2

4

200

Marks for each incorrect answer

(Negative marking)

0.5

0.5

1.32

-

The candidate is required to answer a maximum of 15, 35 and 25 questions from Part-A, Part-B, and Part-C respectively. If more than the required number of questions are answered, only the first 15, 35 and 25 questions in Part A, Part B, and Part C respectively will be taken up for evaluation.

CSIR UGC NET December 2019 Exam Pattern

LIFE SCIENCES

PART A

PART B

PART C

Total

Total questions

20

50

75

145

Max No of Questions to attempt

15

35

25

75

Marks for each correct answer

2

2

4

200

Marks for each incorrect answer

(Negative marking)

0.5

0.5

1

-

The candidate is required to answer a maximum of 15, 35 and 25 questions from Part-A, Part-B, and Part-C respectively. If more than required number of questions are answered, only the first 15, 35 and 25 questions in Part A, Part B, and Part C respectively will be taken up for evaluation.

CSIR UGC NET December 2019 Exam Pattern

MATHEMATICAL SCIENCE

PART A

PART B

PART C

Total

Total questions

20

40

60

120

Max No of Questions to attempt

15

25

20

60

Marks for each correct answer

2

2

4

200

Marks for each incorrect answer

(Negative marking)

0.5

0.75

 

-

The candidate is required to answer a maximum of 15, 25 and 20 questions from Part-A, Part-B, and Part-C respectively. If more than required number of questions are answered, only the first 15, 25 and 20 questions in Part A, Part B, and Part C respectively will be taken up for evaluation.

CSIR UGC NET December 2019 Exam Pattern

PHYSICAL SCIENCES

PART A

PART B

PART C

Total

Total questions

20

25

30

75

Max No of Questions to attempt

15

20

20

35

Marks for each correct answer

2

3.5

5

200

Marks for each incorrect answer

(Negative marking)

0.5

0.875

1.25

-

The candidate is required to answer a maximum of 15, 20 and 20 questions from Part-A, Part-B, and Part-C respectively. If more than required number of questions are answered, only the first 15, 20 and 20 questions in Part A, Part B, and Part C respectively will be taken up for evaluation.



Important Links 

Official Site - Link
Official Exam Notice - Link



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